如何使用 WSGIREF 捕获 POST

发布于 2024-07-18 07:32:43 字数 740 浏览 4 评论 0原文

我正在尝试从简单的表单中捕获 POST 数据。

这是我第一次使用 WSGIREF，我似乎找不到正确的方法来做到这一点。

This is the form:
<form action="test" method="POST">
<input type="text" name="name">
<input type="submit"></form>

并且该函数显然缺少正确的信息来捕获帖子：

def app(environ, start_response):
    """starts the response for the webserver"""
    path = environ[ 'PATH_INFO']
    method = environ['REQUEST_METHOD']
    if method == 'POST':
        if path.startswith('/test'):
            start_response('200 OK',[('Content-type', 'text/html')])
            return "POST info would go here %s" % post_info
    else:
        start_response('200 OK', [('Content-type', 'text/html')])
        return form()

原文

I am trying to catch POST data from a simple form.

This is the first time I am playing around with WSGIREF and I can't seem to find the correct way to do this.

This is the form:
<form action="test" method="POST">
<input type="text" name="name">
<input type="submit"></form>

And the function that is obviously missing the right information to catch post:

def app(environ, start_response):
    """starts the response for the webserver"""
    path = environ[ 'PATH_INFO']
    method = environ['REQUEST_METHOD']
    if method == 'POST':
        if path.startswith('/test'):
            start_response('200 OK',[('Content-type', 'text/html')])
            return "POST info would go here %s" % post_info
    else:
        start_response('200 OK', [('Content-type', 'text/html')])
        return form()

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樱＆纷飞 2024-07-25 07:32:43

您应该读取来自服务器的响应。

来自 nosklo 对类似问题的回答：“PEP 333 说

测试代码（改编自此答案） :

警告：此代码仅用于演示目的。

警告：尽量避免硬编码路径或文件名。

def app(environ, start_response):
    path    = environ['PATH_INFO']
    method  = environ['REQUEST_METHOD']
    if method == 'POST':
        if path.startswith('/test'):
            try:
                request_body_size = int(environ['CONTENT_LENGTH'])
                request_body = environ['wsgi.input'].read(request_body_size)
            except (TypeError, ValueError):
                request_body = "0"
            try:
                response_body = str(request_body)
            except:
                response_body = "error"
            status = '200 OK'
            headers = [('Content-type', 'text/plain')]
            start_response(status, headers)
            return [response_body]
    else:
        response_body = open('test.html').read()
        status = '200 OK'
        headers = [('Content-type', 'text/html'),
                    ('Content-Length', str(len(response_body)))]
        start_response(status, headers)
        return [response_body]

You should be reading responses from the server.

From nosklo's answer to a similar problem: "PEP 333 says you must read environ['wsgi.input']."

Tested code (adapted from this answer):

Caveat: This code is for demonstrative purposes only.

Warning: Try to avoid hard-coding paths or filenames.

def app(environ, start_response):
    path    = environ['PATH_INFO']
    method  = environ['REQUEST_METHOD']
    if method == 'POST':
        if path.startswith('/test'):
            try:
                request_body_size = int(environ['CONTENT_LENGTH'])
                request_body = environ['wsgi.input'].read(request_body_size)
            except (TypeError, ValueError):
                request_body = "0"
            try:
                response_body = str(request_body)
            except:
                response_body = "error"
            status = '200 OK'
            headers = [('Content-type', 'text/plain')]
            start_response(status, headers)
            return [response_body]
    else:
        response_body = open('test.html').read()
        status = '200 OK'
        headers = [('Content-type', 'text/html'),
                    ('Content-Length', str(len(response_body)))]
        start_response(status, headers)
        return [response_body]

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