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(C#) 如何获取屏幕的点与像素关系？

发布于 2024-07-24 23:21:52 字数 63 浏览 5 评论 0原文

据我了解，点与像素的关系取决于屏幕分辨率。那么如何在 C# 中在运行时计算它呢？

谢谢

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陪你搞怪i 2024-07-31 23:21:53

如果你想获取屏幕的 DPI，那就有点棘手了。您必须创建一个真正的 Graphics 对象并对其进行查询。

例如，在主窗体的 Load 事件中：

using( Graphics g = CreateGraphics() )
{
    _dpiX = g.DpiX;
    _dpiY = g.DpiY; // In practice usually == dpiX
    _points = _dpiX / 72.0f; // There are 72 points per inch
}

当然，大多数显示器都会谎报实际 DPI，并且始终返回 72 或 96，或者在启用大字体时返回 120。如果您实际上想要将物理英寸映射到屏幕，您可以必须在用户的帮助下实际校准它 - 让他们选择一条测量为 1 英寸的线。

If you're trying to get the DPI of the screen it's a bit trickier. You'll have to create a real Graphics object and query that.

For example, in the Load event of your main form:

using( Graphics g = CreateGraphics() )
{
    _dpiX = g.DpiX;
    _dpiY = g.DpiY; // In practice usually == dpiX
    _points = _dpiX / 72.0f; // There are 72 points per inch
}

Of course most monitors lie about the actual DPI and always return 72 or 96, or when large fonts are enabled 120. If you actually want to map a physical inch to a the screen you'll have to actually calibrate it with the user's help - having them pick a line that they measure to be 1 inch.

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静若繁花 2024-07-31 23:21:53

一切都在 Screen 对象中：

int bpp = System.Windows.Forms.Screen.PrimaryScreen.BitsPerPixel;
int wid = Screen.PrimaryScreen.WorkingArea.Width;
int ht = Screen.PrimaryScreen.WorkingArea.Height;

在我的机器上它给出：

bpp=32
width=1280
height=740

It is all in the Screen object:

int bpp = System.Windows.Forms.Screen.PrimaryScreen.BitsPerPixel;
int wid = Screen.PrimaryScreen.WorkingArea.Width;
int ht = Screen.PrimaryScreen.WorkingArea.Height;

On my machine it gives: