根据周数计算日期

Question

任何人都知道一种简单的方法来获取一周第一天的日期（欧洲的星期一）。 我知道年份和周数吗？ 我将在 C# 中执行此操作。

Answer 1

最简单的方法可能是找到一年中的第一个星期一，然后添加相关的周数。 这是一些示例代码。 顺便说一句，它假定周数从 1 开始：

using System;

class Test
{
    static void Main()
    {
        // Show the third Tuesday in 2009. Should be January 20th
        Console.WriteLine(YearWeekDayToDateTime(2009, DayOfWeek.Tuesday, 3));
    }

    static DateTime YearWeekDayToDateTime(int year, DayOfWeek day, int week)
    {
        DateTime startOfYear = new DateTime (year, 1, 1);

        // The +7 and %7 stuff is to avoid negative numbers etc.
        int daysToFirstCorrectDay = (((int)day - (int)startOfYear.DayOfWeek) + 7) % 7;

        return startOfYear.AddDays(7 * (week-1) + daysToFirstCorrectDay);
    }
}

Answer 2

就我个人而言，我会利用文化信息来获取一周中的某一天，并循环到文化的一周第一天。 我不确定我的解释是否正确，这是一个例子：

    public DateTime GetFirstDayOfWeek(int year, int weekNumber)
    {
        return GetFirstDayOfWeek(year, weekNumber, Application.CurrentCulture);
    }

    public DateTime GetFirstDayOfWeek(int year, int weekNumber,
        System.Globalization.CultureInfo culture)
    {
        System.Globalization.Calendar calendar = culture.Calendar;
        DateTime firstOfYear = new DateTime(year, 1, 1, calendar);
        DateTime targetDay = calendar.AddWeeks(firstOfYear, weekNumber);
        DayOfWeek firstDayOfWeek = culture.DateTimeFormat.FirstDayOfWeek;

        while (targetDay.DayOfWeek != firstDayOfWeek)
        {
            targetDay = targetDay.AddDays(-1);
        }

        return targetDay;
    }

Answer 3

使用 Fluent DateTime http://fluentdatetime.codeplex.com/

        var year = 2009;
        var firstDayOfYear = new DateTime(year, 1, 1);
        var firstMonday = firstDayOfYear.Next(DayOfWeek.Monday);
        var weeksDateTime = 12.Weeks().Since(firstMonday);

Answer 4

这是一种与 Google Analytics 的周数兼容的方法，也与我们在英特尔内部使用的相同编号方案兼容，我确信它也在许多其他环境中使用。

// Google Analytics does not follow ISO standards for date.
// It numbers week 1 starting on Jan. 1, regardless what day of week it starts on.
// It treats Sunday as the first day of the week.
// The first and last weeks of a year are usually not complete weeks.
public static DateTime GetStartDateTimeFromWeekNumberInYear(int year, uint weekOfYear)
{
  if (weekOfYear == 0 || weekOfYear > 54) throw new ArgumentException("Week number must be between 1 and 54! (Yes, 54... Year 2000 had Jan. 1 on a Saturday plus 53 Sundays.)");

  // January 1 -- first week.
  DateTime firstDayInWeek = new DateTime(year, 1, 1);
  if (weekOfYear == 1) return firstDayInWeek;

  // Get second week, starting on the following Sunday.      
  do
  {
    firstDayInWeek = firstDayInWeek.AddDays(1);
  } while (firstDayInWeek.DayOfWeek != DayOfWeek.Sunday);

  if (weekOfYear == 2) return firstDayInWeek;

  // Now get the Sunday of whichever week we're looking for.
  return firstDayInWeek.AddDays((weekOfYear - 2)*7);
}

Answer 5

稍微修改了 Mikael Svenson 代码。 我找到了第一个星期一所在的周并适当更改了周数。

 DateTime GetFirstWeekDay(int year, int weekNum)
    {
        Calendar calendar = CultureInfo.CurrentCulture.Calendar;

        DateTime jan1 = new DateTime(year, 1, 1);

        int daysOffset = DayOfWeek.Monday - jan1.DayOfWeek;
        DateTime firstMonday = jan1.AddDays(daysOffset);
        int firstMondayWeekNum = calendar.GetWeekOfYear(firstMonday, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);

