如何根据单选类型选择切换 div?

发布于 2024-07-26 11:18:49 字数 1488 浏览 1 评论 0原文

我使用类似这样的东西切换 div -

<input type="radio" name="myRadio" value="myDiv_1" />MyDiv
<input type="radio" name="myRadio" value="myDiv_2" />MyDiv2
<input type="radio" name="myRadio" value="myDiv_3" />MyDiv3

<div id="myDiv_1"> 1 Some input fields, text </div>
<div id="myDiv_2"> 2 More input fields, text </div>
<div id="myDiv_3"> 3 More input fields, text </div> 

JAVASCRIPT

$('#myDiv_1').hide();
$('#myDiv_2').hide();
$('#myDiv_3').hide();

$('input[name="myRadio"]').change(function() {
        var selected_type = $(this).val();
        switch(selected_type) {
            case "myDiv_1":
                $('#myDiv_1').slideDown();
                //if others are visible just slideup
                $('#myDiv_2').slideUp(); 
                $('#myDiv_3').slideUp();
            break;

            case "myDiv_2": 
                $('#myDiv_2').slideDown();
                //if others are visible just slideup
                $('#myDiv_1').slideUp(); 
                $('#myDiv_3').slideUp();
            break;
            case "myDiv_3": 
                $('#myDiv_3').slideDown();
                //if others are visible just slideup
                $('#myDiv_2').slideUp(); 
                $('#myDiv_1').slideUp();
            break;
        }
    }
);

这工作正常。 我的问题是如何改进它并使其更加灵活,就好像我必须使用更多 div 来修改所有 switch 情况一样。

还应该将开关功能包含在一个函数中,并将该函数绑定到单击和更改等事件(只是为了确保切换有效)?

感谢您的帮助。

I toggle a div using something like this -

<input type="radio" name="myRadio" value="myDiv_1" />MyDiv
<input type="radio" name="myRadio" value="myDiv_2" />MyDiv2
<input type="radio" name="myRadio" value="myDiv_3" />MyDiv3

<div id="myDiv_1"> 1 Some input fields, text </div>
<div id="myDiv_2"> 2 More input fields, text </div>
<div id="myDiv_3"> 3 More input fields, text </div> 

JAVASCRIPT

$('#myDiv_1').hide();
$('#myDiv_2').hide();
$('#myDiv_3').hide();

$('input[name="myRadio"]').change(function() {
        var selected_type = $(this).val();
        switch(selected_type) {
            case "myDiv_1":
                $('#myDiv_1').slideDown();
                //if others are visible just slideup
                $('#myDiv_2').slideUp(); 
                $('#myDiv_3').slideUp();
            break;

            case "myDiv_2": 
                $('#myDiv_2').slideDown();
                //if others are visible just slideup
                $('#myDiv_1').slideUp(); 
                $('#myDiv_3').slideUp();
            break;
            case "myDiv_3": 
                $('#myDiv_3').slideDown();
                //if others are visible just slideup
                $('#myDiv_2').slideUp(); 
                $('#myDiv_1').slideUp();
            break;
        }
    }
);

This works fine. My question is how I can improve it and make it more flexible as if I have to MORE divs I have to modify all cases of switch.

Also should enclose the switch functionality in a function and bind this function to events such as click and change (just to ensure that toggling works)??

Thanks for your help.

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评论(3

迷爱 2024-08-02 11:18:50

这有效,我刚刚测试过。

<script type="text/javascript">
$(document).ready(function(){

    $('.MyDiv').hide();

    $('input[name="myRadio"]').change(function(){
        var selected = $(this).val();
        $('.MyDiv').slideUp();
        $('#'+selected).slideDown();
    });

});
</script>

单选按钮应如下所示,其中 value 是应显示的元素的 id

<form action="example.com" method="post">
    <input type="radio" name="myRadio" value="myDiv_1" />MyDiv<br />
    <input type="radio" name="myRadio" value="myDiv_2" />MyDiv2<br />
    <input type="radio" name="myRadio" value="myDiv_3" />MyDiv3<br />
    <input type="radio" name="myRadio" value="myDiv_4" />MyDiv4
</form>

最后,div 应该如下所示,全部具有类 MyDiv

<div id="myDiv_1" class="MyDiv">Div number 1!</div>
<div id="myDiv_2" class="MyDiv">Div number 2!</div>
<div id="myDiv_3" class="MyDiv">Div number 3!</div>
<div id="myDiv_4" class="myDiv">Div number 4!</div>

This works, I just tested it.

<script type="text/javascript">
$(document).ready(function(){

    $('.MyDiv').hide();

    $('input[name="myRadio"]').change(function(){
        var selected = $(this).val();
        $('.MyDiv').slideUp();
        $('#'+selected).slideDown();
    });

});
</script>

The radio buttons should look like this, where the value is the id of the element that should be shown.

<form action="example.com" method="post">
    <input type="radio" name="myRadio" value="myDiv_1" />MyDiv<br />
    <input type="radio" name="myRadio" value="myDiv_2" />MyDiv2<br />
    <input type="radio" name="myRadio" value="myDiv_3" />MyDiv3<br />
    <input type="radio" name="myRadio" value="myDiv_4" />MyDiv4
</form>

And finally, the divs should look like this, all having the class MyDiv:

<div id="myDiv_1" class="MyDiv">Div number 1!</div>
<div id="myDiv_2" class="MyDiv">Div number 2!</div>
<div id="myDiv_3" class="MyDiv">Div number 3!</div>
<div id="myDiv_4" class="myDiv">Div number 4!</div>
绮烟 2024-08-02 11:18:50

以下内容基于您粘贴到此处的代码 - 在使用之前,请阅读以下内容:

$("div").hide();
$("input[name='myRadio']").change(function(){
  $("div:not(#"+$(this).val()+")").slideUp();
  $("div#"+$(this).val()).slideDown();
});

在使用之前...

我建议您向每个可折叠面板添加一个类,可能是 .panel。 然后更新选择器以仅修改 div.panel 而不是页面上的每个 div。

The following is based on the code you pasted here - before using, read below:

$("div").hide();
$("input[name='myRadio']").change(function(){
  $("div:not(#"+$(this).val()+")").slideUp();
  $("div#"+$(this).val()).slideDown();
});

Before Using...

I would suggest you add a class to each of the collapsable panels, maybe .panel. And then update the selectors to modify only div.panel instead of every div on the page.

执妄 2024-08-02 11:18:50

您的解决方案在 IE 8 中不起作用 - 实际上具有相反的行为。 使用“点击”功能而不是“更改”

  $('.myDiv').hide(); 
    $('input[name="myRadio"]').click(function(){
        var selected = $(this).val();
       $('.myDiv').slideUp();
        $('#'+selected).slideDown();
    });

your solution doesn't work in IE 8-- actually has the opposite behavior. Use the "click" function instead of "change"

  $('.myDiv').hide(); 
    $('input[name="myRadio"]').click(function(){
        var selected = $(this).val();
       $('.myDiv').slideUp();
        $('#'+selected).slideDown();
    });
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