如何启动低优先级进程？ C＃

发布于 2024-07-24 15:57:32 字数 472 浏览 9 评论 0原文

我想执行命令行工具来处理数据。它不需要阻塞。我希望它的优先级较低。所以我写了下面的内容

 Process app = new Process();
 app.StartInfo.FileName = @"bin\convert.exe";
 app.StartInfo.Arguments = TheArgs;
 app.PriorityClass = ProcessPriorityClass.BelowNormal;
 app.Start();

但是，我收到一个 System.InvalidOperationException ，其中包含消息“没有进程与此对象关联”。为什么？如何以低优先级正确启动此应用程序？

如果没有 app.PriorityClass = ProcessPriorityClass.BelowNormal; 行，应用程序运行正常。

原文

I want to execute a command line tool to process data. It does not need to be blocking.
I want it to be low priority. So I wrote the below

 Process app = new Process();
 app.StartInfo.FileName = @"bin\convert.exe";
 app.StartInfo.Arguments = TheArgs;
 app.PriorityClass = ProcessPriorityClass.BelowNormal;
 app.Start();

However, I get a System.InvalidOperationException with the message "No process is associated with this object." Why? How do I properly launch this app in low priority?

Without the line app.PriorityClass = ProcessPriorityClass.BelowNormal; the app runs fine.

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苍白女子 2024-07-31 15:57:33

尝试在启动该过程后设置 PriorityClass。任务管理器以这种方式工作，允许您为已经运行的进程设置优先级。

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短暂陪伴 2024-07-31 15:57:33

您可以通过一些小技巧来创建一个优先级较低的进程。您降低父进程优先级，创建新进程，然后恢复到原始进程优先级：

var parent   = Process.GetCurrentProcess();
var original = parent.PriorityClass;

parent.PriorityClass = ProcessPriorityClass.Idle;
var child            = Process.Start("cmd.exe");
parent.PriorityClass = original;

child 将在开始时具有 Idle 进程优先级。

You can create a process with lower priority by doing a little hack. You lower the parent process priority, create the new process and then revert back to the original process priority:

var parent   = Process.GetCurrentProcess();
var original = parent.PriorityClass;

parent.PriorityClass = ProcessPriorityClass.Idle;
var child            = Process.Start("cmd.exe");
parent.PriorityClass = original;

child will have the Idle process priority right at the start.

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