从路径列表填充树视图

Question

我正在尝试从文件夹路径列表填充树视图，例如：

C:\WINDOWS\addins
C:\WINDOWS\AppPatch
C:\WINDOWS\AppPatch\MUI
C:\WINDOWS\AppPatch\MUI\040C
C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727
C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI
C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI\0409

使用如下输出：

├───addins
├───AppPatch
│   └───MUI
│       └───040C
├───Microsoft.NET
│   └───Framework
│       └───v2.0.50727
│           └───MUI
│               └───0409

注意，没有 'C:\WINDOWS\Microsoft.NET' 或 'C:\WINDOWS\Microsoft.NET\Framework'在列表中。 我已经为此工作了近两天，我的代码中有很多错误。 希望我能从这里得到帮助。

谢谢。

埃里克

Answer 1

private void Form1_Load(object sender, EventArgs e)
    {
        var paths = new List<string>
                        {
                            @"C:\WINDOWS\AppPatch\MUI\040C",
                            @"C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727",
                            @"C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI",
                            @"C:\WINDOWS\addins",
                            @"C:\WINDOWS\AppPatch",
                            @"C:\WINDOWS\AppPatch\MUI",
                            @"C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI\0409"
                        };

        treeView1.PathSeparator = @"\";

        PopulateTreeView(treeView1, paths, '\\');
}


private static void PopulateTreeView(TreeView treeView, IEnumerable<string> paths, char pathSeparator)
    {
        TreeNode lastNode = null;
        string subPathAgg;
        foreach (string path in paths)
        {
            subPathAgg = string.Empty;
            foreach (string subPath in path.Split(pathSeparator))
            {
                subPathAgg += subPath + pathSeparator;
                TreeNode[] nodes = treeView.Nodes.Find(subPathAgg, true);
                if (nodes.Length == 0)
                    if (lastNode == null)
                        lastNode = treeView.Nodes.Add(subPathAgg, subPath);
                    else
                        lastNode = lastNode.Nodes.Add(subPathAgg, subPath);
                else
                    lastNode = nodes[0];
            }
        }
    }

Answer 2

ehosca 答案是正确的，但有一个小问题，
当我将路径更改为这样的

C:\WINDOWS\AppPatch\MUI\040C
D:\WIS\Microsoft.NET\Framework\v2.0.50727
E:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI
C:\WINDOWS\addins
C:\WINDOWS\AppPatch
C:\WINDOWS\AppPatch\MUI
C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI\0409

它将像这样填充树视图。

但是添加一些额外的代码我们可以避免这种情况。 所以我更改了 PopulateTreeView 中的代码

private static void PopulateTreeView(TreeView treeView, string[] paths, char pathSeparator)
        {
            TreeNode lastNode = null;
            string subPathAgg;
            foreach (string path in paths)
            {
                subPathAgg = string.Empty;
                foreach (string subPath in path.Split(pathSeparator))
                {
                    subPathAgg += subPath + pathSeparator;
                    TreeNode[] nodes = treeView.Nodes.Find(subPathAgg, true);
                    if (nodes.Length == 0)
                        if (lastNode == null)
                            lastNode = treeView.Nodes.Add(subPathAgg, subPath);
                        else
                            lastNode = lastNode.Nodes.Add(subPathAgg, subPath);
                    else
                        lastNode = nodes[0];
                }
                lastNode = null; // This is the place code was changed

            }
        }

现在它工作正常，如下所示

Answer 3

对于 linq'y 版本：

public static TreeNode MakeTreeFromPaths(List<string> paths, string rootNodeName = "", char separator = '/')
{
    var rootNode = new TreeNode(rootNodeName);
    foreach (var path in paths.Where(x => !string.IsNullOrEmpty(x.Trim()))) {
        var currentNode = rootNode;
        var pathItems = path.Split(separator);
        foreach (var item in pathItems) {
            var tmp = currentNode.Nodes.Cast<TreeNode>().Where(x => x.Text.Equals(item));
            currentNode = tmp.Count() > 0 ? tmp.Single() : currentNode.Nodes.Add(item);
        }
    }
    return rootNode;
}

Answer 4

我拿了你的代码，它运行得很好，
但我只是做了一点修改来提高加载速度
当它用于大量文件列表时
看起来像查找操作，而字符串操作通常非常慢，

private TreeNode PopulateTreeNode2(string[] paths, string pathSeparator)
    {
        if (paths == null)
            return null;

