Java FileWriter 帮助

发布于 2024-07-25 12:23:24 字数 458 浏览 5 评论 0原文

好吧...所以我有一个相当有趣的错误...我声明了一个名为 file 的 FileWriter，并且让它经历以下 for 循环：

for (int i = 0; i < a.radtot; i++) {
    file.write("" + i * a.rstep);

    for (int n = 0; n < a.timetot; n++) {
        file.write("\t " + T[n][i]);
        System.out.println(T[n][i] + " " + n + " " + i);
    }

    file.write("\n");
}

最后，System.out.println 命令打印我期望的内容到，但文件中途中断...就像，不是打印出 System.out 所做的所有内容...它停在中间。有谁知道为什么会这样做？难道我做错了什么？

原文

Okay... so I have a fairly interesting error... I declare a FileWriter called file, and I have it go through the following for loops:

for (int i = 0; i < a.radtot; i++) {
    file.write("" + i * a.rstep);

    for (int n = 0; n < a.timetot; n++) {
        file.write("\t " + T[n][i]);
        System.out.println(T[n][i] + " " + n + " " + i);
    }

    file.write("\n");
}

At the end of it, the System.out.println command prints what I expect it to, but the file cuts off midway... As in, instead of printing out everything System.out does... it stops in the middle. Does anyone happen to know why it would do that? Am I doing something wrong?

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情仇皆在手 2024-08-01 12:23:24

您需要调用 close完成后，在 FileWriter 上单击 () 。这会强制所有输出实际写入磁盘（否则可能会留在缓冲区中）。

for (int i = 0; i < a.radtot; i++) {
    file.write("" + i * a.rstep);

    for (int n = 0; n < a.timetot; n++) {
        file.write("\t " + T[n][i]);
        System.out.println(T[n][i] + " " + n + " " + i);
    }

    file.write("\n");
}
file.close(); // <-- Add this

（为了简洁起见，我假设您省略了异常处理，所以我也做了同样的事情。close() 通常位于 finally 块中，以确保它会一直运行。）

You need to call close() on the FileWriter when you're done with it. This forces all output to be actually written to disk (it could be left in a buffer otherwise).

for (int i = 0; i < a.radtot; i++) {
    file.write("" + i * a.rstep);

    for (int n = 0; n < a.timetot; n++) {
        file.write("\t " + T[n][i]);
        System.out.println(T[n][i] + " " + n + " " + i);
    }

    file.write("\n");
}
file.close(); // <-- Add this

(I'm assuming you've omitted exception handling for brevity, so I have done the same. The close() would ordinarily be in a finally block to ensure that it will always run.)

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