上传时获取原始文件创建日期

发布于 2024-07-24 17:57:45 字数 121 浏览 10 评论 0原文

我们有一个将文件上传到我们网站的流程。对于用户来说，能够看到这些文件的创建时间变得很重要。我正在寻找一种从 HttpPostedFile 中提取原始创建日期的方法。如果有人对我有想法，我会非常感激（此时我有点困惑）。

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风向决定发型 2024-07-31 17:57:46

我尝试了上面提到的布莱恩提到的方法，但它给了我不正确的日期。即 1600 年左右。

不过，您可以通过 FileUpload 控件的 files 属性从“lastModifiedDate”属性获取每个（待）上传文件的日期。

这是它的 HTML/Javascript 示例。
我取自：

http://www.w3schools.com/jsref/ tryit.asp?filename=tryjsref_fileupload_files
并根据我们的需要对其进行了一些修改。注意：请阅读下面这个 HTML /Javascript 片段之后我的评论。

<!DOCTYPE html>
<html>
<body onload="myFunction()">

<input type="file" id="myFile" multiple size="50" onchange="myFunction()">

<p id="demo"></p>

<script>
function myFunction(){
    var x = document.getElementById("myFile");
    var txt = "";
    if ('files' in myFile) {
        if (x.files.length == 0) {
            txt = "Select one or more files.";
        } else {
            for (var i = 0; i < x.files.length; i++) {
                txt += "<br><strong>" + (i+1) + ". file</strong><br>";
                var file = x.files[i];
                if ('name' in file) {
                    txt += "name: " + file.name + "<br>";
                }
                if ('size' in file) {
                    txt += "size: " + file.size + " bytes <br>";
                }
                if ('lastModifiedDate' in file) {
                    txt += "lastModifiedDate: " + file.lastModifiedDate.toString();
                }
            }
        }
    } 
    else {
        if (x.value == "") {
            txt += "Select one or more files.";
        } else {
            txt += "The files property is not supported by your browser!";
            txt  += "<br>The path of the selected file: " + x.value; // If the browser does not support the files property, it will return the path of the selected file instead. 
        }
    }
    document.getElementById("demo").innerHTML = txt;
}
</script>

<p><strong>Tip:</strong> Use the Control or the Shift key to select multiple files.</p>

</body>
</html>

例如，您可以使用 jQuery 文件上传控件将此信息作为附加参数传递。
以下是演示这一点的链接：

jquery 文件上传模块发送额外参数

I tried the approach mentioned by Bryon above but it gives me incorrect date. i.e something around year 1600.

You can however get the Date for each (to be) uploaded file from the 'lastModifiedDate' property via FileUpload control's files property.

Here is the sample HTML/Javascript for it.
I have taken it from:

http://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_fileupload_files
and modified it a bit for our need. Note: Please read my comment below after this HTML /Javascript snippet.

<!DOCTYPE html>
<html>
<body onload="myFunction()">

<input type="file" id="myFile" multiple size="50" onchange="myFunction()">

<p id="demo"></p>

<script>
function myFunction(){
    var x = document.getElementById("myFile");
    var txt = "";
    if ('files' in myFile) {
        if (x.files.length == 0) {
            txt = "Select one or more files.";
        } else {
            for (var i = 0; i < x.files.length; i++) {
                txt += "<br><strong>" + (i+1) + ". file</strong><br>";
                var file = x.files[i];
                if ('name' in file) {
                    txt += "name: " + file.name + "<br>";
                }
                if ('size' in file) {
                    txt += "size: " + file.size + " bytes <br>";
                }
                if ('lastModifiedDate' in file) {
                    txt += "lastModifiedDate: " + file.lastModifiedDate.toString();
                }
            }
        }
    } 
    else {
        if (x.value == "") {
            txt += "Select one or more files.";
        } else {
            txt += "The files property is not supported by your browser!";
            txt  += "<br>The path of the selected file: " + x.value; // If the browser does not support the files property, it will return the path of the selected file instead. 
        }
    }
    document.getElementById("demo").innerHTML = txt;
}
</script>

<p><strong>Tip:</strong> Use the Control or the Shift key to select multiple files.</p>

</body>
</html>

You can pass this information as an additional parameter using jQuery file upload control for example.
Here is the link demonstrating this:

jquery file upload module sending extra parameter

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烟酒忠诚 2024-07-31 17:57:46

您无权访问在客户端上创建文件的日期。您可以使用 Fiddler 来验证这一点。我相信您看到的唯一数据是文件名和 MIME 类型。

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红衣飘飘貌似仙 2024-07-31 17:57:46

这是我最终得到的解决方案。上传文件并将其保存到服务器后，您可以访问文件中的元数据（但是，此解决方案当前仅适用于图像文件 - 那里还有一些额外的代码可用于显示整个元数据如果需要的话，该文件，并且我在我破解的元数据中发现了一些奇怪的日期格式，这可能可以做得更干净）...

