警告:内置函数“xyz”不兼容的隐式声明;
在编译一些二进制文件时,我收到了许多这样的警告:
warning: incompatible implicit declaration of built-in function ‘strcpy’
warning: incompatible implicit declaration of built-in function ‘strlen’
warning: incompatible implicit declaration of built-in function ‘exit’
添加了
#include <stdlib.h>
为了尝试解决这个问题,除了使用以下标志进行编译之外,我还在与此警告相关的 C 文件的顶部
CFLAGS = -fno-builtin-exit -fno-builtin-strcat -fno-builtin-strncat -fno-builtin-strcpy -fno-builtin-strlen -fno-builtin-calloc
:我正在使用 GCC 4.1 .2:
$ gcc --version
gcc (GCC) 4.1.2 20080704
我应该怎么做才能解决这些警告?
I'm getting a number of these warnings when compiling a few binaries:
warning: incompatible implicit declaration of built-in function ‘strcpy’
warning: incompatible implicit declaration of built-in function ‘strlen’
warning: incompatible implicit declaration of built-in function ‘exit’
To try to resolve this, I have added
#include <stdlib.h>
at the top of the C files associated with this warning, in addition to compiling with the following flags:
CFLAGS = -fno-builtin-exit -fno-builtin-strcat -fno-builtin-strncat -fno-builtin-strcpy -fno-builtin-strlen -fno-builtin-calloc
I am using GCC 4.1.2:
$ gcc --version
gcc (GCC) 4.1.2 20080704
What should I do to resolve these warnings?
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对于某些程序,这些错误是正常的,不应修复。
我在编译程序 phrap 时收到这些错误消息(例如)。 该程序恰好包含修改或替换某些内置函数的代码,当我包含适当的头文件来修复警告时,GCC 相反会生成一堆错误。 因此修复警告会有效地破坏构建。
如果您将源代码作为应该正常编译的发行版的一部分来获取,则错误可能是正常的。 请查阅文档以确定。
In the case of some programs, these errors are normal and should not be fixed.
I get these error messages when compiling the program phrap (for example). This program happens to contain code that modifies or replaces some built in functions, and when I include the appropriate header files to fix the warnings, GCC instead generates a bunch of errors. So fixing the warnings effectively breaks the build.
If you got the source as part of a distribution that should compile normally, the errors might be normal. Consult the documentation to be sure.
在 C 中,使用先前未声明的函数构成该函数的隐式声明。 如果我没记错的话,在隐式声明中,返回类型是 int 。 现在,GCC 已经内置了一些标准函数的定义。 如果隐式声明与内置定义不匹配,您会收到此警告。
要解决这个问题,您必须在使用函数之前声明它们; 通常,您可以通过包含适当的标头来完成此操作。 如果可能的话,我建议不要使用
-fno-builtin-*
标志。您应该尝试而不是 stdlib.h:
这是定义
strcpy
和strncpy
的地方,至少根据strcpy
代码>(2) 手册页。不过,
exit
函数是在 stdlib.h 中定义的,所以我不知道那里发生了什么。In C, using a previously undeclared function constitutes an implicit declaration of the function. In an implicit declaration, the return type is
int
if I recall correctly. Now, GCC has built-in definitions for some standard functions. If an implicit declaration does not match the built-in definition, you get this warning.To fix the problem, you have to declare the functions before using them; normally you do this by including the appropriate header. I recommend not to use the
-fno-builtin-*
flags if possible.Instead of stdlib.h, you should try:
That's where
strcpy
andstrncpy
are defined, at least according to thestrcpy
(2) man page.The
exit
function is defined in stdlib.h, though, so I don't know what's going on there.这里是一些产生上述错误的 C 代码:
在 Fedora 17 Linux 64 位上使用 gcc 进行编译:
要使警告消失,请将此声明添加到文件顶部:
Here is some C code that produces the above mentioned error:
Compiled like this on Fedora 17 Linux 64 bit with gcc:
To make the warning go away, add this declaration to the top of the file:
我在
mempcpy
函数上遇到了这些警告。 手册页说这个函数是一个 GNU 扩展,概要显示:当
#define
在#include
之前添加到我的源代码时,GNU 扩展的声明变得可见并发出警告消失。I met these warnings on
mempcpy
function. Man page says this function is a GNU extension and synopsis shows:When
#define
is added to my source before the#include
, declarations for the GNU extensions are made visible and warnings disappear.