        DateTime firstWeekDay = firstMonday.AddDays((weekNum-firstMondayWeekNum) * 7);

        return firstWeekDay;
    }

Answer 6

根据瑞典使用的 ISO 8601:1988 标准，一年中的第一周是新的一年中至少有四天的第一周。

因此，如果您的一周从星期一开始，则任何一年的第一个星期四都在第一周内。
您可以从中添加 DateAdd 或 DateDiff 。

Answer 7

假设周数从 1 开始，

DateTime dt =  new DateTime(YearNumber, 1, 1).AddDays((WeekNumber - 1) * 7 - (WeekNumber == 1 ? 0 : 1));
return dt.AddDays(-(int)dt.DayOfWeek);

这将为您提供任何给定周的第一天。 我没有对其进行大量测试，但看起来它确实有效。 它比我在网上找到的大多数其他解决方案都要小，所以想分享。

Answer 8

免费的.NET 时间段库包括ISO 8601 符合类 Week：

// ----------------------------------------------------------------------
public static DateTime GetFirstDayOfWeek( int year, int weekOfYear )
{
  return new Week( year, weekOfYear ).FirstDayStart;
} // GetFirstDayOfWeek

Answer 9

这个对我有用，它还有一个优点是期望以文化信息作为参数来测试不同文化的公式。 如果为空，它将获取当前的文化信息...有效值如下：“it”，“en-us”，“fr”，...等等。
诀窍是减去一年中第一天的周数，这可能是 1，表示第一天在第一周之内。 希望这可以帮助。

Public Shared Function FirstDayOfWeek(ByVal year As Integer, ByVal weekNumber As Integer, ByVal culture As String) As Date
    Dim cInfo As System.Globalization.CultureInfo
    If culture = "" Then
        cInfo = System.Globalization.CultureInfo.CurrentCulture
    Else
        cInfo = System.Globalization.CultureInfo.CreateSpecificCulture(culture)
    End If
    Dim calendar As System.Globalization.Calendar = cInfo.Calendar
    Dim firstOfYear As DateTime = New DateTime(year, 1, 1, calendar)
    Dim firstDayWeek As Integer = calendar.GetWeekOfYear(firstOfYear, cInfo.DateTimeFormat.CalendarWeekRule, cInfo.DateTimeFormat.FirstDayOfWeek)
    weekNumber -= firstDayWeek
    Dim targetDay As DateTime = calendar.AddWeeks(firstOfYear, weekNumber)
    Dim fDayOfWeek As DayOfWeek = cInfo.DateTimeFormat.FirstDayOfWeek

    While (targetDay.DayOfWeek <> fDayOfWeek)
        targetDay = targetDay.AddDays(-1)
    End While
    Return targetDay
End Function

Answer 10

我尝试了上面的一些代码，有些有小错误，当你尝试不同的年份和不同的一周开始日期时，你会看到它们，我采用了 Jon Skeet 的代码，修复它并且它可以工作，非常简单的代码。

Public Function YearWeekDayToDateTime(ByVal year As Integer, ByVal weekDay As Integer, ByVal week As Integer) As DateTime
   ' weekDay, day you want
    Dim startOfYear As New DateTime(year, 1, 1)
    Dim startOfYearFixDay As Integer

    If startOfYear.DayOfWeek <> DayOfWeek.Sunday Then
        startOfYearFixDay = startOfYear.DayOfWeek
    Else
        startOfYearFixDay = 7
    End If

    Return startOfYear.AddDays((7 * (week)) - startOfYearFixDay + weekDay)
End Function

Answer 11

我简化了 Mikael Svensson 提供的代码，该代码对于欧洲许多国家/地区都是正确的。

public static DateTime FirstDateOfWeekIso8601(int year, int week)
{
        var firstThursdayOfYear = new DateTime(year, 1, 1);
        while (firstThursdayOfYear.DayOfWeek != DayOfWeek.Thursday)
        {
            firstThursdayOfYear = firstThursdayOfYear.AddDays(1);
        }

        var startDateOfWeekOne = firstThursdayOfYear.AddDays(-(DayOfWeek.Thursday - DayOfWeek.Monday));

        return startDateOfWeekOne.AddDays(7 * (week - 1));        
}

Answer 12

正如 khellang 所建议的（抱歉，我无法添加评论），使用 .NET Core 非常简单。 这是我的一段代码：

var today = DateTime.Today;
CultureInfo myCI = new CultureInfo("it-IT");
Calendar myCal = myCI.Calendar;
var weekNumber = myCal.GetWeekOfYear(today, CalendarWeekRule.FirstFullWeek, DayOfWeek.Monday);
var firstWeekDay = ISOWeek.ToDateTime(today.Year, weekNumber, DayOfWeek.Monday);

