如何使用 Cocoa 查找给定日期是一周中的哪一天

发布于 2024-07-25 21:17:38 字数 66 浏览 8 评论 0原文

我试图找出任何给定日期(即 2009 年 6 月 27 日)的哪一天(即星期一、星期五...)

谢谢。

I'm trying to figure out what day (i.e. Monday, Friday...) of any given date (i.e. Jun 27th, 2009)

Thank you.

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评论(4

一萌ing 2024-08-01 21:17:38

我一直在做:

NSDateFormatter* theDateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[theDateFormatter setFormatterBehavior:NSDateFormatterBehavior10_4];
[theDateFormatter setDateFormat:@"EEEE"];
NSString *weekDay =  [theDateFormatter stringFromDate:[NSDate date]];

这有一个额外的好处,让您可以选择如何返回工作日(通过更改 setDateFormat 中的日期格式字符串:调用

更多信息:

http://developer.apple.com/documentation/Cocoa /Conceptual/DataFormatting/Articles/dfDateFormatting10_4.html#//apple_ref/doc/uid/TP40002369

I've been doing:

NSDateFormatter* theDateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[theDateFormatter setFormatterBehavior:NSDateFormatterBehavior10_4];
[theDateFormatter setDateFormat:@"EEEE"];
NSString *weekDay =  [theDateFormatter stringFromDate:[NSDate date]];

This has the added bonus of letting you choose how you'd like the weekday to be returned (by changing the date format string in the setDateFormat: call

Lots more information at:

http://developer.apple.com/documentation/Cocoa/Conceptual/DataFormatting/Articles/dfDateFormatting10_4.html#//apple_ref/doc/uid/TP40002369

感悟人生的甜 2024-08-01 21:17:38

您可以查看 NSDate 和 NSCalendar 类。
例如, 这里这里

他们提供了以下代码:

NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc]
                         initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents =
                [gregorian components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:today];
NSInteger day = [weekdayComponents day];
NSInteger weekday = [weekdayComponents weekday];

You may have a look to the NSDate and NSCalendar classes.
For example, here and here

They provide the following code:

NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc]
                         initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents =
                [gregorian components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:today];
NSInteger day = [weekdayComponents day];
NSInteger weekday = [weekdayComponents weekday];
自演自醉 2024-08-01 21:17:38

使用 NSCalendar 和 NSDateComponents。 如 NSDateComponents 文档所示:

NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *date = [gregorian dateFromComponents:comps];
NSDateComponents *weekdayComponents = [gregorian components:NSWeekdayCalendarUnit fromDate:date];
int weekday = [weekdayComponents weekday];

Use NSCalendar and NSDateComponents. As shown in the NSDateComponents documentation:

NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *date = [gregorian dateFromComponents:comps];
NSDateComponents *weekdayComponents = [gregorian components:NSWeekdayCalendarUnit fromDate:date];
int weekday = [weekdayComponents weekday];
巨坚强 2024-08-01 21:17:38

这就是我的最终结果,它完全按照预期工作。 它需要一个日期,将日期更改为该月的第一天,并获取该日期的

    NSDateComponents *components = [[NSCalendar currentCalendar] components:NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear fromDate:date];
NSDateComponents *monthDateComponents = [[NSCalendar currentCalendar] components: NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear |
                                         NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond fromDate: date];

//  build date as start of month
monthDateComponents.year = components.year;
monthDateComponents.month = components.month;
monthDateComponents.day = 1;

NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
//    [gregorian setFirstWeekday:1];

NSDate *builtDate =[gregorian dateFromComponents: monthDateComponents];
//    NSDateComponents *weekdayComponents =[gregorian components: NSCalendarUnitWeekday fromDate: builtDate];

NSDateFormatter *df = [NSDateFormatter new];
[df setDateFormat:@"E"];

NSString *firstDay = [df stringFromDate:builtDate];
if([firstDay isEqual:@"Sun"])  //  do for the other 6 days as appropriate
    return 7;

Here's what I wound up with, which works exactly as intended. It takes a date, alters the date to be the first of the month, and gets the day of that date:

    NSDateComponents *components = [[NSCalendar currentCalendar] components:NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear fromDate:date];
NSDateComponents *monthDateComponents = [[NSCalendar currentCalendar] components: NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear |
                                         NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond fromDate: date];

//  build date as start of month
monthDateComponents.year = components.year;
monthDateComponents.month = components.month;
monthDateComponents.day = 1;

NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
//    [gregorian setFirstWeekday:1];

NSDate *builtDate =[gregorian dateFromComponents: monthDateComponents];
//    NSDateComponents *weekdayComponents =[gregorian components: NSCalendarUnitWeekday fromDate: builtDate];

NSDateFormatter *df = [NSDateFormatter new];
[df setDateFormat:@"E"];

NSString *firstDay = [df stringFromDate:builtDate];
if([firstDay isEqual:@"Sun"])  //  do for the other 6 days as appropriate
    return 7;
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