如何使用 KSOAP2 从 Android 调用 .NET Web 服务?

发布于 2024-07-25 04:07:10 字数 1826 浏览 10 评论 0原文

我在调用网络服务时遇到问题。 我的服务器上有一个 .NET Web 服务,并且我在 Android 中使用 KSOAP2 (ksoap2-j2se-full-2.1.2)。 运行程序时,我遇到了类似“org.ksoap2.serialization.SoapPrimitive”的运行时异常。 我应该怎么办?

这是我的代码。

package projects.ksoap2sample;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;

import android.app.*;
import android.os.*;
import android.widget.TextView;

public class ksoap2sample extends Activity {
    /** Called when the activity is first created. */
    private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
    private static final String METHOD_NAME = "HelloWorld";
    private static final String NAMESPACE = "http://tempuri.org/";
    private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx";
    TextView tv;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        tv=(TextView)findViewById(R.id.text1);

        try {
            SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

            //request.addProperty("prop1", "myprop");

            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
            envelope.dotNet=true;
            envelope.setOutputSoapObject(request);

            HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

            androidHttpTransport.call(SOAP_ACTION, envelope);

            Object result = (Object)envelope.getResponse();

            String[] results = (String[])  result;
            tv.setText( ""+results[0]);
        }
        catch (Exception e) {
            tv.setText(e.getMessage());
        }
    }
}

I have a problem while calling a webservice. I have a .NET web service on the server, and I am using KSOAP2 (ksoap2-j2se-full-2.1.2) in Android. While running the program I got an runtime exception like "org.ksoap2.serialization.SoapPrimitive". What should I do?

Here is my code.

package projects.ksoap2sample;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;

import android.app.*;
import android.os.*;
import android.widget.TextView;

public class ksoap2sample extends Activity {
    /** Called when the activity is first created. */
    private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
    private static final String METHOD_NAME = "HelloWorld";
    private static final String NAMESPACE = "http://tempuri.org/";
    private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx";
    TextView tv;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        tv=(TextView)findViewById(R.id.text1);

        try {
            SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

            //request.addProperty("prop1", "myprop");

            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
            envelope.dotNet=true;
            envelope.setOutputSoapObject(request);

            HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

            androidHttpTransport.call(SOAP_ACTION, envelope);

            Object result = (Object)envelope.getResponse();

            String[] results = (String[])  result;
            tv.setText( ""+results[0]);
        }
        catch (Exception e) {
            tv.setText(e.getMessage());
        }
    }
}

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评论(6

荭秂 2024-08-01 04:07:10

这很简单。 您将结果放入一个原始对象中。

您的代码:

Object result = (Object)envelope.getResponse();

正确的代码:

SoapObject result=(SoapObject)envelope.getResponse();

//To get the data.
String resultData=result.getProperty(0).toString();
// 0 is the first object of data.

我认为这绝对应该有效。

It's very simple. You are getting the result into an Object which is a primitive one.

Your code:

Object result = (Object)envelope.getResponse();

Correct code:

SoapObject result=(SoapObject)envelope.getResponse();

//To get the data.
String resultData=result.getProperty(0).toString();
// 0 is the first object of data.

I think this should definitely work.

你与昨日 2024-08-01 04:07:10

您的 .NET Web 服务是什么样的?

我使用 来自 code.google.com 的 ksoap 2.3 获得了相同的效果。 一句,这很棒。)

我遵循了 代码项目 上的教程(顺便说 我曾经

    Integer result = (Integer)envelope.getResponse();

获取 Web 服务的结果(无论类型如何,我都尝试过 Object、String、int),但遇到了 org.ksoap2.serialization.SoapPrimitive 异常。

我找到了一个解决方案(解决方法)。 我要做的第一件事是从我的 webservice 方法中删除“SoapRpcMethod() 属性。

    [SoapRpcMethod(), WebMethod]
    public Object GetInteger1(int i)
    {
        // android device will throw exception
        return 0;
    }

    [WebMethod]
    public Object GetInteger2(int i)
    {
        // android device will get the value
        return 0;
    }

然后我将 Android 代码更改为:

    SoapPrimitive result = (SoapPrimitive)envelope.getResponse();

但是,我得到了一个 SoapPrimitive 对象,它有一个私有的“值”文件。幸运的是值是通过 toString() 方法传递的,因此我使用 Integer.parseInt(result.toString()) 来获取我的值,这对我来说已经足够了,因为我没有任何需要从 Web 服务获取的复杂类型,

以下是完整的源代码:

private static final String SOAP_ACTION = "http://tempuri.org/GetInteger2";
private static final String METHOD_NAME = "GetInteger2";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://10.0.2.2:4711/Service1.asmx";

public int GetInteger2() throws IOException, XmlPullParserException {
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    PropertyInfo pi = new PropertyInfo();
    pi.setName("i");
    pi.setValue(123);
    request.addProperty(pi);

    SoapSerializationEnvelope envelope =
        new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);

    AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
    androidHttpTransport.call(SOAP_ACTION, envelope);

    SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
    return Integer.parseInt(result.toString());
}

How does your .NET Webservice look like?

I had the same effect using ksoap 2.3 from code.google.com. I followed the tutorial on The Code Project (which is great BTW.)

And everytime I used

    Integer result = (Integer)envelope.getResponse();

to get the result of a my webservice (regardless of the type, I tried Object, String, int) I ran into the org.ksoap2.serialization.SoapPrimitive exception.

I found a solution (workaround). The first thing I had to do was to remove the "SoapRpcMethod() attribute from my webservice methods.

