在Django管理中，如何按组过滤用户？

发布于 2024-07-21 03:03:36 字数 34 浏览 3 评论 0原文

它可以让您按员工状态和超级用户状态进行过滤，但是组呢？

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伊面 2024-07-28 03:03:36

从版本 1.3 开始，可以使用使用this：

list_filter = ('groups__name')

当然，正如 @S.Lott 所解释的，您必须在 admin.py 文件中注册您的自定义类：

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class MyUserAdmin(UserAdmin):
    list_filter = UserAdmin.list_filter + ('groups__name',)

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

Since version 1.3 it can be done using this:

list_filter = ('groups__name')

Of course as @S.Lott explains you must register your customized class in the admin.py file:

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class MyUserAdmin(UserAdmin):
    list_filter = UserAdmin.list_filter + ('groups__name',)

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

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拧巴小姐 2024-07-28 03:03:36

请参阅在 Django 中自定义管理表单，同时还使用自动发现< /a>

本质上，您可以使用您想要的功能定义自定义的 Admin 类。

然后注销并注册您修改后的 Admin 类。

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

See Customizing an Admin form in Django while also using autodiscover

Essentially, you define a customized Admin class with the features you want.

Then unregister and register your revised Admin class.

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

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无边思念无边月 2024-07-28 03:03:36

下面是一个完整的示例，它继承自 SimpleListFilter，它在 Django 1.4 及更高版本中可用（截至 2023 年 5 月）：

https://docs.djangoproject.com/en/4.2/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_filter

它支持设置所有可用的标签和参数来创建完全自定义的过滤器。

它在过滤器面板中显示为“按组”，并包含所有可用组的列表。

from django.contrib.admin import SimpleListFilter
from django.contrib.auth.models import Group
from django.utils.translation import ugettext as _

class GroupListFilter(SimpleListFilter):
    title = _('group')
    parameter_name = 'group'

    def lookups(self, request, model_admin):
        items = ()
        for group in Group.objects.all():
            items += ((str(group.id), str(group.name),),)
        return items

    def queryset(self, request, queryset):
        group_id = request.GET.get(self.parameter_name, None)
        if group_id:
            return queryset.filter(groups=group_id)
        return queryset

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class MyUserAdmin(UserAdmin):
    list_filter = UserAdmin.list_filter + (GroupListFilter,)

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

Here is a complete example, that inherits from SimpleListFilter, which is available in Django 1.4 and up (current as of May 2023):

https://docs.djangoproject.com/en/4.2/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_filter

It support setting all available labels and parameters to create the completely custom filter.

It shows up as "By group" in the filter panel, with a list of all available groups.

from django.contrib.admin import SimpleListFilter
from django.contrib.auth.models import Group
from django.utils.translation import ugettext as _

class GroupListFilter(SimpleListFilter):
    title = _('group')
    parameter_name = 'group'

    def lookups(self, request, model_admin):
        items = ()
        for group in Group.objects.all():
            items += ((str(group.id), str(group.name),),)
        return items

    def queryset(self, request, queryset):
        group_id = request.GET.get(self.parameter_name, None)
        if group_id:
            return queryset.filter(groups=group_id)
        return queryset

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class MyUserAdmin(UserAdmin):
    list_filter = UserAdmin.list_filter + (GroupListFilter,)

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

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