                System.IO.FileInfo fileInfo = new System.IO.FileInfo(UPLOAD_DIRECTORY + file.FileName);
                if (!fileInfo.Exists)
                {
                    break;
                }
                else
                {

                  //Check for metadata original create date
                  if (_imageFormats.Contains(fileInfo.Extension.ToLower()))
                  {
                    Stream fileStream = fileInfo.OpenRead();
                    System.Drawing.Image image = new System.Drawing.Bitmap(fileStream);

                    // Get the PropertyItems property from image.
                    System.Drawing.Imaging.PropertyItem[] propItems = image.PropertyItems;

                    // For each PropertyItem in the array, display the ID, type, and 
                    // length.
                    int count = 0;
                    string s1 = null;
                    string dateID = null;
                    foreach (System.Drawing.Imaging.PropertyItem propItem in propItems)
                    {
                      s1 += "Property Item " + count.ToString() + "/n/r";

                      s1 += "iD: 0x" + propItem.Id.ToString("x") + "/n/r";
                      if (("0x" + propItem.Id.ToString("x")) == PROPERTYTAGEXIFDTORIG)
                      {
                        dateID = count.ToString();
                      }
                      s1 += "type: " + propItem.Type.ToString() + "/n/r";

                      s1 += "length: " + propItem.Len.ToString() + " bytes" + "/n/r";

                      count++;
                    }
                    // Convert the value of the second property to a string, and display 
                    // it.
                    System.Text.ASCIIEncoding encoding = new System.Text.ASCIIEncoding();
                    if (dateID != null)
                    {
                      string date = encoding.GetString(propItems[int.Parse(dateID)].Value);
                      date = date.Replace("\0", string.Empty);
                      string[] datesplit = date.Split(' ');
                      string newDate = datesplit[0].Replace(":", "-") + " " + datesplit[1];
                      originalCreateDate = DateTime.Parse(newDate);
                    }
                    fileStream.Close();
                  }

Here's the solution I ended up with. Once you've uploaded the file and saved it to the server you can access the metadata in the file (this solution however, only currently applies to image files - there's also some extra code in there that could be used to show the entire metadata for the file if needed, and I found some weird date formating in the metadata that I hacked around that could probably be done cleaner)...

                System.IO.FileInfo fileInfo = new System.IO.FileInfo(UPLOAD_DIRECTORY + file.FileName);
                if (!fileInfo.Exists)
                {
                    break;
                }
                else
                {

                  //Check for metadata original create date
                  if (_imageFormats.Contains(fileInfo.Extension.ToLower()))
                  {
                    Stream fileStream = fileInfo.OpenRead();
                    System.Drawing.Image image = new System.Drawing.Bitmap(fileStream);

                    // Get the PropertyItems property from image.
                    System.Drawing.Imaging.PropertyItem[] propItems = image.PropertyItems;

                    // For each PropertyItem in the array, display the ID, type, and 
                    // length.
                    int count = 0;
                    string s1 = null;
                    string dateID = null;
                    foreach (System.Drawing.Imaging.PropertyItem propItem in propItems)
                    {
                      s1 += "Property Item " + count.ToString() + "/n/r";

                      s1 += "iD: 0x" + propItem.Id.ToString("x") + "/n/r";
                      if (("0x" + propItem.Id.ToString("x")) == PROPERTYTAGEXIFDTORIG)
                      {
                        dateID = count.ToString();
                      }
                      s1 += "type: " + propItem.Type.ToString() + "/n/r";

                      s1 += "length: " + propItem.Len.ToString() + " bytes" + "/n/r";

                      count++;
                    }
                    // Convert the value of the second property to a string, and display 
                    // it.
                    System.Text.ASCIIEncoding encoding = new System.Text.ASCIIEncoding();
                    if (dateID != null)
                    {
                      string date = encoding.GetString(propItems[int.Parse(dateID)].Value);
                      date = date.Replace("\0", string.Empty);
                      string[] datesplit = date.Split(' ');
                      string newDate = datesplit[0].Replace(":", "-") + " " + datesplit[1];
                      originalCreateDate = DateTime.Parse(newDate);
                    }
                    fileStream.Close();
                  }

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弃爱 2024-07-31 17:57:46

您只需从 HttpPostedFile::FileName 获取文件系统创建日期即可。

像这样的事情：

HttpFileCollection MyFileColl = Request.Files;
HttpPostedFile MyPostedFile = MyFileColl.Get(0);
String filename = MyPostedFile.FileName;
String creationTime;

if (File.Exists(fileName)) 
{
      creationTime = File.GetCreationTime(fileName).ToString(); 
}
System.writeLine(creationTime);

You just grab the file system creation date from the HttpPostedFile::FileName.

Somthing like this:

HttpFileCollection MyFileColl = Request.Files;
HttpPostedFile MyPostedFile = MyFileColl.Get(0);
String filename = MyPostedFile.FileName;
String creationTime;

if (File.Exists(fileName)) 
{
      creationTime = File.GetCreationTime(fileName).ToString(); 
}
System.writeLine(creationTime);

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~没有更多了~