Answer 13

第 1 周定义为从星期一开始并包含一年中第一个星期四的一周。

Answer 14

要双向转换，请参阅此处：有关 ISO 周日期的维基百科文章

Answer 15

我通过覆盖对托马斯的解决方案进行了一些改进：

   public static DateTime FirstDateOfWeek(int year, int weekOfYear)
    {
      return Timer.FirstDateOfWeekOfMonth(year, 1, weekOfYear);
    }

    public static DateTime FirstDateOfWeekOfMonth(int year, int month, 
    int weekOfYear)
    {
      DateTime dtFirstDayOfMonth = new DateTime(year, month, 1);

       //I also commented out this part:
      /*
      if (firstWeek <= 1)
      {
        weekOfYear -= 1;
      }
      */

否则日期提前一周。

谢谢托马斯，很有帮助。

Answer 16

我使用了其中一个解决方案，但它给了我错误的结果，仅仅是因为它将星期日算作一周的第一天。

我将： 更改

var firstDay = new DateTime(DateTime.Now.Year, 1, 1).AddDays((weekNumber - 1) * 7);
var lastDay = firstDay.AddDays(6);

为：

var lastDay = new DateTime(DateTime.Now.Year, 1, 1).AddDays((weekNumber) * 7);
var firstDay = lastDay.AddDays(-6);

现在它正在发挥作用。

Answer 17

建议的解决方案并不完整 - 它仅适用于 CalendarWeekRule.FirstFullWeek。 其他类型的周规则不起作用。 使用这个测试用例可以看出这一点：

foreach (CalendarWeekRule rule in Enum.GetValues(typeof(CalendarWeekRule)))
{
    for (int year = 1900; year < 2000; year++)
    {
        DateTime date = FirstDateOfWeek(year, 1, rule);
        Assert(CultureInfo.CurrentCulture.Calendar.GetWeekOfYear(date, rule, DayOfWeek.Monday) == 1);
        Assert(CultureInfo.CurrentCulture.Calendar.GetWeekOfYear(date.AddDays(-1), rule, DayOfWeek.Monday) != 1);
    }
}

Answer 18

我对所提出的解决方案做了一个改进版本，它更简单，并且参数化了firstDayOfWeek：

public static DateTime GetFirstDayOfWeek(int year, int week, DayOfWeek firstDayOfWeek)
{
    return GetWeek1Day1(year, firstDayOfWeek).AddDays(7 * (week - 1));
}

public static DateTime GetWeek1Day1(int year, DayOfWeek firstDayOfWeek)
{
    DateTime date = new DateTime(year, 1, 1);

    // Move towards firstDayOfWeek
    date = date.AddDays(firstDayOfWeek - date.DayOfWeek);

    // Either 1 or 52 or 53
    int weekOfYear = CultureInfo.CurrentCulture.Calendar.GetWeekOfYear(date, CalendarWeekRule.FirstFullWeek, firstDayOfWeek);

    // Move forwards 1 week if week is 52 or 53
    date = date.AddDays(7 * System.Math.Sign(weekOfYear - 1));

    return date;
}

Answer 19

当我们想要计算给定年份、周数和星期几的日期时，这是我的解决方案。

int Year = 2014;
int Week = 48;
int DayOfWeek = 4;

DateTime FecIni = new DateTime(Year, 1, 1);
FecIni = FecIni.AddDays(7 * (Week - 1));
if ((int)FecIni.DayOfWeek > DayOfWeek)
{
    while ((int)FecIni.DayOfWeek != DayOfWeek) FecIni = FecIni.AddDays(-1);
}
else
{
    while ((int)FecIni.DayOfWeek != DayOfWeek) FecIni = FecIni.AddDays(1);
}

