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如何使用 PHP 检查远程文件是否存在？

发布于 2024-07-23 06:34:51 字数 170 浏览 7 评论 0原文

我能找到的最好的，一个 if fclose fopen 类型的东西，使得页面加载非常慢。

基本上我想做的是：我有一个网站列表，我想在它们旁边显示它们的图标。但是，如果网站没有，我想用另一张图像替换它，而不是显示损坏的图像。

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评论（24）

一直在等你来 2024-07-30 06:34:51

您可以通过 CURLOPT_NOBODY 指示curl 使用HTTP HEAD 方法。

或多或少

$ch = curl_init("http://www.example.com/favicon.ico");

curl_setopt($ch, CURLOPT_NOBODY, true);
curl_exec($ch);
$retcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
// $retcode >= 400 -> not found, $retcode = 200, found.
curl_close($ch);

无论如何，你只节省了HTTP传输的成本，而不是TCP连接建立和关闭的成本。由于网站图标很小，您可能看不到太大的改进。

如果结果太慢，在本地缓存结果似乎是个好主意。
HEAD 检查文件的时间，并将其返回到标头中。你可以像浏览器一样获取图标的CURLINFO_FILETIME。
您可以在缓存中存储 URL => [ 网站图标、时间戳 ]。然后您可以比较时间戳并重新加载图标。

You can instruct curl to use the HTTP HEAD method via CURLOPT_NOBODY.

More or less

$ch = curl_init("http://www.example.com/favicon.ico");

curl_setopt($ch, CURLOPT_NOBODY, true);
curl_exec($ch);
$retcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
// $retcode >= 400 -> not found, $retcode = 200, found.
curl_close($ch);

Anyway, you only save the cost of the HTTP transfer, not the TCP connection establishment and closing. And being favicons small, you might not see much improvement.

Caching the result locally seems a good idea if it turns out to be too slow.
HEAD checks the time of the file, and returns it in the headers. You can do like browsers and get the CURLINFO_FILETIME of the icon.
In your cache you can store the URL => [ favicon, timestamp ]. You can then compare the timestamp and reload the favicon.

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兮子 2024-07-30 06:34:51

正如 Pies 所说，您可以使用 cURL。您可以让 cURL 只提供标题，而不提供正文，这可能会使其速度更快。坏域名可能总是需要一段时间，因为您将等待请求超时；您可以使用 cURL 更改超时长度。

这是示例：

function remoteFileExists($url) {
    $curl = curl_init($url);

    //don't fetch the actual page, you only want to check the connection is ok
    curl_setopt($curl, CURLOPT_NOBODY, true);

    //do request
    $result = curl_exec($curl);

    $ret = false;

    //if request did not fail
    if ($result !== false) {
        //if request was ok, check response code
        $statusCode = curl_getinfo($curl, CURLINFO_HTTP_CODE);  

        if ($statusCode == 200) {
            $ret = true;   
        }
    }

    curl_close($curl);

    return $ret;
}

$exists = remoteFileExists('http://stackoverflow.com/favicon.ico');
if ($exists) {
    echo 'file exists';
} else {
    echo 'file does not exist';   
}

As Pies say you can use cURL. You can get cURL to only give you the headers, and not the body, which might make it faster. A bad domain could always take a while because you will be waiting for the request to time-out; you could probably change the timeout length using cURL.

Here is example:

function remoteFileExists($url) {
    $curl = curl_init($url);

    //don't fetch the actual page, you only want to check the connection is ok
    curl_setopt($curl, CURLOPT_NOBODY, true);

    //do request
    $result = curl_exec($curl);

    $ret = false;

    //if request did not fail
    if ($result !== false) {
        //if request was ok, check response code
        $statusCode = curl_getinfo($curl, CURLINFO_HTTP_CODE);  

        if ($statusCode == 200) {
            $ret = true;   
        }
    }

    curl_close($curl);

    return $ret;
}

$exists = remoteFileExists('http://stackoverflow.com/favicon.ico');
if ($exists) {
    echo 'file exists';
} else {
    echo 'file does not exist';   
}

