flash 10 正交投影

发布于 2024-07-15 07:35:50 字数 481 浏览 8 评论 0原文

我一直在尝试新的 flash 10 3d 可能性，发现在 3d 中旋转精灵相当容易：

var card:Sprite = new MyCard()
card.x = 100
card.y = 100
card.z = 200
card.rotationX = -60
addChild(card)

简单而有效，这显示了随透视旋转的卡片。

现在我想使用正交投影，但我不知道从哪里开始。 DisplayObject确实有一个perspectiveProjection成员，但它当然只能进行透视投影。也许我应该使用transform.matrix3D？

我认为这应该不会太难，但我不知道如何解决这个问题。

更新：正如评论之一所建议的：将perspectiveProjection.fieldOfView设置为接近0的值（10实际上在我的设置中产生比0.1更好的结果），你会得到一个接近正交的投影，这可能已经足够好了。

原文

I've been playing a bit with the new flash 10 3d possibilities, and found out that rotating a sprite in 3d is fairly easy:

var card:Sprite = new MyCard()
card.x = 100
card.y = 100
card.z = 200
card.rotationX = -60
addChild(card)

Simple and effective, this shows the card rotated with perspective.

Now I want to use an orthographic projection, and I have no clue where to start. DisplayObject does have a perspectiveProjection member, but that can only make perspective projections of course. Maybe I should use the transform.matrix3D?

I'd think this should not be too hard, but I don't see how to tackle this issue.

UPDATE: as one of the comments suggests: setting the perspectiveProjection.fieldOfView to something close to 0 (10 actually produces a nicer result in my setup than something like 0.1) you get a projection that is nearly orthographic, that might be good enough.

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高跟鞋的旋律 2024-07-22 07:35:50

我终于让它工作了。

        var m:Matrix3D = new Matrix3D()
        var v3:Vector.<Vector3D> = new Vector.<Vector3D>(3);
        v3 = m.decompose();
        v3[2] = new Vector3D(1,1,0);
        m.recompose(v3)
        transform.matrix3D.appendRotation( -90, Vector3D.X_AXIS );
        transform.matrix3D.appendRotation( -45, Vector3D.Y_AXIS );
        transform.matrix3D.appendRotation( 35.264, Vector3D.X_AXIS );
        transform.matrix3D.append(m)

现在，添加到应用了此变换的精灵的任何元素都将显示在等角投影中。（35.264 是一个近似值，请参阅 http://en.wikipedia.org/wiki/Isometric_projection)

I finally got it working.

        var m:Matrix3D = new Matrix3D()
        var v3:Vector.<Vector3D> = new Vector.<Vector3D>(3);
        v3 = m.decompose();
        v3[2] = new Vector3D(1,1,0);
        m.recompose(v3)
        transform.matrix3D.appendRotation( -90, Vector3D.X_AXIS );
        transform.matrix3D.appendRotation( -45, Vector3D.Y_AXIS );
        transform.matrix3D.appendRotation( 35.264, Vector3D.X_AXIS );
        transform.matrix3D.append(m)

Now any element added to the sprite that has this transform applied to it will show up in isometric projection. (that 35.264 number is an approximation see http://en.wikipedia.org/wiki/Isometric_projection)

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