    [SoapRpcMethod(), WebMethod]
    public Object GetInteger1(int i)
    {
        // android device will throw exception
        return 0;
    }

    [WebMethod]
    public Object GetInteger2(int i)
    {
        // android device will get the value
        return 0;
    }

Then I changed my Android code to:

    SoapPrimitive result = (SoapPrimitive)envelope.getResponse();

However, I get a SoapPrimitive object, which has a "value" filed that is private. Luckily the value is passed through the toString() method, so I use Integer.parseInt(result.toString()) to get my value, which is enough for me, because I don't have any complex types that I need to get from my Web service.

Here is the full source:

private static final String SOAP_ACTION = "http://tempuri.org/GetInteger2";
private static final String METHOD_NAME = "GetInteger2";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://10.0.2.2:4711/Service1.asmx";

public int GetInteger2() throws IOException, XmlPullParserException {
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    PropertyInfo pi = new PropertyInfo();
    pi.setName("i");
    pi.setValue(123);
    request.addProperty(pi);

    SoapSerializationEnvelope envelope =
        new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);

    AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
    androidHttpTransport.call(SOAP_ACTION, envelope);

    SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
    return Integer.parseInt(result.toString());
}
空城旧梦 2024-08-01 04:07:10

将信封类型转换为 SoapPrimitive:

SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
String strRes = result.toString();

它将起作用。

Typecast the envelope to SoapPrimitive:

SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
String strRes = result.toString();

and it will work.

随梦而飞# 2024-08-01 04:07:10

您可以使用下面的代码调用 Web 服务并获取响应。确保您的 Web 服务以数据表格式返回响应。如果您使用来自 SQL Server 的数据,此代码可以帮助您 数据库。如果您使用 MYSQL,您需要更改一件事,只需替换句子 obj2=(SoapObject) obj1.getProperty(" 中的单词 NewDataSet ) NewDataSet"); by DocumentElement

private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://localhost/Web_Service.asmx?"; // you can use   IP address instead of localhost
private static final String METHOD_NAME = "Function_Name";
private static final String SOAP_ACTION = NAMESPACE + METHOD_NAME;

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("parm_name", prm_value); // Parameter for Method
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

try {
    androidHttpTransport.call(SOAP_ACTION, envelope); //call the eb service Method
} catch (Exception e) {
    e.printStackTrace();
} //Next task is to get Response and format that response

SoapObject obj, obj1, obj2, obj3;
obj = (SoapObject) envelope.getResponse();
obj1 = (SoapObject) obj.getProperty("diffgram");
obj2 = (SoapObject) obj1.getProperty("NewDataSet");

for (int i = 0; i < obj2.getPropertyCount(); i++) //the method getPropertyCount() return the number of rows
{
    obj3 = (SoapObject) obj2.getProperty(i);
    obj3.getProperty(0).toString(); //value of column 1
    obj3.getProperty(1).toString(); //value of column 2
    //like that you will get value from each column
}

如果您对此有任何问题,可以给我写信。

You can Use below code to call the web service and get response .Make sure that your Web Service return the response in Data Table Format..This code help you if you using data from SQL Server database .If you you using MYSQL you need to change one thing just replace word NewDataSet from sentence obj2=(SoapObject) obj1.getProperty("NewDataSet"); by DocumentElement

private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://localhost/Web_Service.asmx?"; // you can use   IP address instead of localhost
private static final String METHOD_NAME = "Function_Name";
private static final String SOAP_ACTION = NAMESPACE + METHOD_NAME;

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("parm_name", prm_value); // Parameter for Method
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

try {
    androidHttpTransport.call(SOAP_ACTION, envelope); //call the eb service Method
} catch (Exception e) {
    e.printStackTrace();
} //Next task is to get Response and format that response

SoapObject obj, obj1, obj2, obj3;
obj = (SoapObject) envelope.getResponse();
obj1 = (SoapObject) obj.getProperty("diffgram");
obj2 = (SoapObject) obj1.getProperty("NewDataSet");

for (int i = 0; i < obj2.getPropertyCount(); i++) //the method getPropertyCount() return the number of rows
{
    obj3 = (SoapObject) obj2.getProperty(i);
    obj3.getProperty(0).toString(); //value of column 1
    obj3.getProperty(1).toString(); //value of column 2
    //like that you will get value from each column
}

If you have any problem regarding this you can write me..

热情消退 2024-08-01 04:07:10

如果需要多个结果,则 getResponse() 方法将返回一个包含各种响应的 Vector

在这种情况下,有问题的代码将变为:

Object result = envelope.getResponse();

// treat result as a vector
String resultText = null;
if (result instanceof Vector)
{
    SoapPrimitive element0 = (SoapPrimitive)((Vector) result).elementAt(0);
    resultText = element0.toString();
}

tv.setText(resultText);

基于 ksoap2-android (mosabua fork) 的答案

If more than one result is expected, then the getResponse() method will return a Vector containing the various responses.

In which case the offending code becomes:

Object result = envelope.getResponse();

// treat result as a vector
String resultText = null;
if (result instanceof Vector)
{
    SoapPrimitive element0 = (SoapPrimitive)((Vector) result).elementAt(0);
    resultText = element0.toString();
}

tv.setText(resultText);

Answer based on the ksoap2-android (mosabua fork)

最偏执的依靠 2024-08-01 04:07:10

我认为你不能

 androidHttpTransport.call(SOAP_ACTION, envelope);

在主线程上调用。

网络操作应该在不同的线程上完成。

创建另一个线程或AsyncTask 来调用该方法。

I think you can't call

 androidHttpTransport.call(SOAP_ACTION, envelope);

on main Thread.

Network operations should be done on different Thread.

Create another Thread or AsyncTask to call the method.

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