        TreeNode thisnode = new TreeNode();
        TreeNode currentnode;
        char[] cachedpathseparator = pathSeparator.ToCharArray();
        foreach (string path in paths)            {
            currentnode = thisnode;
            foreach (string subPath in path.Split(cachedpathseparator))
            {
                if (null == currentnode.Nodes[subPath])
                    currentnode = currentnode.Nodes.Add(subPath, subPath);
                else
                    currentnode = currentnode.Nodes[subPath];                   
            }
        }

        return thisnode;
    }

那么您可以使用：

string[] paths =  {
                        @"C:\WINDOWS\AppPatch\MUI\040C",
                        @"D:\WINDOWS\Microsoft.NET\Framework\v2.0.50727",
                        @"E:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI",
                        @"C:\WINDOWS\addins",
                        @"C:\WINDOWS\AppPatch",
                        @"C:\WINDOWS\AppPatch\MUI",
                        @"C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\MUI\0409"
                    };
TreeView treeview = new TreeView();
treeview.Nodes.Add(PopulateTreeNode2(paths, "\\"));

注意：两种解决方案中可能都需要一些字符串敏感性检查，
为了防止重新创建某些文件夹。

因为某些 url 可能指向磁盘上的同一文件夹
但拼写不同，例如：
窗户； Windows , WINDOWS

Answer 5

我尝试了 ykm29 的代码，但它无法正确填充子文件夹。 这里的一些其他答案也使用单个路径部分来识别创建的 TreeNodes。 如果不同目录中存在重复的文件夹名称，可能会导致我认为的问题。

因此，在我的代码中，我将“currentPath”值设置为我为文件夹获取的 TreeNodes 的键。 下面代码中的“ExtendedFileInfo”扩展了“FileInfo”类，并为我自己的用例添加了一些附加属性。 在调用此函数之前，创建根节点并将其分配给 TreeView。

private void MakeTreeViewFromPaths(TreeNode rootNode, List<ExtendedFileInfo> files, string rootNodeName = "C:\\", char separator = '\\')
    {
        foreach (var file in files)
        {
            TreeNode currentNode = rootNode;
            string[] relPath = file.RelativePath.Split(separator);
            string currentPath = rootNodeName;  

            //**Split operation always generates an empty entry so we use "-1" to avoid iterating through the last empty array item
            for (int i = 0; i < relPath.Length - 1; i++)
            {
                currentPath += "\\" + relPath[i];
                TreeNode[] tmp = currentNode.Nodes.Find(currentPath, false);
                if (tmp.Length > 0)
                {
                    currentNode = tmp[0];
                    continue;
                }
                //Create Folder Nodes
                currentNode = currentNode.Nodes.Add(currentPath, relPath[i]);
            }

            //Create File Nodes
            TreeNode newNode = new TreeNode(file.FileInfo.Name);
            newNode.Tag = file;
            currentNode.Nodes.Add(newNode);
        }
    }

Answer 6

下面是我曾经用来从代码创建 ASP.NET 树视图的一些非常旧的代码（假设 TreeView 的 ID 为 TreeViewFolders）：

protected void Page_Load(object sender, EventArgs e)
{
    GenerateTreeView(@"C:\WINDOWS\");
}

private void GenerateTreeView(string rootPath)
{
    GetFolders(System.IO.Path.GetFullPath(rootPath), TreeViewFolders.Nodes);
    TreeViewFolders.ExpandDepth = 1;
}

// recursive method to load all folders and files into tree
private void GetFolders(string path, TreeNodeCollection nodes)
{
    // add nodes for all directories (folders)
    string[] dirs = Directory.GetDirectories(path);
    foreach (string p in dirs)
    {
        string dp = p.Substring(path.Length);
        nodes.Add(Node("", p.Substring(path.Length), "folder"));
    }

    // add nodes for all files in this directory (folder)
    string[] files = Directory.GetFiles(path, "*.*");
    foreach (string p in files)
    {
        nodes.Add(Node(p, p.Substring(path.Length), "file"));
    }

    // add all subdirectories for each directory (recursive)
    for (int i = 0; i < nodes.Count; i++)
    {
        if (nodes[i].Value == "folder")
            GetFolders(dirs[i] + "\\", nodes[i].ChildNodes);
    }
}

