如何将数组作为对象属性添加到 PHP 扩展中声明的类中？

发布于 2024-07-26 18:41:29 字数 1223 浏览 10 评论 0原文

我希望我的 PHP 扩展声明一个与以下 PHP 等效的类：

class MyClass
{
    public $MyMemberArray;

    __construct()
    {
        $this->MyMemberArray = array();
    }
}

我正在遵循“高级 PHP 编程" 和 "扩展和嵌入 PHP" 并且我能够声明一个类在 PHP_MINIT_FUNCTION 中具有整数属性。

但是，当我使用相同的方法在 PHP_MINIT_FUNCTION 中声明数组属性时，我在运行时收到以下错误消息：

PHP Fatal error:  Internal zval's can't be arrays, objects or resources in Unknown on line 0

高级 PHP 编程第 557 页上有一个示例，说明如何声明一个构造函数，该构造函数创建一个数组属性，但示例代码无法编译（第二个“对象”似乎是多余的）。

我修复了该错误并将其改编为我的代码：

PHP_METHOD(MyClass, __construct)
{
    zval *myarray;
    zval *pThis;

    pThis = getThis();

    MAKE_STD_ZVAL(myarray);

    array_init(myarray);
    zend_declare_property(Z_OBJCE_P(pThis), "MyMemberArray", sizeof("MyMemberArray"), myarray, ZEND_ACC_PUBLIC TSRMLS_DC);
}

并且可以编译，但它在构造时给出相同的运行时错误。

原文

I want my PHP extension to declare a class equivalent to the following PHP:

class MyClass
{
    public $MyMemberArray;

    __construct()
    {
        $this->MyMemberArray = array();
    }
}

I'm following the examples in "Advanced PHP Programming" and "Extending and Embedding PHP" and I'm able to declare a class that has integer properties in PHP_MINIT_FUNCTION.

However, when I use the same approach to declare an array property in PHP_MINIT_FUNCTION, I get the following error message at runtime:

PHP Fatal error:  Internal zval's can't be arrays, objects or resources in Unknown on line 0

There's an example on page 557 of Advanced PHP Programming of how to declare a constructor which creates an array property, but the example code doesn't compile (the second "object" seems to be redundant).

I fixed the bug and adapted it to my code:

PHP_METHOD(MyClass, __construct)
{
    zval *myarray;
    zval *pThis;

    pThis = getThis();

    MAKE_STD_ZVAL(myarray);

    array_init(myarray);
    zend_declare_property(Z_OBJCE_P(pThis), "MyMemberArray", sizeof("MyMemberArray"), myarray, ZEND_ACC_PUBLIC TSRMLS_DC);
}

And this compiles, but it gives the same runtime error on construction.

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小伙你站住 2024-08-02 18:41:30

答案是在构造函数中使用add_property_zval_ex()，而不是zend_declare_property()。

以下工作按预期进行：

PHP_METHOD(MyClass, __construct)
{
    zval *myarray;
    zval *pThis;

    pThis = getThis();

    MAKE_STD_ZVAL(myarray);

    array_init(myarray);
    add_property_zval_ex(pThis, "MyMemberArray", sizeof("MyMemberArray"), myarray);
}

The answer is to use add_property_zval_ex() in the constructor, rather than zend_declare_property().

The following works as intended:

PHP_METHOD(MyClass, __construct)
{
    zval *myarray;
    zval *pThis;

    pThis = getThis();

    MAKE_STD_ZVAL(myarray);

    array_init(myarray);
    add_property_zval_ex(pThis, "MyMemberArray", sizeof("MyMemberArray"), myarray);
}

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