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转身以后 2024-07-30 06:34:51

CoolGoose 的解决方案很好，但对于大文件来说速度更快（因为它只尝试读取 1 个字节）：

if (false === file_get_contents("http://example.com/path/to/image",0,null,0,1)) {
    $image = $default_image;
}

CoolGoose's solution is good but this is faster for large files (as it only tries to read 1 byte):

if (false === file_get_contents("http://example.com/path/to/image",0,null,0,1)) {
    $image = $default_image;
}

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红ご颜醉 2024-07-30 06:34:51

这不是对您最初问题的答案，而是一种更好的方法来完成您想要做的事情：

而不是实际尝试直接获取网站的图标（这是一个巨大的痛苦，因为它可能是 /favicon.png，/ favicon.ico、/favicon.gif，甚至 /path/to/favicon.png），使用 google：

<img src="http://www.google.com/s2/favicons?domain=[domain]">

完成。

This is not an answer to your original question, but a better way of doing what you're trying to do:

Instead of actually trying to get the site's favicon directly (which is a royal pain given it could be /favicon.png, /favicon.ico, /favicon.gif, or even /path/to/favicon.png), use google:

<img src="http://www.google.com/s2/favicons?domain=[domain]">

Done.

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￡冰雨忧蓝° 2024-07-30 06:34:51

得票最多的答案的完整功能：

function remote_file_exists($url)
{
    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_NOBODY, 1);
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); # handles 301/2 redirects
    curl_exec($ch);
    $httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
    curl_close($ch);
    if( $httpCode == 200 ){return true;}
}

您可以这样使用它：

if(remote_file_exists($url))
{
    //file exists, do something
}

A complete function of the most voted answer:

function remote_file_exists($url)
{
    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_NOBODY, 1);
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); # handles 301/2 redirects
    curl_exec($ch);
    $httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
    curl_close($ch);
    if( $httpCode == 200 ){return true;}
}

You can use it like this:

if(remote_file_exists($url))
{
    //file exists, do something
}

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北城孤痞 2024-07-30 06:34:51

如果您正在处理图像，请使用 getimagesize。与 file_exists 不同，此内置函数支持远程文件。它将返回一个包含图像信息（宽度、高度、类型等）的数组。您所要做的就是检查数组中的第一个元素（宽度）。使用 print_r 输出数组的内容

$imageArray = getimagesize("http://www.example.com/image.jpg");
if($imageArray[0])
{
    echo "it's an image and here is the image's info<br>";
    print_r($imageArray);
}
else
{
    echo "invalid image";
}

If you are dealing with images, use getimagesize. Unlike file_exists, this built-in function supports remote files. It will return an array that contains the image information (width, height, type..etc). All you have to do is to check the first element in the array (the width). use print_r to output the content of the array

$imageArray = getimagesize("http://www.example.com/image.jpg");
if($imageArray[0])
{
    echo "it's an image and here is the image's info<br>";
    print_r($imageArray);
}
else
{
    echo "invalid image";
}

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梦回旧景 2024-07-30 06:34:51

如果出于安全原因将 allow_url_fopen 设置设置为关闭，PHP 的内置函数可能无法检查 URL。 Curl 是一个更好的选择，因为我们以后不需要更改代码阶段。下面是我用来验证有效 URL 的代码：

$url = str_replace(' ', '%20', $url);
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); 
curl_setopt($ch, CURLOPT_NOBODY, true);
curl_exec($ch);
$httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);  
curl_close($ch);
if($httpcode>=200 && $httpcode<300){  return true; } else { return false; }

请注意 CURLOPT_SSL_VERIFYPEER 选项，该选项还验证 URL 是否以 HTTPS 开头。

PHP's inbuilt functions may not work for checking URL if allow_url_fopen setting is set to off for security reasons. Curl is a better option as we would not need to change our code at later stage. Below is the code I used to verify a valid URL:

$url = str_replace(' ', '%20', $url);
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); 
curl_setopt($ch, CURLOPT_NOBODY, true);
curl_exec($ch);
$httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);  
curl_close($ch);
if($httpcode>=200 && $httpcode<300){  return true; } else { return false; }

Kindly note the CURLOPT_SSL_VERIFYPEER option which also verify the URL's starting with HTTPS.