// create a TreeNode from the specified path, text and type
private TreeNode Node(string path, string text, string type)
{
    TreeNode n = new TreeNode();
    n.Value = type;
    n.Text = text;
    return n;
}

Answer 7

private void Form2_Load(object sender, EventArgs e)
{
    treeView1.CheckBoxes = true;

    foreach (TreeNode node in treeView1.Nodes)
    {
        node.Checked = true;
    }

    string[] drives = Environment.GetLogicalDrives();

    foreach (string drive in drives)
    {
        // treeView1.Nodes[0].Nodes[1].Checked = true;
        DriveInfo di = new DriveInfo(drive);
        int driveImage;

        switch (di.DriveType)   
        {
            case DriveType.CDRom:
                driveImage = 3;
                break;
            case DriveType.Network:
                driveImage = 6;
                break;
            case DriveType.NoRootDirectory:
                driveImage = 8;
                break;
            case DriveType.Unknown:
                driveImage = 8;
                break;
            default:
                driveImage = 2;
                break;
        }

        TreeNode node = new TreeNode(drive.Substring(0, 1), driveImage, driveImage);
        node.Tag = drive;

        if (di.IsReady == true)
             node.Nodes.Add("...");

        treeView1.Nodes.Add(node);          
    }

    foreach (TreeNode node in treeView1.Nodes)
    {
        node.Checked = true;
    }
}

private void treeView1_BeforeExpand(object sender, TreeViewCancelEventArgs e)
{
    {
        if (e.Node.Nodes.Count > 0)
        {
            if (e.Node.Nodes[0].Text == "..." && e.Node.Nodes[0].Tag == null)
            {
                e.Node.Nodes.Clear();

                string[] dirs = Directory.GetDirectories(e.Node.Tag.ToString());

                foreach (string dir in dirs)
                {
                    DirectoryInfo di = new DirectoryInfo(dir);
                    TreeNode node = new TreeNode(di.Name, 0, 1);
                    node.Checked = true;

                    try
                    {
                        node.Tag = dir;
                        if (di.GetDirectories().Count() > 0)
                            node.Nodes.Add(null, "...", 0, 0).Checked = node.Checked;
                    }
                    catch (UnauthorizedAccessException)
                    {
                        node.ImageIndex = 12;
                        node.SelectedImageIndex = 12;
                    }
                    catch (Exception ex)
                    {
                        MessageBox.Show(ex.Message, "DirectoryLister", MessageBoxButtons.OK,
                        MessageBoxIcon.Error);
                    }
                    finally
                    {
                        node.Checked = e.Node.Checked;
                        e.Node.Nodes.Add(node);
                    }
                }
            }
        }
    }              
}

private void treeView1_AfterCheck(object sender, TreeViewEventArgs e)
{
    button1.Enabled = false;
    TreeNode node = e.Node;
    bool is_checked = node.Checked;
    foreach (TreeNode childNode in e.Node.Nodes)
    {
        childNode.Checked = e.Node.Checked;
    }
    treeView1.SelectedNode = node;
 }

Answer 8

我已经成功地仅使用 for 循环从路径列表创建了一棵树。 而现在看来，这就是这个问题最简单的答案了。

使用此代码块创建一棵树。 list 是文件或文件夹的列表，treeView1 是您的 TreeView。

//Creates a tree from given path list
foreach (string path in list)
{
    TreeNodeCollection nodes = treeView1.Nodes;

    foreach (string path_part in path.Split('\\'))
    {
        //Here it adds a new node (file or folder)
        if (!nodes.ContainsKey(path_part))
            nodes.Add(path_part, path_part);
        //Go one node deeper
        nodes = nodes[path_part].Nodes;
    }
}

注意 - 如果您将其与以路径分隔符开头的路径一起使用（例如 /home/user），

并且如果您想删除路径的公共部分（或删除单个父节点），则 这可能会中断，在上一个代码块之后使用此代码块：

//This removes "single" TreeNodes (common paths)
while (treeView1.Nodes.Count == 1)
{
    //This "unpacks" child TreeNodes from the only parent TreeNode
    for (int i = 0; i < treeView1.Nodes[0].Nodes.Count; i++)
        treeView1.Nodes.Add(treeView1.Nodes[0].Nodes[i]);
    //This removes parent TreeNode
    treeView1.Nodes.RemoveAt(0);
}

如果所有路径都相同，这将生成一棵空树。