有没有办法访问同一类模板的不同实例的私有部分?

发布于 2024-07-29 02:35:42 字数 1017 浏览 11 评论 0原文

在我继续使用模板的过程中,我不仅在它所保存的 ItemType 上对 Container 类进行了模板化,而且还在 Functor 参数上进行了模板化,该参数确定了它应该如何对项目进行排序。 到目前为止,一切都很好。

当我想将一个容器的内容复制到另一个容器时,我遇到了一个小问题:如果两个容器具有不同的函子类型,那么它们在技术上是不相关的类。 因此,容器 A 不允许访问容器 B 的非公开内容。除了将我需要访问的所有内容公开之外,还有什么好方法来处理这个问题吗? 也许有某种方式可以模板化“朋友”声明?

演示该问题的示例代码如下:

#include <stdio.h>

class FunctorA {};
class FunctorB {};

template <class ItemType, class Functor> class MyContainer
{
public:
   MyContainer() : _metaData(0) {/* empty */}

   template<class RHSFunctor> void CopyFrom(const MyContainer<ItemType, RHSFunctor> & copyFrom)
   {
      _metaData = copyFrom._metaData;
      _item     = copyFrom._item;
   }

private:
  int _metaData;
  ItemType _item;
};

int main(int argc, char ** argv)
{
   MyContainer<void *, FunctorA> containerA;
   MyContainer<void *, FunctorB> containerB;

   containerA.CopyFrom(containerB);  // error, containerA::CopyFrom() can't access containerB's private data!
   return 0;
}

In my continuing adventure with templates, I've templated my Container class not just on the ItemType it holds, but also on a Functor argument that determines how it should order the items. So far, so good.

A little problem I've run into occurs when I want to copy the contents of one Container to another: If the two Containers have different Functor types, then they technically are unrelated classes. Therefore, Container A isn't allowed to access the non-public contents of Container B. Is there any good way to deal with this problem, other than making everything I need to access public? Some way to template a "friend" declaration, perhaps?

Example code to demonstrate the problem follows:

#include <stdio.h>

class FunctorA {};
class FunctorB {};

template <class ItemType, class Functor> class MyContainer
{
public:
   MyContainer() : _metaData(0) {/* empty */}

   template<class RHSFunctor> void CopyFrom(const MyContainer<ItemType, RHSFunctor> & copyFrom)
   {
      _metaData = copyFrom._metaData;
      _item     = copyFrom._item;
   }

private:
  int _metaData;
  ItemType _item;
};

int main(int argc, char ** argv)
{
   MyContainer<void *, FunctorA> containerA;
   MyContainer<void *, FunctorB> containerB;

   containerA.CopyFrom(containerB);  // error, containerA::CopyFrom() can't access containerB's private data!
   return 0;
}

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评论(2

挽手叙旧 2024-08-05 02:35:42

您可以创建一个仅在 ItemType 上模板化的基模板类,将数据保留在那里,拥有该基类的成熟的 2-args 模板子类,并将复制来源放在基类中,因为它无论如何都不依赖于函子。 IE:

template <class ItemType> class MyContainerBase
{
public:
   MyContainerBase() : _metaData(0) {/* empty */}

   void CopyFrom(const MyContainerBase<ItemType> & copyFrom)
   {
      _metaData = copyFrom._metaData;
      _item     = copyFrom._item;
   }

protected:
  int _metaData;
  ItemType _item;
};

template <class ItemType, class Functor> class MyContainer:
    public MyContainerBase<ItemType>
{
  // whatever you need here -- I made the data above protected
  // just on the assumption you may need to access it here;-)
};

You can make a base template class templated just on ItemType, keep the data there, have the full-fledged 2-args template subclass that base, AND put the copy-from in the base class as it doesn't depend on the functor anyway. I.e.:

template <class ItemType> class MyContainerBase
{
public:
   MyContainerBase() : _metaData(0) {/* empty */}

   void CopyFrom(const MyContainerBase<ItemType> & copyFrom)
   {
      _metaData = copyFrom._metaData;
      _item     = copyFrom._item;
   }

protected:
  int _metaData;
  ItemType _item;
};

template <class ItemType, class Functor> class MyContainer:
    public MyContainerBase<ItemType>
{
  // whatever you need here -- I made the data above protected
  // just on the assumption you may need to access it here;-)
};
迷爱 2024-08-05 02:35:42

正如您所指出的,您还可以使用友元函数:

class FunctorA {};
class FunctorB {};

template <class ItemType, class Functor> class MyContainer
{
public:
  MyContainer() : _metaData(0) {/* empty */}

  template<class CmnItemType, class LHSFunctor, class RHSFunctor>
  friend void Copy(const MyContainer<CmnItemType, LHSFunctor> & copyFrom
    , MyContainer<CmnItemType, RHSFunctor> & copyTo);

private:
  int _metaData;
  ItemType _item;
};

template<class CmnItemType, class LHSFunctor, class RHSFunctor>
void Copy(const MyContainer<CmnItemType, LHSFunctor> & copyFrom
  , MyContainer<CmnItemType, RHSFunctor> & copyTo)
{
  copyTo._metaData = copyFrom._metaData;
  copyTo._item     = copyFrom._item;
}


int main(int argc, char ** argv)
{
  MyContainer<void *, FunctorA> containerA;
  MyContainer<void *, FunctorB> containerB;

  Copy(containerB, containerA);
  return 0;
}

As you point out, you can also use a friend function:

class FunctorA {};
class FunctorB {};

template <class ItemType, class Functor> class MyContainer
{
public:
  MyContainer() : _metaData(0) {/* empty */}

  template<class CmnItemType, class LHSFunctor, class RHSFunctor>
  friend void Copy(const MyContainer<CmnItemType, LHSFunctor> & copyFrom
    , MyContainer<CmnItemType, RHSFunctor> & copyTo);

private:
  int _metaData;
  ItemType _item;
};

template<class CmnItemType, class LHSFunctor, class RHSFunctor>
void Copy(const MyContainer<CmnItemType, LHSFunctor> & copyFrom
  , MyContainer<CmnItemType, RHSFunctor> & copyTo)
{
  copyTo._metaData = copyFrom._metaData;
  copyTo._item     = copyFrom._item;
}


int main(int argc, char ** argv)
{
  MyContainer<void *, FunctorA> containerA;
  MyContainer<void *, FunctorB> containerB;

  Copy(containerB, containerA);
  return 0;
}
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