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夢归不見 2024-07-30 06:34:51

if (false === file_get_contents("http://example.com/path/to/image")) {
    $image = $default_image;
}

应该管用 ;）

if (false === file_get_contents("http://example.com/path/to/image")) {
    $image = $default_image;
}

Should work ;)

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汐鸠 2024-07-30 06:34:51

这可以通过获取 HTTP 状态代码（404 = 未找到）来完成，可以使用 file_get_contents^文档使用上下文选项。以下代码考虑了重定向，并将返回最终目的地的状态代码（演示）：

$url = 'http://example.com/';
$code = FALSE;

$options['http'] = array(
    'method' => "HEAD",
    'ignore_errors' => 1
);

$body = file_get_contents($url, NULL, stream_context_create($options));

foreach($http_response_header as $header)
    sscanf($header, 'HTTP/%*d.%*d %d', $code);

echo "Status code: $code";

如果您不这样做想要跟随重定向，你可以这样做类似（演示）：

$url = 'http://example.com/';
$code = FALSE;

$options['http'] = array(
    'method' => "HEAD",
    'ignore_errors' => 1,
    'max_redirects' => 0
);

$body = file_get_contents($url, NULL, stream_context_create($options));

sscanf($http_response_header[0], 'HTTP/%*d.%*d %d', $code);

echo "Status code: $code";

解释了一些正在使用的函数、选项和变量我写的博客文章中有更多详细信息： HEAD First with PHP Streams 。

This can be done by obtaining the HTTP Status code (404 = not found) which is possible with file_get_contents^Docs making use of context options. The following code takes redirects into account and will return the status code of the final destination (Demo):

$url = 'http://example.com/';
$code = FALSE;

$options['http'] = array(
    'method' => "HEAD",
    'ignore_errors' => 1
);

$body = file_get_contents($url, NULL, stream_context_create($options));

foreach($http_response_header as $header)
    sscanf($header, 'HTTP/%*d.%*d %d', $code);

echo "Status code: $code";

If you don't want to follow redirects, you can do it similar (Demo):

$url = 'http://example.com/';
$code = FALSE;

$options['http'] = array(
    'method' => "HEAD",
    'ignore_errors' => 1,
    'max_redirects' => 0
);

$body = file_get_contents($url, NULL, stream_context_create($options));

sscanf($http_response_header[0], 'HTTP/%*d.%*d %d', $code);

echo "Status code: $code";

Some of the functions, options and variables in use are explained with more detail on a blog post I've written: HEAD first with PHP Streams.

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︶￣淡然 2024-07-30 06:34:51

要检查图像是否存在，exif_imagetype 应该优于 getimagesize，因为它更快。

要抑制 E_NOTICE，只需在前面添加错误控制运算符 (@)。

if (@exif_imagetype($filename)) {
  // Image exist
}

作为奖励，通过 exif_imagetype 返回的值 (IMAGETYPE_XXX)，我们还可以通过 image_type_to_mime_type / < 获取 mime 类型或文件扩展名代码>image_type_to_extension。

To check for the existence of images, exif_imagetype should be preferred over getimagesize, as it is much faster.

To suppress the E_NOTICE, just prepend the error control operator (@).

if (@exif_imagetype($filename)) {
  // Image exist
}

As a bonus, with the returned value (IMAGETYPE_XXX) from exif_imagetype we could also get the mime-type or file-extension with image_type_to_mime_type / image_type_to_extension.

