如何在SQL中查找组内序列中的缺失值?

发布于 2024-07-16 18:55:53 字数 909 浏览 10 评论 0原文

我有一个 ID 和位置表

CREATE TABLE #MissingSequence (ID INT NOT NULL, Position INT NOT NULL)
INSERT INTO #MissingSequence (ID,Position)
SELECT 36,1
UNION ALL SELECT 36,2
UNION ALL SELECT 36,3
UNION ALL SELECT 36,4
UNION ALL SELECT 36,5
UNION ALL SELECT 36,6
UNION ALL SELECT 44,1
UNION ALL SELECT 44,3
UNION ALL SELECT 44,4
UNION ALL SELECT 44,5
UNION ALL SELECT 44,6

我想要找到的是按 ID 排列的位置序列中是否有任何中断,在本例中是 44,1 和 44,3 之间的中断,

我已经设法一起解析:

SELECT  l.ID
    ,Start_Position = MIN(l.Position) + 1
    ,Stop_Position = MIN(fr.Position) - 1
FROM #MissingSequence l
LEFT JOIN #MissingSequence r 
    ON l.Position = r.Position - 1
LEFT JOIN #MissingSequence fr 
    ON l.Position < fr.Position
WHERE r.Position IS NULL
    AND fr.Position IS NOT NULL
GROUP BY l.ID

但是它如果有多个 ID 值,则不起作用。 如果只有一个 ID 44 存在,它就可以工作。

想法、评论、建议?

谢谢!

i have a table of IDs and positions

CREATE TABLE #MissingSequence (ID INT NOT NULL, Position INT NOT NULL)
INSERT INTO #MissingSequence (ID,Position)
SELECT 36,1
UNION ALL SELECT 36,2
UNION ALL SELECT 36,3
UNION ALL SELECT 36,4
UNION ALL SELECT 36,5
UNION ALL SELECT 36,6
UNION ALL SELECT 44,1
UNION ALL SELECT 44,3
UNION ALL SELECT 44,4
UNION ALL SELECT 44,5
UNION ALL SELECT 44,6

What I am trying to find is if there is any break in the sequence of Positions by ID in this case the break between 44,1 and 44,3

I've managed to parse together:

SELECT  l.ID
    ,Start_Position = MIN(l.Position) + 1
    ,Stop_Position = MIN(fr.Position) - 1
FROM #MissingSequence l
LEFT JOIN #MissingSequence r 
    ON l.Position = r.Position - 1
LEFT JOIN #MissingSequence fr 
    ON l.Position < fr.Position
WHERE r.Position IS NULL
    AND fr.Position IS NOT NULL
GROUP BY l.ID

but it doesn't work if there are multiple ID values. It does work if only a single ID, 44 exists.

thoughts, comments, suggestions?

thanks!

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评论(3

铁轨上的流浪者 2024-07-23 18:55:53

左自连接是一个很好的本能,但我不认为聚合会削减它,并且当然您需要在自连接中包含匹配 ID 子句。

这是一个使用 null-left-join 思想的(符合 ANSI 的)版本,选择顶行和底行并检查它们之间没有任何内容:

SELECT
    above.ID AS ID, below.Position+1 AS Start_Position, above.Position-1 AS End_Position
FROM MissingSequence AS above
JOIN MissingSequence AS below
    ON below.ID=above.ID AND below.Position<above.Position-1
LEFT JOIN MissingSequence AS inbetween
    ON inbetween.ID=below.ID AND inbetween.Position BETWEEN below.Position+1 AND above.Position-1
WHERE inbetween.ID IS NULL;

+----+----------------+--------------+
| ID | Start_Position | End_Position |
+----+----------------+--------------+
| 44 |              2 |            2 | 
+----+----------------+--------------+

The left self-join was a good instinct, but I don't think the aggregates are going to cut it, and certainly you'd need to include the matching-ID clause in your self-joins.

Here's an (ANSI-compliant) version using the null-left-join idea, selecting a top row and a bottom row and checking there's nothing between them:

SELECT
    above.ID AS ID, below.Position+1 AS Start_Position, above.Position-1 AS End_Position
FROM MissingSequence AS above
JOIN MissingSequence AS below
    ON below.ID=above.ID AND below.Position<above.Position-1
LEFT JOIN MissingSequence AS inbetween
    ON inbetween.ID=below.ID AND inbetween.Position BETWEEN below.Position+1 AND above.Position-1
WHERE inbetween.ID IS NULL;

+----+----------------+--------------+
| ID | Start_Position | End_Position |
+----+----------------+--------------+
| 44 |              2 |            2 | 
+----+----------------+--------------+
装纯掩盖桑 2024-07-23 18:55:53

本次查询发现单据,希望有用; 如果您使用的是 SQL 2005,则可以使用 CTE

SELECT ID, Position + 1
FROM #MissingSequence t1
WHERE (Position + 1) NOT IN (SELECT Position FROM #MissingSequence t2 WHERE t1.ID = t2.ID)
AND Position <> (SELECT MAX(Position) FROM #MissingSequence t2 WHERE t1.ID = t2.ID)

This query spots the slips, hope to be useful; if you are in SQL 2005, you can use a CTE

SELECT ID, Position + 1
FROM #MissingSequence t1
WHERE (Position + 1) NOT IN (SELECT Position FROM #MissingSequence t2 WHERE t1.ID = t2.ID)
AND Position <> (SELECT MAX(Position) FROM #MissingSequence t2 WHERE t1.ID = t2.ID)
旧话新听 2024-07-23 18:55:53
create database testing
use testing;
create table sequence (
    id int not null primary key
);

insert into sequence(id) values
    (1), (2), (3), (4), (6), (7), (8), (9),
    (10), (15), (16), (17), (18), (19), (20);

select * from sequence

Create PROCEDURE test_proce(@mode varchar(50))   
AS
BEGIN
    declare @se int;
    set @se=0;
    set @se=(
        select top 1 t.id + 1 
        from sequence t 
        left join sequence x on x.id = t.id + 1 
        where x.id is null 
        order by t.id
    );
    select * from sequence where id<@se;
END

exec test_proce 'mode'
create database testing
use testing;
create table sequence (
    id int not null primary key
);

insert into sequence(id) values
    (1), (2), (3), (4), (6), (7), (8), (9),
    (10), (15), (16), (17), (18), (19), (20);

select * from sequence

Create PROCEDURE test_proce(@mode varchar(50))   
AS
BEGIN
    declare @se int;
    set @se=0;
    set @se=(
        select top 1 t.id + 1 
        from sequence t 
        left join sequence x on x.id = t.id + 1 
        where x.id is null 
        order by t.id
    );
    select * from sequence where id<@se;
END

exec test_proce 'mode'
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