MSBuild 烦恼（或者我的公然无知）

发布于 2024-07-26 10:07:10 字数 711 浏览 7 评论 0原文

在重新设计我们的部署过程时，我转而使用 MSBuild 项目来代替现有的批处理文件。所有主要元素都已就位，我本想删掉一两步，但遇到了障碍。

我正在使用组合路径任务创建一个名为 OutputPath 的属性，虽然在创建它后我可以毫无问题地访问它，但我不知道如何使用它来发挥我的优势。考虑一下：

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" ItemName ="OutputFolder"/>
</CombinePath>

<MakeDir Directories="@(OutputFolder)" />
<MakeDir Directories="@(OutputFolder)\Foo" />
<MakeDir Directories="@(OutputFolder)\Bar" />

命令 2 和 3 失败，因为我正在引用一个数组并尝试与一个字符串连接。创建属性并将其分配给 @(OutputFolder) 只会产生另一个项目组，而不是我可以使用 $ 访问器引用的属性。我确实有一个丑陋的解决方法，但我很想澄清这一点。

谢谢，

-何塞

原文

In reworking our deployment process I moved over to using an MSBuild project in place of our existing batch files. All of the major elements are in place, and I was looking to cut out a step or two but ran into a snag.

I'm creating a property called OutputPath using the CombinePath task, and, while I can access it with no issues after it has been created I'm at a loss as for how to use it to my advantage. Consider:

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" ItemName ="OutputFolder"/>
</CombinePath>

<MakeDir Directories="@(OutputFolder)" />
<MakeDir Directories="@(OutputFolder)\Foo" />
<MakeDir Directories="@(OutputFolder)\Bar" />

Commands 2 and 3 fail because I'm referencing an array and attempting to concatenate with a string. Creating a property and assigning it @(OutputFolder) simply results in another item group, not a property I can reference with the $ accessor. I do have an ugly workaround but I'd love to clear this up somewhat.

Thanks,

-Jose

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不念旧人 2024-08-02 10:07:10

我不确定确切的答案，但这里有一个想法：

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" ItemName ="OutputFolder"/>
</CombinePath>

<OutputFolder Include="$(DeployFolderRoot)$(DeployReleaseFolder)$(ReleaseFolderFormatted)\Foo" /> 
<OutputFolder Include="$(DeployFolderRoot)$(DeployReleaseFolder)$(ReleaseFolderFormatted)\Bar" />

<MakeDir Directories="@(OutputFolder)" />

本质上，如果您使用路径创建 OutputFolder 项目，它们将被附加到列表中。顺便说一句，这必须位于元素中，并且您必须使用 Include=""。

I'm not sure of the answer exactly but here is an idea:

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" ItemName ="OutputFolder"/>
</CombinePath>

<OutputFolder Include="$(DeployFolderRoot)$(DeployReleaseFolder)$(ReleaseFolderFormatted)\Foo" /> 
<OutputFolder Include="$(DeployFolderRoot)$(DeployReleaseFolder)$(ReleaseFolderFormatted)\Bar" />

<MakeDir Directories="@(OutputFolder)" />

Essentially, if you create OutputFolder items with the path they will just be appended to the list. This would have to be in an element btw, and you have to use Include="".

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浅唱々樱花落 2024-08-02 10:07:10

噢！绝对是无知，在输出元素上使用了错误的属性。

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" PropertyName="OutputFolder"/>
</CombinePath>

<MakeDir Directories="$(OutputFolder)" />
<MakeDir Directories="$(OutputFolder)\Foo" />
<MakeDir Directories="$(OutputFolder)\Bar" />

dOh! Definitely ignorance, used the wrong attribute on the Output element.

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" PropertyName="OutputFolder"/>
</CombinePath>

<MakeDir Directories="$(OutputFolder)" />
<MakeDir Directories="$(OutputFolder)\Foo" />
<MakeDir Directories="$(OutputFolder)\Bar" />

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~没有更多了~