使用 Visual Basic 打开文件
if 语句中的“读者”正在显示
表达式不是方法
Dim reader As New CSVReader
OpenFileDialog2.Filter = "CSV File (*.csv)|*.csv"
OpenFileDialog2.RestoreDirectory = True
If OpenFileDialog2.ShowDialog() = DialogResult.OK Then
reader(OpenFileDialog2.FileName)
reader.DisplayResults(DataGridView1)
'Return OpenFileDialog2.FileName
Else
End If
我移动了 Dim 并且它起作用了。
OpenFileDialog2.InitialDirectory = "a:"
OpenFileDialog2.Filter = "CSV File (*.csv)|*.csv"
OpenFileDialog2.RestoreDirectory = True
If OpenFileDialog2.ShowDialog() = DialogResult.OK Then
Dim reader As New CSVReader(OpenFileDialog2.FileName)
reader.DisplayResults(DataGridView1)
'Return OpenFileDialog2.FileName
Else
End If
The 'reader' within the if statement is showing
Expression is not a method
Dim reader As New CSVReader
OpenFileDialog2.Filter = "CSV File (*.csv)|*.csv"
OpenFileDialog2.RestoreDirectory = True
If OpenFileDialog2.ShowDialog() = DialogResult.OK Then
reader(OpenFileDialog2.FileName)
reader.DisplayResults(DataGridView1)
'Return OpenFileDialog2.FileName
Else
End If
I moved the Dim and it worked.
OpenFileDialog2.InitialDirectory = "a:"
OpenFileDialog2.Filter = "CSV File (*.csv)|*.csv"
OpenFileDialog2.RestoreDirectory = True
If OpenFileDialog2.ShowDialog() = DialogResult.OK Then
Dim reader As New CSVReader(OpenFileDialog2.FileName)
reader.DisplayResults(DataGridView1)
'Return OpenFileDialog2.FileName
Else
End If
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评论（2）
在这一行：
您试图在已构造的对象上调用构造函数。 这是不可能的，因此 VB 编译器会将此解释为您尝试调用读取器对象，就好像它是一个函数一样。
只是在获得文件名之前不要声明读取器，以便在实际构造它时可以将名称传递给构造函数，如下所示
On this line:
You're trying to call a constructor on an object that is already constructed. That's not possible, so the VB compiler is interpreting this as you trying to call the reader object as if it were a function.
Just don't declare the reader until you have the filename, so that you can pass the name to the constructor when you actually construct it, like so
您错过了
reader(OpenFileDialog2.FileName)中的方法名称。You missed out the method name in
reader(OpenFileDialog2.FileName).