Java曲线拟合库

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要求我们推荐或查找工具、库或最喜欢的场外资源的问题对于 Stack Overflow 来说是偏离主题的，因为它们往往会吸引固执己见的答案和垃圾邮件。 相反，描述问题以及到目前为止已采取的解决措施。

10 年前已关闭。

Answer 1

Apache Commons Math 有一系列很好的算法，特别是“SplineInterpolator”，请参阅API 文档

我们调用 alpha 插值函数的示例来自 Groovy 的 (x)、beta(x)：

package example.com

import org.apache.commons.math3.analysis.interpolation.SplineInterpolator
import org.apache.commons.math3.analysis.polynomials.PolynomialSplineFunction

import statec.Extrapolate.Value;

class Interpolate {

    enum Value {
        ALPHA, BETA
    }

    def static xValues     = [
        -284086,
        -94784,
        31446,
        354837,
        667782,
        982191
    ]
    def static alphaValues = [
        71641,
        78245,
        80871,
        94045,
        105780,
        119616
    ]
    def static betaValues = [
        95552,
        103413,
        108667,
        128456,
        144686,
        171953
    ]

    static def getValueByName(Value value, int i) {
        def res
        switch (value) {
            case Value.ALPHA:
                res = alphaValues[i]
                break
            case Value.BETA:
                res = betaValues[i]
                break
            default:
                assert false
        }
        return res
    }

    static PolynomialSplineFunction interpolate(Value value) {
        def yValues = []
        int i = 0
        xValues.each {
            def y = getValueByName(value, i++)
            yValues << (y as Double)
        }
        SplineInterpolator spi = new SplineInterpolator()
        return spi.interpolate(xValues as double[], yValues as double[])
    }

    static void main(def argv) {
        //
        // Create a map mapping a Value instance to its interpolating function
        //
        def interpolations = [:]
        Value.values().each {
            interpolations[it] = interpolate(it)
        }
        //
        // Create an array of new x values to compute display.
        // Make sure the last "original" value is in there!
        // Note that the newxValues MUST stay within the range of the original xValues!
        //
        def newxValues = []
        for (long x = xValues[0] ; x < xValues[-1] ; x+=25000) {
            newxValues << x
        }
        newxValues << xValues[-1]
        //
        // Write interpolated values for ALPHA and BETA, adding the original values in columns 4 and 5
        //
        System.out << "X , ALPHA, BETA, X_orig, ALPHA_orig, BETA_orig" << "\n"
        int origIndex = 0
        newxValues.each { long x ->
            def alpha_ipol = interpolations[Value.ALPHA].value(x)
            def beta_ipol  = interpolations[Value.BETA].value(x)
            String out = "${x} ,  ${alpha_ipol} , ${beta_ipol}"
            if (x >= xValues[origIndex]) {
                out += ", ${xValues[origIndex]}, ${alphaValues[origIndex]}, ${betaValues[origIndex]}"
                origIndex++
            }
            System.out << out << "\n"
        }
    }
}

现在来说一个题外话外推法的例子，因为它很有趣。 这里我们使用与上面相同的数据，但使用二次多项式进行推断。 当然还有适当的课程。 同样，在 Groovy 中：

package example.com

import org.apache.commons.math3.analysis.polynomials.PolynomialFunction
import org.apache.commons.math3.fitting.PolynomialFitter
import org.apache.commons.math3.fitting.WeightedObservedPoint
import org.apache.commons.math3.optim.SimpleVectorValueChecker
import org.apache.commons.math3.optim.nonlinear.vector.jacobian.GaussNewtonOptimizer

class Extrapolate {

    enum Value {
        ALPHA, BETA
    }

    def static xValues     = [
        -284086,
        -94784,
        31446,
        354837,
        667782,
        982191
    ]
    def static alphaValues = [
        71641,
        78245,
        80871,
        94045,
        105780,
        119616
    ]
    def static betaValues = [
        95552,
        103413,
        108667,
        128456,
        144686,
        171953
    ]

    static def getValueByName(Value value, int i) {
        def res
        switch (value) {
            case Value.ALPHA:
                res = alphaValues[i]
                break
            case Value.BETA:
                res = betaValues[i]
                break
            default:
                assert false
        }
        return res
    }

    static PolynomialFunction extrapolate(Value value) {
        //
        // how to check that we converged
        //
        def checker
        A: {
            double relativeThreshold = 0.01
            double absoluteThreshold = 10
            int maxIter = 1000
            checker = new SimpleVectorValueChecker(relativeThreshold, absoluteThreshold, maxIter)
        }
        //
        // how to fit
        //
        def fitter
        B: {
            def useLUdecomposition = true
            def optimizer = new GaussNewtonOptimizer(useLUdecomposition, checker)
            fitter = new PolynomialFitter(optimizer)
            int i = 0
            xValues.each {
                def weight = 1.0
                def y = getValueByName(value, i++)
                fitter.addObservedPoint(new WeightedObservedPoint(weight, it, y))
            }
        }
        //
        // fit using a 2-degree polynomial; guess at a linear function at first
        // "a0 + (a1 * x) + (a2 * x²)"; a linear guess mean a2 == 0
        //
        def params
        C: {
            def mStart = getValueByName(value,0)
            def mEnd   = getValueByName(value,-1)
            def xStart = xValues[0]
            def xEnd   = xValues[-1]
            def a2 = 0
            def a1 = (mEnd - mStart) / (xEnd - xStart) // slope
            def a0 = mStart - (xStart * a1) // 0-intersection
            def guess = [a0 , a1 , a2]
            params = fitter.fit(guess as double[])
        }
        //
        // make polynomial
        //
        return new PolynomialFunction(params)
    }

    static void main(def argv) {
        //
        // Create a map mapping a Value instance to its interpolating function
        //
        def extrapolations = [:]
        Value.values().each {
            extrapolations[it] = extrapolate(it)
        }
        //
        // New x, this times reaching out past the range of the original xValues
        //
        def newxValues = []
        for (long x = xValues[0] - 400000L ; x < xValues[-1] + 400000L ; x += 10000) {
            newxValues << x
        }
        //
        // Write the extrapolated series ALPHA and BETA, adding the original values in columns 4 and 5
        //
        System.out << "X , ALPHA, BETA, X_orig, ALPHA_orig, BETA_orig" << "\n"
        int origIndex = 0
        newxValues.each { long x ->
            def alpha_xpol = extrapolations[Value.ALPHA].value(x)
            def beta_xpol  = extrapolations[Value.BETA].value(x)
            String out = "${x} ,  ${alpha_xpol} , ${beta_xpol}"
            if (origIndex < xValues.size() && x >= xValues[origIndex]) {
                out += ", ${xValues[origIndex]}, ${alphaValues[origIndex]}, ${betaValues[origIndex]}"
                origIndex++
            }
            System.out << out << "\n"
        }
    }
}

Answer 2

我从来没有这样做过，但是快速谷歌搜索显示贝塞尔曲线是在 http://java.sun.com/j2se/1.5.0/docs/api/java/awt/geom/QuadCurve2D.Double.html

然后，您可以从这条曲线中 getPathIterator() ，根据文档的说明，您可以得到“形状边界的坐标”，我想这就是您正在寻找的。