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R 中具有多个捕获组的正则表达式组捕获

发布于 2024-07-24 04:03:42 字数 348 浏览 10 评论 0原文

在 R 中，是否可以从正则表达式匹配中提取组捕获？ 据我所知，没有 grep、grepl、regexpr、gregexpr、sub< /code> 或 gsub 返回组捕获。

我需要从这样编码的字符串中提取键值对：

\((.*?) :: (0\.[0-9]+)\)

我总是可以执行多个完全匹配的 grep，或者执行一些外部（非 R）处理，但我希望我可以在 R 中完成这一切。有一个函数或一个包提供这样的函数来执行此操作吗？

原文

In R, is it possible to extract group capture from a regular expression match? As far as I can tell, none of grep, grepl, regexpr, gregexpr, sub, or gsub return the group captures.

I need to extract key-value pairs from strings that are encoded thus:

\((.*?) :: (0\.[0-9]+)\)

I can always just do multiple full-match greps, or do some outside (non-R) processing, but I was hoping I can do it all within R. Is there's a function or a package that provides such a function to do this?

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评论（9）

流年里的时光 2024-07-31 04:03:42

str_match()，来自 stringr 包，将执行此操作。 它返回一个字符矩阵，其中每一组对应一列（整个匹配对应一列）：

> s = c("(sometext :: 0.1231313213)", "(moretext :: 0.111222)")
> str_match(s, "\\((.*?) :: (0\\.[0-9]+)\\)")
     [,1]                         [,2]       [,3]          
[1,] "(sometext :: 0.1231313213)" "sometext" "0.1231313213"
[2,] "(moretext :: 0.111222)"     "moretext" "0.111222"

str_match(), from the stringr package, will do this. It returns a character matrix with one column for each group in the match (and one for the whole match):

> s = c("(sometext :: 0.1231313213)", "(moretext :: 0.111222)")
> str_match(s, "\\((.*?) :: (0\\.[0-9]+)\\)")
     [,1]                         [,2]       [,3]          
[1,] "(sometext :: 0.1231313213)" "sometext" "0.1231313213"
[2,] "(moretext :: 0.111222)"     "moretext" "0.111222"
回复 原文
谁对谁错谁最难过 2024-07-31 04:03:42

gsub 是这样做的，从您的示例来看：

gsub("\\((.*?) :: (0\\.[0-9]+)\\)","\\1 \\2", "(sometext :: 0.1231313213)")
[1] "sometext 0.1231313213"

您需要对引号中的 \s 进行双重转义，然后它们适用于正则表达式。

希望这可以帮助。

gsub does this, from your example:

gsub("\\((.*?) :: (0\\.[0-9]+)\\)","\\1 \\2", "(sometext :: 0.1231313213)")
[1] "sometext 0.1231313213"

you need to double escape the \s in the quotes then they work for the regex.

Hope this helps.

回复 原文
初熏 2024-07-31 04:03:42

尝试 regmatches() 和 regexec()：

regmatches("(sometext :: 0.1231313213)",regexec("\\((.*?) :: (0\\.[0-9]+)\\)","(sometext :: 0.1231313213)"))
[[1]]
[1] "(sometext :: 0.1231313213)" "sometext"                   "0.1231313213"

Try regmatches() and regexec():

regmatches("(sometext :: 0.1231313213)",regexec("\\((.*?) :: (0\\.[0-9]+)\\)","(sometext :: 0.1231313213)"))
[[1]]
[1] "(sometext :: 0.1231313213)" "sometext"                   "0.1231313213"
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玩套路吗 2024-07-31 04:03:42

gsub() 可以执行此操作并仅返回捕获组：

但是，为了使其正常工作，您必须显式选择捕获组之外的元素，如 gsub() 帮助中所述。

(...) 字符向量“x”中未被替换的元素将原封不动地返回。

因此，如果要选择的文本位于某个字符串的中间，则在捕获组之前和之后添加 .* 应该允许您只返回它。

gsub(".*\\((.*?) :: (0\\.[0-9]+)\\).*","\\1 \\2", "(sometext : : 0.1231313213)")
[1]“某个文本0.1231313213”

gsub() can do this and return only the capture group:

However, in order for this to work, you must explicitly select elements outside your capture group as mentioned in the gsub() help.

(...) elements of character vectors 'x' which are not substituted will be returned unchanged.

