这个 Quartz Cron 表达式是如何执行的

发布于 2024-07-27 01:36:33 字数 435 浏览 3 评论 0原文

我有以下内容；

private String cronExpression = "";
private final String jobID = "MyJObID";
...
Scheduler scheduler = ServiceLocator.getInstance().getScheduler();
CronTrigger trigger = new CronTrigger(jobID , Scheduler.DEFAULT_GROUP, cronExpression);
JobDetail jobDetail = new JobDetail(jobID , Scheduler.DEFAULT_GROUP, MyJob.class);
scheduler.scheduleJob(jobDetail, trigger);

我的问题是空 cron 表达式何时触发此作业？

原文

I have a the following;

private String cronExpression = "";
private final String jobID = "MyJObID";
...
Scheduler scheduler = ServiceLocator.getInstance().getScheduler();
CronTrigger trigger = new CronTrigger(jobID , Scheduler.DEFAULT_GROUP, cronExpression);
JobDetail jobDetail = new JobDetail(jobID , Scheduler.DEFAULT_GROUP, MyJob.class);
scheduler.scheduleJob(jobDetail, trigger);

My question is when is this job triggered for the empty cron expression?

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二手情话 2024-08-03 01:36:33

你确定它有效吗？

只需查看 org.quartz.CronExpression#buildExpression() 方法代码，看起来应该抛出异常：

        if (exprOn <= DAY_OF_WEEK) {
            throw new ParseException("Unexpected end of expression.",
                        expression.length());
        }

      // exprOn should be equal to SECOND in case of empty String given

[在 Quartz 1.6.0 中检查]

Are you sure it works?

Just by looking at the org.quartz.CronExpression#buildExpression() method code it looks like an exception should be thrown:

        if (exprOn <= DAY_OF_WEEK) {
            throw new ParseException("Unexpected end of expression.",
                        expression.length());
        }

      // exprOn should be equal to SECOND in case of empty String given

[checked in Quartz 1.6.0]

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