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栀子花开つ 2024-07-30 06:34:51

一个彻底的解决方案是将图标显示为默认图标上方 div 中的背景图像。这样，所有开销都将放在客户端上，同时仍然不会显示损坏的图像（据我所知，所有浏览器都会忽略缺少的背景图像）。

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回心转意 2024-07-30 06:34:51

您可以使用以下内容：

$file = 'http://mysite.co.za/images/favicon.ico';
$file_exists = (@fopen($file, "r")) ? true : false;

在尝试检查 URL 上是否存在图像时为我工作

You could use the following:

$file = 'http://mysite.co.za/images/favicon.ico';
$file_exists = (@fopen($file, "r")) ? true : false;

Worked for me when trying to check if an image exists on the URL

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辞旧 2024-07-30 06:34:51

function remote_file_exists($url){
   return(bool)preg_match('~HTTP/1\.\d\s+200\s+OK~', @current(get_headers($url)));
}  
$ff = "http://www.emeditor.com/pub/emed32_11.0.5.exe";
    if(remote_file_exists($ff)){
        echo "file exist!";
    }
    else{
        echo "file not exist!!!";
    }

function remote_file_exists($url){
   return(bool)preg_match('~HTTP/1\.\d\s+200\s+OK~', @current(get_headers($url)));
}  
$ff = "http://www.emeditor.com/pub/emed32_11.0.5.exe";
    if(remote_file_exists($ff)){
        echo "file exist!";
    }
    else{
        echo "file not exist!!!";
    }

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嘿嘿嘿 2024-07-30 06:34:51

这对我来说可以检查 PHP 中是否存在远程文件：

$url = 'https://cdn.sstatic.net/Sites/stackoverflow/img/favicon.ico';
    $header_response = get_headers($url, 1);

    if ( strpos( $header_response[0], "404" ) !== false ) {
        echo 'File does NOT exist';
        } else {
        echo 'File exists';
        }

This works for me to check if a remote file exist in PHP:

$url = 'https://cdn.sstatic.net/Sites/stackoverflow/img/favicon.ico';
    $header_response = get_headers($url, 1);

    if ( strpos( $header_response[0], "404" ) !== false ) {
        echo 'File does NOT exist';
        } else {
        echo 'File exists';
        }

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你怎么这么可爱啊 2024-07-30 06:34:51

您可以使用：

$url=getimagesize(“http://www.flickr.com/photos/27505599@N07/2564389539/”);

if(!is_array($url))
{
   $default_image =”…/directoryFolder/junal.jpg”;
}

You can use :

$url=getimagesize(“http://www.flickr.com/photos/27505599@N07/2564389539/”);

if(!is_array($url))
{
   $default_image =”…/directoryFolder/junal.jpg”;
}

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心碎的声音 2024-07-30 06:34:51

如果您使用 Laravel 框架或 guzzle 包，还有一种使用 guzzle 客户端的更简单的方法，它在链接重定向时也可以工作：

$client = new \GuzzleHttp\Client(['allow_redirects' => ['track_redirects' => true]]);
try {
    $response = $client->request('GET', 'your/url');
    if ($response->getStatusCode() != 200) {
        // not exists
    }
} catch (\GuzzleHttp\Exception\GuzzleException $e) {
    // not exists
}

文档中的更多内容： https://docs.guzzlephp.org/en/latest/faq.html#how-can- i-track-redirected-requests

If you're using the Laravel framework or guzzle package, there is also a much simpler way using the guzzle client, it also works when links are redirected:

$client = new \GuzzleHttp\Client(['allow_redirects' => ['track_redirects' => true]]);
try {
    $response = $client->request('GET', 'your/url');
    if ($response->getStatusCode() != 200) {
        // not exists
    }
} catch (\GuzzleHttp\Exception\GuzzleException $e) {
    // not exists
}

More in Document : https://docs.guzzlephp.org/en/latest/faq.html#how-can-i-track-redirected-requests

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沩ん囻菔务 2024-07-30 06:34:51

您应该发出 HEAD 请求，而不是 GET 请求，因为您根本不需要 URI 内容。正如 Pies 上面所说，您应该检查状态代码（在 200-299 范围内，并且您可以选择遵循 3xx 重定向）。

答案问题包含很多可能有用的代码示例：PHP / Curl：HEAD 请求在某些网站上需要很长时间

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不忘初心 2024-07-30 06:34:51

还有一个更复杂的替代方案。您可以使用 JQuery 技巧来检查所有客户端。

$('a[href^="http://"]').filter(function(){
     return this.hostname && this.hostname !== location.hostname;
}).each(function() {
    var link = jQuery(this);
    var faviconURL =
      link.attr('href').replace(/^(http:\/\/[^\/]+).*$/, '$1')+'/favicon.ico';
    var faviconIMG = jQuery('<img src="favicon.png" alt="" />')['appendTo'](link);
    var extImg = new Image();
    extImg.src = faviconURL;
    if (extImg.complete)
      faviconIMG.attr('src', faviconURL);
    else
      extImg.onload = function() { faviconIMG.attr('src', faviconURL); };
});

来自 http://snipplr.com/ view/18782/add-a-favicon-near-external-links-with-jquery/（原始博客目前已关闭）

There's an even more sophisticated alternative. You can do the checking all client-side using a JQuery trick.

$('a[href^="http://"]').filter(function(){
     return this.hostname && this.hostname !== location.hostname;
}).each(function() {
    var link = jQuery(this);
    var faviconURL =
      link.attr('href').replace(/^(http:\/\/[^\/]+).*$/, '$1')+'/favicon.ico';
    var faviconIMG = jQuery('<img src="favicon.png" alt="" />')['appendTo'](link);
    var extImg = new Image();
    extImg.src = faviconURL;
    if (extImg.complete)
      faviconIMG.attr('src', faviconURL);
    else
      extImg.onload = function() { faviconIMG.attr('src', faviconURL); };
});

From http://snipplr.com/view/18782/add-a-favicon-near-external-links-with-jquery/ (the original blog is presently down)

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三生池水覆流年 2024-07-30 06:34:51

这里所有使用 get_headers() 的答案都在执行 GET 请求。
仅执行 HEAD 请求会更快/更便宜。

为了确保 get_headers() 执行 HEAD 请求而不是 GET，您应该添加以下内容：

stream_context_set_default(
    array(
        'http' => array(
            'method' => 'HEAD'
        )
    )
);

因此，要检查文件是否存在，您的代码将如下所示：

stream_context_set_default(
    array(
        'http' => array(
            'method' => 'HEAD'
        )
    )
);
$headers = get_headers('http://website.com/dir/file.jpg', 1);
$file_found = stristr($headers[0], '200');

$file_found 显然将返回 false 或 true。

all the answers here that use get_headers() are doing a GET request.
It's much faster/cheaper to just do a HEAD request.

To make sure that get_headers() does a HEAD request instead of a GET you should add this:

stream_context_set_default(
    array(
        'http' => array(
            'method' => 'HEAD'
        )
    )
);

so to check if a file exists, your code would look something like this:

stream_context_set_default(
    array(
        'http' => array(
            'method' => 'HEAD'
        )
    )
);
$headers = get_headers('http://website.com/dir/file.jpg', 1);
$file_found = stristr($headers[0], '200');

$file_found will return either false or true, obviously.

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潦草背影 2024-07-30 06:34:51

如果文件不是外部托管的，您可以将远程 URL 转换为网络服务器上的绝对路径。这样你就不必调用 CURL 或 file_get_contents 等。

function remoteFileExists($url) {

    $root = realpath($_SERVER["DOCUMENT_ROOT"]);
    $urlParts = parse_url( $url );

    if ( !isset( $urlParts['path'] ) )
        return false;

    if ( is_file( $root . $urlParts['path'] ) )
        return true;
    else
        return false;

}

remoteFileExists( 'https://www.yourdomain.com/path/to/remote/image.png' );