So if your text to be selected lies in the middle of some string, adding .* before and after the capture group should allow you to only return it.

gsub(".*\\((.*?) :: (0\\.[0-9]+)\\).*","\\1 \\2", "(sometext :: 0.1231313213)")
[1] "sometext 0.1231313213"

回复 原文
诗笺 2024-07-31 04:03:42

使用 utils 中的 strcapture 解决方案：

x <- c("key1 :: 0.01",
       "key2 :: 0.02")
strcapture(pattern = "(.*) :: (0\\.[0-9]+)",
           x = x,
           proto = list(key = character(), value = double()))
#>    key value
#> 1 key1  0.01
#> 2 key2  0.02

Solution with strcapture from the utils:

x <- c("key1 :: 0.01",
       "key2 :: 0.02")
strcapture(pattern = "(.*) :: (0\\.[0-9]+)",
           x = x,
           proto = list(key = character(), value = double()))
#>    key value
#> 1 key1  0.01
#> 2 key2  0.02
回复 原文
恰似旧人归 2024-07-31 04:03:42

这就是我最终解决这个问题的方法。 我使用两个单独的正则表达式来匹配第一个和第二个捕获组，并运行两个 gregexpr 调用，然后提取匹配的子字符串：

regex.string <- "(?<=\\().*?(?= :: )"
regex.number <- "(?<= :: )\\d\\.\\d+"

match.string <- gregexpr(regex.string, str, perl=T)[[1]]
match.number <- gregexpr(regex.number, str, perl=T)[[1]]

strings <- mapply(function (start, len) substr(str, start, start+len-1),
                  match.string,
                  attr(match.string, "match.length"))
numbers <- mapply(function (start, len) as.numeric(substr(str, start, start+len-1)),
                  match.number,
                  attr(match.number, "match.length"))

This is how I ended up working around this problem. I used two separate regexes to match the first and second capture groups and run two gregexpr calls, then pull out the matched substrings:

regex.string <- "(?<=\\().*?(?= :: )"
regex.number <- "(?<= :: )\\d\\.\\d+"

match.string <- gregexpr(regex.string, str, perl=T)[[1]]
match.number <- gregexpr(regex.number, str, perl=T)[[1]]

strings <- mapply(function (start, len) substr(str, start, start+len-1),
                  match.string,
                  attr(match.string, "match.length"))
numbers <- mapply(function (start, len) as.numeric(substr(str, start, start+len-1)),
                  match.number,
                  attr(match.number, "match.length"))
回复 原文
影子的影子 2024-07-31 04:03:42

我喜欢 Perl 兼容的正则表达式。 可能其他人也这样做...

这是一个函数，它执行 perl 兼容的正则表达式，并与我习惯的其他语言中的函数功能相匹配：

regexpr_perl <- function(expr, str) {
  match <- regexpr(expr, str, perl=T)
  matches <- character(0)
  if (attr(match, 'match.length') >= 0) {
    capture_start <- attr(match, 'capture.start')
    capture_length <- attr(match, 'capture.length')
    total_matches <- 1 + length(capture_start)
    matches <- character(total_matches)
    matches[1] <- substr(str, match, match + attr(match, 'match.length') - 1)
    if (length(capture_start) > 1) {
      for (i in 1:length(capture_start)) {
        matches[i + 1] <- substr(str, capture_start[[i]], capture_start[[i]] + capture_length[[i]] - 1)
      }
    }
  }
  matches
}

I like perl compatible regular expressions. Probably someone else does too...

Here is a function that does perl compatible regular expressions and matches the functionality of functions in other languages that I am used to:

regexpr_perl <- function(expr, str) {
  match <- regexpr(expr, str, perl=T)
  matches <- character(0)
  if (attr(match, 'match.length') >= 0) {
    capture_start <- attr(match, 'capture.start')
    capture_length <- attr(match, 'capture.length')
    total_matches <- 1 + length(capture_start)
    matches <- character(total_matches)
    matches[1] <- substr(str, match, match + attr(match, 'match.length') - 1)
    if (length(capture_start) > 1) {
      for (i in 1:length(capture_start)) {
        matches[i + 1] <- substr(str, capture_start[[i]], capture_start[[i]] + capture_length[[i]] - 1)
      }
    }
  }
  matches
}
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闻呓 2024-07-31 04:03:42

正如 stringr 中所建议的包，这可以使用 str_match() 或 str_extract() 来实现。

改编自手册：

library(stringr)

strings <- c(" 219 733 8965", "329-293-8753 ", "banana", 
             "239 923 8115 and 842 566 4692",
             "Work: 579-499-7527", "$1000",
             "Home: 543.355.3679")
phone <- "([2-9][0-9]{2})[- .]([0-9]{3})[- .]([0-9]{4})"

提取并组合我们的组：

str_extract_all(strings, phone, simplify=T)
#      [,1]           [,2]          
# [1,] "219 733 8965" ""            
# [2,] "329-293-8753" ""            
# [3,] ""             ""            
# [4,] "239 923 8115" "842 566 4692"
# [5,] "579-499-7527" ""            
# [6,] ""             ""            
# [7,] "543.355.3679" ""

