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替换 JavaScript 中的符号

发布于 2024-07-23 01:45:20 字数 123 浏览 7 评论 0原文

有谁知道如何将下面的这 2 个符号从字符串替换为代码？

'左单引号变为'
'右单引号变为'
"左双引号变为“
”右双引号变为”

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绿萝 2024-07-30 01:45:20

如果您希望万无一失，那么知道引用的方向（左或右）并不容易。如果始终保持正确并不那么重要，您可以使用几个正则表达式：

function curlyQuotes(inp) {
    return inp.replace(/(\b)'/, "$1’")
              .replace(/'(\b)/, "‘$1")
              .replace(/(\b)"/, "$1”")
              .replace(/"(\b)/, "“$1")
}

curlyQuotes("'He said that he was \"busy\"', said O'reilly")
// ‘He said that he was “busy”', said O’reilly

您会发现第二个 ' 没有正确更改。

Knowing which way to make the quotes go (left or right) won't be easy if you want it to be foolproof. If it's not that important to make it exactly right all the time, you could use a couple of regexes:

function curlyQuotes(inp) {
    return inp.replace(/(\b)'/, "$1’")
              .replace(/'(\b)/, "‘$1")
              .replace(/(\b)"/, "$1”")
              .replace(/"(\b)/, "“$1")
}

curlyQuotes("'He said that he was \"busy\"', said O'reilly")
// ‘He said that he was “busy”', said O’reilly

You'll see that the second ' doesn't change properly.

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小镇女孩 2024-07-30 01:45:20

困难的部分是识别撇号，这会扰乱单引号的计数。

对于双引号，我认为找到所有双引号并将奇数替换为左弯引号，偶数替换为右弯引号是安全的。除非你有嵌套引用的情况。

来源是什么？英文文本？代码？

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烙印 2024-07-30 01:45:20

我最近编写了一个名为 jsPrettify 的排版美化引擎，它就是这样做的。这是我使用的算法的仅引号版本（原始此处）：

prettifyStr = function(text) {
  var e = {
    lsquo:  '\u2018',
    rsquo:  '\u2019',
    ldquo:  '\u201c',
    rdquo:  '\u201d',
  };
  var subs = [
    {pattern: "(^|[\\s\"])'",      replace: '$1' + e.lsquo},
    {pattern: '(^|[\\s-])"',       replace: '$1' + e.ldquo},
    {pattern: "'($|[\\s\"])?",     replace: e.rsquo + '$1'},
    {pattern: '"($|[\\s.,;:?!])',  replace: e.rdquo + '$1'}
  ];
  for (var i = 0; i < subs.length; i++) {
    var sub = subs[i];
    var pattern = new RegExp(sub.pattern, 'g');
    text = text.replace(pattern, sub.replace);
  };
  return text;
};

I recently wrote a typography prettification engine called jsPrettify that does just that. Here's a quotes-only version the algorithm I use (original here):

prettifyStr = function(text) {
  var e = {
    lsquo:  '\u2018',
    rsquo:  '\u2019',
    ldquo:  '\u201c',
    rdquo:  '\u201d',
  };
  var subs = [
    {pattern: "(^|[\\s\"])'",      replace: '$1' + e.lsquo},
    {pattern: '(^|[\\s-])"',       replace: '$1' + e.ldquo},
    {pattern: "'($|[\\s\"])?",     replace: e.rsquo + '$1'},
    {pattern: '"($|[\\s.,;:?!])',  replace: e.rdquo + '$1'}
  ];
  for (var i = 0; i < subs.length; i++) {
    var sub = subs[i];
    var pattern = new RegExp(sub.pattern, 'g');
    text = text.replace(pattern, sub.replace);
  };
  return text;
};

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