有选择地仅对部分翻译单元禁用 GCC 警告
与此 MSVC 预处理器代码最接近的 GCC 等效项是什么？
#pragma warning( push ) // Save the current warning state.
#pragma warning( disable : 4723 ) // C4723: potential divide by 0
// Code which would generate warning 4723.
#pragma warning( pop ) // Restore warnings to previous state.
我们在通常包含的标头中有代码，但我们不希望为其生成特定警告。 但是，我们希望包含这些标头的文件继续生成该警告（如果项目启用了该警告）。
What's the closest GCC equivalent to this MSVC preprocessor code?
#pragma warning( push ) // Save the current warning state.
#pragma warning( disable : 4723 ) // C4723: potential divide by 0
// Code which would generate warning 4723.
#pragma warning( pop ) // Restore warnings to previous state.
We have code in commonly included headers which we do not want to generate a specific warning for. However, we want files which include those headers to continue to generate that warning (if the project has that warning enabled).
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最接近的是 GCC 诊断编译指示，
#pragma GCC诊断[警告|错误|忽略]“-无论什么”。 它与您想要的不太接近，请参阅链接以获取详细信息和注意事项。The closest thing is the GCC diagnostic pragma,
#pragma GCC diagnostic [warning|error|ignored] "-Wwhatever". It isn't very close to what you want, and see the link for details and caveats.我也做过类似的事情。 对于第三方代码，我根本不想看到任何警告。 因此，我没有指定 -I/path/to/libfoo/include ，而是使用了 -isystem /path/to/libfoo/include 。 这使得编译器将这些头文件视为“系统头文件”以用于警告目的，并且只要您不启用
-Wsystem-headers，您就基本上是安全的。 我仍然看到一些警告从那里泄漏出来，但它减少了大部分垃圾。请注意，只有当您可以通过包含目录隔离有问题的代码时，这才会对您有所帮助。 如果它只是您自己项目的子集，或者与其他代码混合，那么您就不走运了。
I've done something similar. For third-party code, I didn't want to see any warnings at all. So, rather than specify
-I/path/to/libfoo/include, I used-isystem /path/to/libfoo/include. This makes the compiler treat those header files as "system headers" for the purpose of warnings, and so long as you don't enable-Wsystem-headers, you're mostly safe. I've still seen a few warnings leak out of there, but it cuts down on most of the junk.Note that this only helps you if you can isolate the offending code by include-directory. If it's just a subset of your own project, or intermixed with other code, you're out of luck.
这是对Matt Joiner 的答案的扩展。
如果您不想在代码中生成编译指示，可以使用 _Pragma 运算符：
This is an expansion to Matt Joiner's answer.
If you don't want to spawn pragmas all over your code, you can use the _Pragma operator: