Python 拖放

发布于 2024-07-15 01:40:22 字数 1116 浏览 14 评论 0原文

我在这里开发一个解析器，它打开一个文件，读取它并在另一个文件中打印数据。

输入文件由 sys.argv[1] 确定，以处理命令行打开和拖放（在 Windows 中）。但是，当拖放文件时，它让我

ioerror 13: Permission denied

查看 sys.argv 包含的内容，我执行了以下操作（从 cmd.exe）以使其包含相同的内容：

C:\>python C:\test\iotest.py C:\test\iotestin.txt

它失败了。然而，以下作品

C:\>cd test
C:\test>python iotest.py iotestin.txt

对我来说，上面的内容实际上/应该是相同的。

为什么我会收到权限错误？
如何使 python 能够处理完全指定的路径？（如果这就是问题所在。）
如何启用拖放功能？

哦，如果不清楚，我将 input/txt 文件拖到 python 文件中，而不是相反。作为一名编码员，我总是更喜欢 CLI，但该软件的未来用户并不喜欢，因此我需要让它正常工作。

虽然非常简单，但这里有一些代码可以重现该问题：

import sys
print sys.argv
raw_input("")

try:
    print "opening",sys.argv[1]
    infile = open(sys.argv[1])
    outfile = open("out.txt", "w")
    raw_input("")
except IndexError:
    print "usage:",sys.argv[0].split("\\")[-1],"FILE"
    raw_input("")
    exit()
except IOError as (errno, strerror):
    print "I/O error({0}): {1}".format(errno, strerror)
    raw_input("")
    exit()

raw_input("done")

原文

Im working on a parser here that opens a file, reads it and prints data in another file.

The input file is determined from sys.argv[1] to both handle commandline opening and drag and drop (in windows). However, when drag and dropping a file, it gives me

ioerror 13: Permission denied

Looking at what sys.argv contained, I did the following (from cmd.exe) to have it contain the same:

C:\>python C:\test\iotest.py C:\test\iotestin.txt

It failed. However, the following works

C:\>cd test
C:\test>python iotest.py iotestin.txt

To me, the above would/should be virtually the same.

Why do I get the permission error?
How do I make python able to handle fully specified paths? (If thats the problem.)
How do I enable drag and drop?

Oh, and if its unclear, I drag the input/txt file to the python file, not the other way around. As a coder, I always prefer a CLI, but the future users of this software do not, hence I need to get this working.

Although extremely simple, heres some code to reproduce the problem:

import sys
print sys.argv
raw_input("")

try:
    print "opening",sys.argv[1]
    infile = open(sys.argv[1])
    outfile = open("out.txt", "w")
    raw_input("")
except IndexError:
    print "usage:",sys.argv[0].split("\\")[-1],"FILE"
    raw_input("")
    exit()
except IOError as (errno, strerror):
    print "I/O error({0}): {1}".format(errno, strerror)
    raw_input("")
    exit()

raw_input("done")

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