用输出矩阵指示组（我们对第 2+ 列感兴趣）：

str_match_all(strings, phone)
# [[1]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "219 733 8965" "219" "733" "8965"
# 
# [[2]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "329-293-8753" "329" "293" "8753"
# 
# [[3]]
#      [,1] [,2] [,3] [,4]
# 
# [[4]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "239 923 8115" "239" "923" "8115"
# [2,] "842 566 4692" "842" "566" "4692"
# 
# [[5]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "579-499-7527" "579" "499" "7527"
# 
# [[6]]
#      [,1] [,2] [,3] [,4]
# 
# [[7]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "543.355.3679" "543" "355" "3679"

As suggested in the stringr package, this can be achieved using either str_match() or str_extract().

Adapted from the manual:

library(stringr)

strings <- c(" 219 733 8965", "329-293-8753 ", "banana", 
             "239 923 8115 and 842 566 4692",
             "Work: 579-499-7527", "$1000",
             "Home: 543.355.3679")
phone <- "([2-9][0-9]{2})[- .]([0-9]{3})[- .]([0-9]{4})"

Extracting and combining our groups:

str_extract_all(strings, phone, simplify=T)
#      [,1]           [,2]          
# [1,] "219 733 8965" ""            
# [2,] "329-293-8753" ""            
# [3,] ""             ""            
# [4,] "239 923 8115" "842 566 4692"
# [5,] "579-499-7527" ""            
# [6,] ""             ""            
# [7,] "543.355.3679" ""

Indicating groups with an output matrix (we're interested in columns 2+):

str_match_all(strings, phone)
# [[1]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "219 733 8965" "219" "733" "8965"
# 
# [[2]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "329-293-8753" "329" "293" "8753"
# 
# [[3]]
#      [,1] [,2] [,3] [,4]
# 
# [[4]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "239 923 8115" "239" "923" "8115"
# [2,] "842 566 4692" "842" "566" "4692"
# 
# [[5]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "579-499-7527" "579" "499" "7527"
# 
# [[6]]
#      [,1] [,2] [,3] [,4]
# 
# [[7]]
#      [,1]           [,2]  [,3]  [,4]  
# [1,] "543.355.3679" "543" "355" "3679"
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留蓝 2024-07-31 04:03:42

这可以使用包 unglue 来完成，以所选答案中的示例为例：

# install.packages("unglue")
library(unglue)

s <- c("(sometext :: 0.1231313213)", "(moretext :: 0.111222)")
unglue_data(s, "({x} :: {y})")
#>          x            y
#> 1 sometext 0.1231313213
#> 2 moretext     0.111222

或者从数据帧开始，

df <- data.frame(col = s)
unglue_unnest(df, col, "({x} :: {y})",remove = FALSE)
#>                          col        x            y
#> 1 (sometext :: 0.1231313213) sometext 0.1231313213
#> 2     (moretext :: 0.111222) moretext     0.111222

您可以从 unglue 模式中获取原始正则表达式，可以选择使用命名捕获：

unglue_regex("({x} :: {y})")
#>             ({x} :: {y}) 
#> "^\\((.*?) :: (.*?)\\)$"

unglue_regex("({x} :: {y})",named_capture = TRUE)
#>                     ({x} :: {y}) 
#> "^\\((?<x>.*?) :: (?<y>.*?)\\)$"

更多信息：< a href="https://github.com/moodymudskipper/unglue/blob/master/README.md" rel="nofollow noreferrer">https://github.com/moodymudskipper/unglue/blob/master/README.md

This can be done using the package unglue, taking the example from the selected answer:

# install.packages("unglue")
library(unglue)

s <- c("(sometext :: 0.1231313213)", "(moretext :: 0.111222)")
unglue_data(s, "({x} :: {y})")
#>          x            y
#> 1 sometext 0.1231313213
#> 2 moretext     0.111222

Or starting from a data frame

df <- data.frame(col = s)
unglue_unnest(df, col, "({x} :: {y})",remove = FALSE)
#>                          col        x            y
#> 1 (sometext :: 0.1231313213) sometext 0.1231313213
#> 2     (moretext :: 0.111222) moretext     0.111222

you can get the raw regex from the unglue pattern, optionally with named capture :

unglue_regex("({x} :: {y})")
#>             ({x} :: {y}) 
#> "^\\((.*?) :: (.*?)\\)$"

unglue_regex("({x} :: {y})",named_capture = TRUE)
#>                     ({x} :: {y}) 
#> "^\\((?<x>.*?) :: (?<y>.*?)\\)$"

More info : https://github.com/moodymudskipper/unglue/blob/master/README.md

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