在 MySQL 语句中使用 datediff

发布于 2024-07-15 08:13:04 字数 701 浏览 5 评论 0原文

这是我使用 datediff 的 SQL 语句：

SELECT SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
FROM  B134HREC 
WHERE datediff (dd, '2006-05-05', getdate()) > 90
GROUP BY b134_rmcid, b134_recdate 
ORDER BY b134_recdate DESC, b134_rmcid

我需要用 MAX(b134_recdate) 替换硬编码日期 '2006-05-05'，如下所示：

SELECT SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
FROM  B134HREC 
where datediff (dd, MAX(b134_recdate), getdate()) > 90
GROUP BY b134_rmcid, b134_recdate 
ORDER BY b134_recdate DESC, b134_rmcid

但我收到此错误消息：

聚合不能出现在 WHERE 子句中，除非它位于 HAVING 子句或选择列表中包含的子查询中，并且聚合的列是外部引用。

知道如何修复我的 SQL 语句吗？

原文

This is my SQL statement that works using datediff:

SELECT SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
FROM  B134HREC 
WHERE datediff (dd, '2006-05-05', getdate()) > 90
GROUP BY b134_rmcid, b134_recdate 
ORDER BY b134_recdate DESC, b134_rmcid

I need to Replace the Hardcoded date '2006-05-05' with MAX(b134_recdate) like so:

SELECT SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
FROM  B134HREC 
where datediff (dd, MAX(b134_recdate), getdate()) > 90
GROUP BY b134_rmcid, b134_recdate 
ORDER BY b134_recdate DESC, b134_rmcid

But i get this Error message:

An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

Any idea how to fix my SQL Statement?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

听，心雨的声音 2024-07-22 08:13:04

尝试

SELECT SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
FROM  B134HRE 
where datediff (dd, 
      (select MAX(b134_recdate) from B134HRE)
      , getdate()) > 90
GROUP BY b134_rmcid, b134_recdate 
ORDER BY b134_recdate DESC, b134_rmcid

Try

SELECT SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
FROM  B134HRE 
where datediff (dd, 
      (select MAX(b134_recdate) from B134HRE)
      , getdate()) > 90
GROUP BY b134_rmcid, b134_recdate 
ORDER BY b134_recdate DESC, b134_rmcid

回复收藏 0 原文

放赐 2024-07-22 08:13:04

您是否尝试过移动此：

datediff (dd, MAX(b134_recdate), getdate()) > > 90

到 HAVING 子句？

sql 语句为：

<代码>
选择 SUM(b134_nettpay) AS 总计、b134_rmcid、b134_recdate
来自 B134HRE
按 b134_rmcid、b134_recdate 分组
按 b134_recdate DESC、b134_rmcid 排序
有 datediff (dd, MAX(b134_recdate), getdate()) > 90

回复收藏 0 原文

你怎么敢 2024-07-22 08:13:04

这段代码适用于 sql server

我不确定 MAX 是否适用于整个表：

DECLARE @MaxDate  datetime
SELECT @MaxDate=MAX(b134_recdate) FROM B134HRE
/* if you don't want time you need to trim it from @maxDate*/

    SELECT
        SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
        FROM  B134HRE 
        where datediff (dd, @MaxDate, getdate()) > 90
        GROUP BY b134_rmcid, b134_recdate 
        ORDER BY b134_recdate DESC, b134_rmcid

或每个组：

SELECT
    SUM(b.b134_nettpay) AS Total, b.b134_rmcid, b.b134_recdate 
    FROM  B134HRE   b
        INNER JOIN (SELECT
                        b134_rmcid, b134_recdate , MAX(b134_recdate) AS MaxDate
                        FROM B134HRE
                        GROUP BY b134_rmcid, b134_recdate 
                   ) dt ON b.b134_rmcid=dt.b134_rmcid AND b.b134_recdate=dt.b134_recdate
    where datediff (dd, dt.MaxDate, getdate()) > 90
    GROUP BY b.b134_rmcid, b.b134_recdate 
    ORDER BY b.b134_recdate DESC, b.b134_rmcid

但你可以尝试一下

This code is for sql server

I'm not sure if the MAX sould be for the entire table:

DECLARE @MaxDate  datetime
SELECT @MaxDate=MAX(b134_recdate) FROM B134HRE
/* if you don't want time you need to trim it from @maxDate*/

    SELECT
        SUM(b134_nettpay) AS Total, b134_rmcid, b134_recdate 
        FROM  B134HRE 
        where datediff (dd, @MaxDate, getdate()) > 90
        GROUP BY b134_rmcid, b134_recdate 
        ORDER BY b134_recdate DESC, b134_rmcid

or per each group:

SELECT
    SUM(b.b134_nettpay) AS Total, b.b134_rmcid, b.b134_recdate 
    FROM  B134HRE   b
        INNER JOIN (SELECT
                        b134_rmcid, b134_recdate , MAX(b134_recdate) AS MaxDate
                        FROM B134HRE
                        GROUP BY b134_rmcid, b134_recdate 
                   ) dt ON b.b134_rmcid=dt.b134_rmcid AND b.b134_recdate=dt.b134_recdate
    where datediff (dd, dt.MaxDate, getdate()) > 90
    GROUP BY b.b134_rmcid, b.b134_recdate 
    ORDER BY b.b134_recdate DESC, b.b134_rmcid

but you could give these a try

回复收藏 0 原文

~没有更多了~