使用thrift在HBase中写入php数组

发布于 2024-07-19 19:48:35 字数 338 浏览 3 评论 0原文

我有一个 Thrift php 客户端，我想在 HBase 表中写入，我正在执行以下操作：

  $mutations = array(
    new Mutation( array(
      'column' => 'entry:num',
      'value' => array('a','b','c')
    ) ),
  );
  $client->mutateRow( $t, $row, $mutations );

问题是，当在 HBase 中插入值时，该值（一个数组）会转换为“数组”，而不是存储元素数组的。如何将列表存储为数组（或字节数组）

原文

I have a Thrift php client and I want to write in a HBase table and I'm doing the following:

  $mutations = array(
    new Mutation( array(
      'column' => 'entry:num',
      'value' => array('a','b','c')
    ) ),
  );
  $client->mutateRow( $t, $row, $mutations );

The problem is that when inserting in HBase the value, which is an array, gets converted to 'Array' instead of storing the elements of the array.
How can I store the list as an array (or byte array)

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云柯 2024-07-26 19:48:35

HBase 突变对象需要三个带有布尔/文本值的字段，而不是数组。因此，您需要将任何结构化值转换为字符串，例如。

  $mutations = array(
     new Mutation( array(
       'isDelete' => FALSE,
       'column'   => 'entry:num',
       'value'    => serialize(array('a','b','c'))
     ) ),
   );
   $client->mutateRow( $t, $row, $mutations );

HBase Thrift API 的定义在这里；
http://svn.apache.org/viewvc/hbase/trunk/src/main/resources/org/apache/hadoop/hbase/thrift/Hbase.thrift?view=markup

我还没有测试过这个。

A HBase mutation object has required three fields with boolean/text values, not arrays. So you need to turn any structured value into a string, something like.

  $mutations = array(
     new Mutation( array(
       'isDelete' => FALSE,
       'column'   => 'entry:num',
       'value'    => serialize(array('a','b','c'))
     ) ),
   );
   $client->mutateRow( $t, $row, $mutations );

The definition of the HBase Thrift API is here;
http://svn.apache.org/viewvc/hbase/trunk/src/main/resources/org/apache/hadoop/hbase/thrift/Hbase.thrift?view=markup

I haven't tested this.

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薄荷→糖丶微凉 2024-07-26 19:48:35

我必须承认，我不知道你想要做什么（可能是由于缺乏有关 Thrift 和 HBase 的知识），但如果我正确理解你的问题，你正在尝试编写一些 PHP 数据结构（在本例中为数组）到存储介质。为了实现这一点，您必须以某种方式序列化您的数据。这可以使用自定义 XML 序列化、自定义二进制序列化，或者可能是最简单的解决方案，即 serialize() 提供的 PHP 内部序列化机制以及相应的 unserialize()。

如果您努力实现语言间互操作性，则应该使用自定义序列化，或者必须编写一个反序列化函数，以目标语言反序列化 PHP 序列化格式。

只是一个简单的例子 - 我不知道你必须把这段代码放在哪里，因为我不知道你到底在做什么：

$mutations = array(
    new Mutation(array(
      'column' => 'entry:num',
      'value'  => array('a','b','c')
    )),
  );
$data = serialize($mutations); // $data now is a string
// write $data to storage
// read $readData from storage
$readMutations = unserialize($readData);
// $readMutations == $mutations 
// (but the Mutation instances are not the same instances any more)

请参阅

I must admit that I do not have a clue what you're trying to do (perhaps due to a lack of knowledge regarding Thrift and HBase), but if I understood your question correctly, you're trying to write some PHP data structure (array in this case) to a storage media. To achieve this you have to serialize your data somehow. That could be using a custom XML serialization, a custom binary serialization or, perhaps the most simple solution, the PHP internal serialization mechanism provided by serialize() and the corresponding unserialize().

If you strive for inter-language-interoperability you should use a custom serialization or you have to write a unserialization function that unserializes the PHP serialization format in your target language.

Just a quick example - I don't know where you'd have to put this code, as I don't know exactly what you're doing:

$mutations = array(
    new Mutation(array(
      'column' => 'entry:num',
      'value'  => array('a','b','c')
    )),
  );
$data = serialize($mutations); // $data now is a string
// write $data to storage
// read $readData from storage
$readMutations = unserialize($readData);
// $readMutations == $mutations 
// (but the Mutation instances are not the same instances any more)

Please seee

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