是否有任何 C# 按位移位运算符可以将溢出位移动到变量的另一端？
我们称之为“<<<”
int32variable <<< numberOfBits
equals
(int32variable << numberOfBits) | (int32variable >> (32 - numberOfBits))
（假设<<和>>丢弃溢出位）
有这样的运算符吗？
Let's call it "<<<"
int32variable <<< numberOfBits
equals
(int32variable << numberOfBits) | (int32variable >> (32 - numberOfBits))
(Assuming << and >> discards overflown bits)
There is such an operator?
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C# 中没有原始运算符可以完成您想要的操作。
忽略方法调用的性能影响（如果您正在执行位移操作，您可能会关心），这将是 Int32 上扩展方法的良好候选者。
There is no primitive operator in C# to do what you're looking for.
Ignoring the performance implications of a method call (if you're doing bitshift operations, you might care), this would be a good candidate for an extension method on Int32.
这就是所谓的位旋转，而 C# 没有这样的运算符。
这是一篇有趣的帖子：
有没有办法执行循环C# 中的位移位？
请注意，您的 int32integer 应该是
uint类型（无符号 int）。我相信位旋转是 Intel 指令集中的指令，但据我所知 CLR 没有位旋转指令。
That would be a called a bit rotate and C# does not have such an operator.
Here's an interesting post:
Is there a way to perform a circular bit shift in C#?
Note that your int32integer should be of type
uint(unsigned int).I believe bit rotate is an instructions in the Intel instruction set but as far as I know the CLR does not have bit rotate instructions.
这称为按位循环。 其他语言有，但C#没有。 有关更多详细信息，请参阅此问题，但其要点是你目前的方法已经是你能做的最好的了。
This is called a bitwise rotation. Other languages have it, but C# does not. See this question for a little more detail, but the gist of it is that your current approach is about as good as you can do.
我认为 C# 没有。 请参阅此页面以获取 C# 运算符列表：http:// /msdn.microsoft.com/en-us/library/6a71f45d(vs.71).aspx。
我认为您在问题中所展示的方式可能是最快的方法。 我认为 Java 可能有一个像您所追求的那样的移位运算符，但作为一名 Java 程序员，我无法证实这一点。
I don't think that there is for C#. See this page for the list of C# operators: http://msdn.microsoft.com/en-us/library/6a71f45d(vs.71).aspx.
I think that they way you have shown in your question is probably the quickest way to do it. I think that Java may have a shift operator like the one you are after, but not being a Java programer I can't confirm that.