注意：您的网络服务器必须填充 DOCUMENT_ROOT 才能使用此功能

If the file is not hosted external you might translate the remote URL to an absolute Path on your webserver. That way you don't have to call CURL or file_get_contents, etc.

function remoteFileExists($url) {

    $root = realpath($_SERVER["DOCUMENT_ROOT"]);
    $urlParts = parse_url( $url );

    if ( !isset( $urlParts['path'] ) )
        return false;

    if ( is_file( $root . $urlParts['path'] ) )
        return true;
    else
        return false;

}

remoteFileExists( 'https://www.yourdomain.com/path/to/remote/image.png' );

Note: Your webserver must populate DOCUMENT_ROOT to use this function

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倾城花音 2024-07-30 06:34:51

不知道当文件远程不存在时这个是否更快，is_file()，但你可以尝试一下。

$favIcon = 'default FavIcon';
if(is_file($remotePath)) {
   $favIcon = file_get_contents($remotePath);
}

Don't know if this one is any faster when the file does not exist remotely, is_file(), but you could give it a shot.

$favIcon = 'default FavIcon';
if(is_file($remotePath)) {
   $favIcon = file_get_contents($remotePath);
}

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我一向站在原地 2024-07-30 06:34:51

如果您使用 Symfony 框架，还有一种使用 HttpClientInterface 的更简单方法：

private function remoteFileExists(string $url, HttpClientInterface $client): bool {
    $response = $client->request(
        'GET',
        $url //e.g. http://example.com/file.txt
    );

    return $response->getStatusCode() == 200;
}

HttpClient 的文档也非常好，如果您需要更具体的方法，也许值得研究一下：< a href="https://symfony.com/doc/current/http_client.html" rel="nofollow noreferrer">https://symfony.com/doc/current/http_client.html

If you're using the Symfony framework, there is also a much simpler way using the HttpClientInterface:

private function remoteFileExists(string $url, HttpClientInterface $client): bool {
    $response = $client->request(
        'GET',
        $url //e.g. http://example.com/file.txt
    );

    return $response->getStatusCode() == 200;
}

The docs for the HttpClient are also very good and maybe worth looking into if you need a more specific approach: https://symfony.com/doc/current/http_client.html

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若沐 2024-07-30 06:34:51

您可以使用文件系统：
使用 Symfony\Component\Filesystem\Filesystem；
使用 Symfony\Component\Filesystem\Exception\IOExceptionInterface；

并检查
$fileSystem = 新文件系统();
if ($fileSystem->exists('path_to_file')==true) {...

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岁吢 2024-07-30 06:34:51

请检查此网址。我相信它会对你有所帮助。他们提供了两种方法来克服这个问题并进行了一些解释。

试试这个。

// Remote file url
$remoteFile = 'https://www.example.com/files/project.zip';

// Initialize cURL
$ch = curl_init($remoteFile);
curl_setopt($ch, CURLOPT_NOBODY, true);
curl_exec($ch);
$responseCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);

// Check the response code
if($responseCode == 200){
    echo 'File exists';
}else{
    echo 'File not found';
}

或访问 URL

https://www.codexworld.com/how-to/check-if-remote-file-exists-url-php/# :~:text=%20file_exists()%20function%20in,a%20remote%20server%20using%20PHP。

Please check this URL. I believe it will help you. They provide two ways to overcome this with a bit of explanation.

Try this one.

// Remote file url
$remoteFile = 'https://www.example.com/files/project.zip';

// Initialize cURL
$ch = curl_init($remoteFile);
curl_setopt($ch, CURLOPT_NOBODY, true);
curl_exec($ch);
$responseCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);

// Check the response code
if($responseCode == 200){
    echo 'File exists';
}else{
    echo 'File not found';
}

or visit the URL

https://www.codexworld.com/how-to/check-if-remote-file-exists-url-php/#:~:text=The%20file_exists()%20function%20in,a%20remote%20server%20using%20PHP.

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