为什么我在使用 vfork() 时出现错误?

发布于 2024-07-16 21:11:34 字数 1382 浏览 6 评论 0原文

这是我的代码...我不知道为什么我收到错误段...有人可以向我解释原因吗?

#include <iostream>

#include <string>

// Required by for routine
#include <sys/types.h>
#include <unistd.h>

using namespace std;


int globalVariable = 2;

main()
{
   string sIdentifier;
   int    iStackVariable = 20;

   pid_t pID = vfork();
   if (pID == 0)                // child
   {
      // Code only executed by child process

      sIdentifier = "Child Process: ";
      globalVariable++;
      iStackVariable++;
      cout << "PROCESO NUMERO"<<getpid()<<sIdentifier;
//          printf("Proceso hijo: PID %d - PPID %d\n", getpid(), getppid());
      cout << " Global variable: " << globalVariable;
      cout << " Stack variable: "  << iStackVariable << endl;
      return (0);
    }
    else if (pID < 0)            // failed to fork
    {
        cerr << "Failed to fork" << endl;
        return (1);
        // Throw exception
    }
    else                                   // parent
    {
      // Code only executed by parent process

      sIdentifier = "Parent Process:";
    }

    // executed only by parent

    cout << sIdentifier;
    cout << " Global variable: " << globalVariable;
    cout << " Stack variable: "  << iStackVariable << endl;
    return (0);
}

This is my code... I don't know why I'm get an error segment... could somebody explain the reason to me?

#include <iostream>

#include <string>

// Required by for routine
#include <sys/types.h>
#include <unistd.h>

using namespace std;


int globalVariable = 2;

main()
{
   string sIdentifier;
   int    iStackVariable = 20;

   pid_t pID = vfork();
   if (pID == 0)                // child
   {
      // Code only executed by child process

      sIdentifier = "Child Process: ";
      globalVariable++;
      iStackVariable++;
      cout << "PROCESO NUMERO"<<getpid()<<sIdentifier;
//          printf("Proceso hijo: PID %d - PPID %d\n", getpid(), getppid());
      cout << " Global variable: " << globalVariable;
      cout << " Stack variable: "  << iStackVariable << endl;
      return (0);
    }
    else if (pID < 0)            // failed to fork
    {
        cerr << "Failed to fork" << endl;
        return (1);
        // Throw exception
    }
    else                                   // parent
    {
      // Code only executed by parent process

      sIdentifier = "Parent Process:";
    }

    // executed only by parent

    cout << sIdentifier;
    cout << " Global variable: " << globalVariable;
    cout << " Stack variable: "  << iStackVariable << endl;
    return (0);
}

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评论(2

荭秂 2024-07-23 21:11:34

这个有用吗? 请注意有关变量修改的警告。

vfork() 函数与 fork() 具有相同的效果,不同之处在于,如果 vfork() 创建的进程修改了除用于存储 vfork 返回值的 pid_t 类型变量之外的任何数据,则该行为是未定义的(),或从调用 vfork() 的函数返回,或在成功调用 _exit() 或 exec 系列函数之一之前调用任何其他函数。

Is this of use ? Note the caveats surrounding modification of variables.

The vfork() function has the same effect as fork(), except that the behaviour is undefined if the process created by vfork() either modifies any data other than a variable of type pid_t used to store the return value from vfork(), or returns from the function in which vfork() was called, or calls any other function before successfully calling _exit() or one of the exec family of functions.

蓝色星空 2024-07-23 21:11:34

如果您 vfork() 两个进程共享地址空间。 如果您要立即在子进程中执行另一个进程,您可能应该只使用 vfork() 。 创建系统调用的原因是为了避免复制父进程地址空间中的每个页面而导致子进程执行时丢弃所有这些映射的开销。 对于您的情况,请改用 fork() 。

If you vfork() both processes are sharing an address space. You should probably only use vfork() if you are going to exec another process pretty much immediately in the child. The reason the system call was created was to avoid the overhead of copying every page in the parent process's address space only to have all those mappings discarded when the child exec's. For your case, use fork() instead.

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