如何获取 C++ 中抽象（？） pimpl 的调试信息？

发布于 2024-07-15 01:29:56 字数 605 浏览 11 评论 0原文

我有一个包装类，它将其工作委托给 pimpl，而 pimpl 是一个指向基类/接口的指针，没有以多种不同方式专门化的数据。

像这样：

class Base
{
    void doStuff=0;
};

class Derived
{
    int x,y;
    void doStuff()
    {
        x = (x+y*2)*x; //whatever
    }
};

class Wrapper
{
    Base*   _pimpl;
    void doStuff()
    {
        _pimpl->doStuff();
    }
};

现在大多数情况下都可以正常工作，但是当进入调试器时，我无法查看派生类的 x,y （因为它可以是任何东西）。通常这是无关紧要的，但是当出现问题时，查看 Derived 的状态可能很重要，但 pimpl 过于模糊了状态（然而这是 pimpl 的原始想法，所以我想我不能真正抱怨）。

现在我有一个 tostring() 函数，可以打印状态以用于调试目的，但想知道是否有更好的解决方案，特别是在 VisualStudio 中调试此类构造，但通用解决方案会更好。

谢谢

原文

I have a wrapper class that delegates its work to a pimpl, and the pimpl is a pointer to a baseclass/interface with no data that is specialized in several different ways.

Like this:

class Base
{
    void doStuff=0;
};

class Derived
{
    int x,y;
    void doStuff()
    {
        x = (x+y*2)*x; //whatever
    }
};

class Wrapper
{
    Base*   _pimpl;
    void doStuff()
    {
        _pimpl->doStuff();
    }
};

Now this works fine most of the time, but when going into the debugger I can't view x,y of the Derived class (because it could be anything). Normally this is irrelevant, but when something goes wrong seeing the state of Derived can be important, but pimpl obscures the state too much (however that's the original idea of a pimpl, so I guess I can't really complain).

Now I have a tostring() function that prints the state out for debug purposes, but was wondering if there is a better solution, to debug this sort of construct in VisualStudio in particular, but a general solution would be better.

Thanks

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