MySQL:当存储过程参数名称与表列名称相同时[继续]

发布于 2024-07-19 05:40:26 字数 727 浏览 5 评论 0 原文

假设有一个存储过程 SetCustomerName,它有一个输入参数 Name,并且我有一个包含 Name 列的表customers。 因此,在我的存储过程中,我想设置客户的姓名。 如果我写

UPDATE customers SET Name = Name;

这是不正确的,我必须写(例如)

UPDATE customers SET `Name` = Name;

所以,有一个关于反引号的链接(http://dev.mysql.com/doc/refman/5.0/en/identifiers.html),但没有足够深入地解释如何使用它们(如何使用它们参数和列名称)。

有一件非常奇怪的事情(至少对我来说):您可以以任何一种方式使用反引号:

UPDATE customers SET Name = `Name`;
//or
UPDATE customers SET `Name` = Name;
//or even
UPDATE customers SET `Name` = `Name`;

而且它们的工作方式完全相同。

你不觉得这很奇怪吗? 这种奇怪的行为是否在某处得到了解释?

Let's say a have a stored procedure SetCustomerName which has an input parameter Name, and I have a table customers with column Name. So inside my stored procedure I want to set customer's name. If I write

UPDATE customers SET Name = Name;

this is incorrect and I have to write (for example)

UPDATE customers SET `Name` = Name;

So, there is a link about backticks (http://dev.mysql.com/doc/refman/5.0/en/identifiers.html) but it's not explained deep enough how to use them (how to use them with parameters and column names).

And there is a very strange thing (at least for me): You can use backticks either way:

UPDATE customers SET Name = `Name`;
//or
UPDATE customers SET `Name` = Name;
//or even
UPDATE customers SET `Name` = `Name`;

and they all work absolutely the same way.

Don't you think this is strange? Is this strange behavior explained somewhere?

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零度℉ 2024-07-26 05:40:26

我不明白为什么你需要首先使用反引号来转义。
在语句 UPDATE x SET a = b 中,a 必须始终引用 x 列。 b 但是可以是变量或列。 鉴于本地范围和变量解析在存储过程中的工作方式< /a>, b 将始终引用局部变量,即使 x 中存在同名列。

因此,我无法重现您的问题。 我尝试了这种方式:

mysql> SELECT * FROM comments;
+----+-----------+---------+
| id | parent_id | content |
+----+-----------+---------+
|  1 |         0 | bar     | 
|  2 |         0 | baz     | 
+----+-----------+---------+
2 rows in set (0.00 sec)
mysql> delimiter //
mysql> CREATE PROCEDURE foo(IN content TEXT)
    -> BEGIN
    ->   UPDATE comments SET content = content;
    -> END //
Query OK, 0 rows affected (0.00 sec)
mysql> delimiter ;
mysql> CALL foo('changed!');
Query OK, 2 rows affected (0.00 sec)
mysql> SELECT * FROM comments;
+----+-----------+----------+
| id | parent_id | content  |
+----+-----------+----------+
|  1 |         0 | changed! | 
|  2 |         0 | changed! | 
+----+-----------+----------+
2 rows in set (0.00 sec)

如您所见,注释表的列 content 得到更新,即使 content 也是存储过程的参数名称 foo.

您确定 UPDATE 客户 SET Name = Name; 给你一个错误?
通过上述解释,似乎合乎逻辑的是,

UPDATE customers SET Name = `Name`;
UPDATE customers SET `Name` = Name;
UPDATE customers SET `Name` = `Name`;

所有这些都具有相同的效果。

编辑:当然,对于 SELECT 语句,情况会有所不同。

I do not understand why you need to escape using backticks in the first place.
In a statement UPDATE x SET a = b, a must always refer to a column of x. b however can either be a variable or a column. Given how local scope and variable resolution works in stored procedures, b will always refer to the local variable, even if a column with the same name in x exists.

Thus, I am unable to reproduce your problem. I tried this way:

mysql> SELECT * FROM comments;
+----+-----------+---------+
| id | parent_id | content |
+----+-----------+---------+
|  1 |         0 | bar     | 
|  2 |         0 | baz     | 
+----+-----------+---------+
2 rows in set (0.00 sec)
mysql> delimiter //
mysql> CREATE PROCEDURE foo(IN content TEXT)
    -> BEGIN
    ->   UPDATE comments SET content = content;
    -> END //
Query OK, 0 rows affected (0.00 sec)
mysql> delimiter ;
mysql> CALL foo('changed!');
Query OK, 2 rows affected (0.00 sec)
mysql> SELECT * FROM comments;
+----+-----------+----------+
| id | parent_id | content  |
+----+-----------+----------+
|  1 |         0 | changed! | 
|  2 |         0 | changed! | 
+----+-----------+----------+
2 rows in set (0.00 sec)

As you can see, the comment-table's column content gets updated, even though content is also the name of the parameter of the stored procedure foo.

Are you sure that UPDATE customers SET Name = Name; gives you an error?
With the above explanation, it seems logical that

UPDATE customers SET Name = `Name`;
UPDATE customers SET `Name` = Name;
UPDATE customers SET `Name` = `Name`;

all have the same effect.

Edit: The situation would be different for SELECT statements, of course.

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