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调整目录中图像的大小

发布于 2024-07-26 07:59:59 字数 108 浏览 6 评论 0原文

我有一个充满图像的目录，我想将其大小调整到原始大小的 60% 左右。

我该怎么做呢？可以是 Python 或 Perl

Cheers

Eef

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两相知 2024-08-02 07:59:59

如果您想以编程方式执行此操作（我认为是这种情况），请使用 PIL 调整大小，

newIm = im.resize((newW, newH)

然后将其保存到同一文件或新位置。

递归地遍历文件夹并对所有图像应用调整大小功能。

我想出了一个示例脚本，我认为它适合您。您可以改进它：也许使其图形化，添加更多选项，例如相同的扩展名或可能全部为 png，调整采样线性/双线性的大小等

import os
import sys
from PIL import Image

def resize(folder, fileName, factor):
    filePath = os.path.join(folder, fileName)
    im = Image.open(filePath)
    w, h  = im.size
    newIm = im.resize((int(w*factor), int(h*factor)))
    # i am saving a copy, you can overrider orginal, or save to other folder
    newIm.save(filePath+"copy.png")

def bulkResize(imageFolder, factor):
    imgExts = ["png", "bmp", "jpg"]
    for path, dirs, files in os.walk(imageFolder):
        for fileName in files:
            ext = fileName[-3:].lower()
            if ext not in imgExts:
                continue

            resize(path, fileName, factor)

if __name__ == "__main__":
    imageFolder=sys.argv[1] # first arg is path to image folder
    resizeFactor=float(sys.argv[2])/100.0# 2nd is resize in %
    bulkResize(imageFolder, resizeFactor)

If you want to do it programatically, which I assume is the case, use PIL to resize e.g.

newIm = im.resize((newW, newH)

then save it to same file or a new location.

Go through the folder recursively and apply resize function to all images.

I have come up with a sample script which I think will work for you. You can improve on it: Maybe make it graphical, add more options e.g. same extension or may be all png, resize sampling linear/bilinear etc

import os
import sys
from PIL import Image

def resize(folder, fileName, factor):
    filePath = os.path.join(folder, fileName)
    im = Image.open(filePath)
    w, h  = im.size
    newIm = im.resize((int(w*factor), int(h*factor)))
    # i am saving a copy, you can overrider orginal, or save to other folder
    newIm.save(filePath+"copy.png")

def bulkResize(imageFolder, factor):
    imgExts = ["png", "bmp", "jpg"]
    for path, dirs, files in os.walk(imageFolder):
        for fileName in files:
            ext = fileName[-3:].lower()
            if ext not in imgExts:
                continue

            resize(path, fileName, factor)

if __name__ == "__main__":
    imageFolder=sys.argv[1] # first arg is path to image folder
    resizeFactor=float(sys.argv[2])/100.0# 2nd is resize in %
    bulkResize(imageFolder, resizeFactor)

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安稳善良 2024-08-02 07:59:59

使用 ImageMagick 的一部分 mogrify 怎么样？如果你确实需要从 Perl 控制它，那么你可以使用 Image::Magick， Image::Resize 或成像器。

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简单 2024-08-02 07:59:59

可以在壳里吗？

mkdir resized
for a in *.jpg; do convert "$a" -resize 60% resized/"$a"; done

如果您有> 1个核心，你可以这样做：

find . -maxdepth 1 -type f -name '*.jpg' -print0 | xargs -0 -P3 -I XXX convert XXX -resize 60% resized/XXX

-P3意味着你想同时调整最多3个图像的大小（并行化）。

如果你不需要保留原件，你可以使用mogrify，但我更喜欢使用convert，然后rm ...； mv ... - 只是为了安全起见，如果调整大小（无论出于何种原因）失败。

Can it be in shell?

mkdir resized
for a in *.jpg; do convert "$a" -resize 60% resized/"$a"; done

If you have > 1 core, you can do it like this:

find . -maxdepth 1 -type f -name '*.jpg' -print0 | xargs -0 -P3 -I XXX convert XXX -resize 60% resized/XXX

-P3 means that you want to resize up to 3 images at the same time (parallelization).

If you don't need to keep originals you can use mogrify, but I prefer to use convert, and then rm ...; mv ... - just to be on safe side if resizing would (for whatever reason) fail.

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