J2ME 中高效的游戏循环

发布于 2024-07-24 09:38:02 字数 754 浏览 2 评论 0原文

我已经回答了一系列有关 J2ME 游戏开发的问题，在最近的一个问题中，Neil Coffey 评论道

作为一个附带问题——你真的想要吗在 J2ME 游戏中每秒执行 100 个刻度？正如我认为某人提到的，你真该还睡到下所需的唤醒点，不是固定的每次持续时间。

出于某种原因，这件事在我脑海中挥之不去，现在我想要答案，我需要什么才能让我的游戏循环睡眠到所需的唤醒点，我真的不知道它在哪里点xD（理论上来说）。

为了提供反馈，这是我的游戏循环的简化版本：

public void run() {
    Graphics g = this.getGraphics();
    while (running) {
        long diff = System.currentTimeMillis() - lastLoop;
        lastLoop = System.currentTimeMillis();
        input();
        this.level.doLogic();
        render(g, diff);
        try {
            Thread.sleep(10);
        } catch (InterruptedException e) {
            stop(e);
        }
    }
}

感谢您的帮助！

原文

I've done a series of questions about J2ME Game developing, and in a recent one, Neil Coffey commented

As a side issue-- do you REALLY want
to do 100 ticks/second in a J2ME game?
As I think sb has mentioned, you
should really also sleep to the next
desired wake-up point, not a fixed
duration each time.

For some reason, that thing stuck in my mind and now I want the answers, what do I need to make my gameloop sleep to the desired wake-up point, I don't really know where is that point xD (theoretically speaking).

For the sake of feedback, this is a simplified version of my gameloop:

public void run() {
    Graphics g = this.getGraphics();
    while (running) {
        long diff = System.currentTimeMillis() - lastLoop;
        lastLoop = System.currentTimeMillis();
        input();
        this.level.doLogic();
        render(g, diff);
        try {
            Thread.sleep(10);
        } catch (InterruptedException e) {
            stop(e);
        }
    }
}

Thanks for your help!!

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

陈甜 2024-07-31 09:38:02

如果您还没有阅读过此处，有一篇关于游戏循环的精彩文章。

根据我编写 J2ME 游戏的经验，您需要尽量减少在游戏循环中执行任何操作的次数，因为编写得不好的游戏循环会很快耗尽手机的微薄电池。也就是说，如果您每 10 毫秒渲染一次，请务必检查是否有任何更改，如果没有，请跳过它。

回复收藏 0 原文

自此以后，行同陌路 2024-07-31 09:38:02

如果您决定每 10 毫秒渲染一次，那么您：

loop {
  - record current time; render
  - do input/logic
  - check the current time, and calculate elapsed time
    - if less than 10 ms has elapsed, calculate the remaining time (10 millis - elapsed time); sleep for this duration
}

我了解计时器分辨率可能存在问题（例如，Thread.sleep(10) 可能不会正好休眠 10 毫秒；而 System.currentTimeMillis() 可能不返回粒度低至 1 毫秒的结果）。这是平台相关的。

If you decide that you want to render every 10 milliseconds, then you:

loop {
  - record current time; render
  - do input/logic
  - check the current time, and calculate elapsed time
    - if less than 10 ms has elapsed, calculate the remaining time (10 millis - elapsed time); sleep for this duration
}

I understand that there may be issues with timer resolution (for example, Thread.sleep(10) may not sleep for exactly 10 ms; and System.currentTimeMillis() may not return results with granularity down to 1 ms). This is platform dependent.

回复收藏 0 原文

~没有更多了~