Answer 20

我已经编写并测试了以下代码，并且对我来说工作得很好。 如果有人遇到此问题，请告诉我，我也发布了一个问题，以便获得最佳答案。 有人可能会发现它很有用。

public static DateTime GetFirstDateOfWeekByWeekNumber(int year, int weekNumber)
        {
            var date = new DateTime(year, 01, 01);
            var firstDayOfYear = date.DayOfWeek;
            var result = date.AddDays(weekNumber * 7);

            if (firstDayOfYear == DayOfWeek.Monday)
                return result.Date;
            if (firstDayOfYear == DayOfWeek.Tuesday)
                return result.AddDays(-1).Date;
            if (firstDayOfYear == DayOfWeek.Wednesday)
                return result.AddDays(-2).Date;
            if (firstDayOfYear == DayOfWeek.Thursday)
                return result.AddDays(-3).Date;
            if (firstDayOfYear == DayOfWeek.Friday)
                return result.AddDays(-4).Date;
            if (firstDayOfYear == DayOfWeek.Saturday)
                return result.AddDays(-5).Date;
            return result.AddDays(-6).Date;
        }

Answer 21

目前，没有 C# 类可以正确处理 ISO 8601week 数字。 尽管您可以实例化一种文化，寻找最接近的事物并纠正它，但我认为最好自己进行完整的计算：

    /// <summary>
    /// Converts a date to a week number.
    /// ISO 8601 week 1 is the week that contains the first Thursday that year.
    /// </summary>
    public static int ToIso8601Weeknumber(this DateTime date)
    {
        var thursday = date.AddDays(3 - date.DayOfWeek.DayOffset());
        return (thursday.DayOfYear - 1) / 7 + 1;
    }

    /// <summary>
    /// Converts a week number to a date.
    /// Note: Week 1 of a year may start in the previous year.
    /// ISO 8601 week 1 is the week that contains the first Thursday that year, so
    /// if December 28 is a Monday, December 31 is a Thursday,
    /// and week 1 starts January 4.
    /// If December 28 is a later day in the week, week 1 starts earlier.
    /// If December 28 is a Sunday, it is in the same week as Thursday January 1.
    /// </summary>
    public static DateTime FromIso8601Weeknumber(int weekNumber, int? year = null, DayOfWeek day = DayOfWeek.Monday)
    {
        var dec28 = new DateTime((year ?? DateTime.Today.Year) - 1, 12, 28);
        var monday = dec28.AddDays(7 * weekNumber - dec28.DayOfWeek.DayOffset());
        return monday.AddDays(day.DayOffset());
    }

    /// <summary>
    /// Iso8601 weeks start on Monday. This returns 0 for Monday.
    /// </summary>
    private static int DayOffset(this DayOfWeek weekDay)
    {
        return ((int)weekDay + 6) % 7;
    }

Answer 22

我发现的最大问题之一是将周转换为日期，然后从日期转换为周。

主要问题是当尝试从属于上一年一周的日期获取正确的星期年份时。 幸运的是 System.Globalization.ISOWeek.GetYear 可以处理这个问题。

这是我的解决方案：

public class WeekOfYear
{
    public static (int Year, int Week) DateToWeekOfYear(DateTime date) =>
        (ISOWeek.GetYear(date), ISOWeek.GetWeekOfYear(date));

    public static bool ValidYearAndWeek(int year, int week) =>
           year >= 1 && year <= 9999 && week >= 1 && week <= 53 // bounds of year/week
        && !(year <= 1 && week <= 1) && !(year >= 9999 && week >= 53); // bounds of DateTime

    public int Year { get; }
    public int Week { get; }
    public virtual DateTime StartOfWeek { get; protected set; }
    public virtual DateTime EndOfWeek { get; protected set; }

    public virtual IEnumerable<DateTime> DaysInWeek =>
        Enumerable.Range(1, 10).Select(i => StartOfWeek.AddDays(i));

    public WeekOfYear(int year, int week)
    {
        if (!ValidYearAndWeek(year, week))
            throw new ArgumentException($"DateTime can't represent {week} of year {year}.");

        Year = year;
        Week = week;
        StartOfWeek = ISOWeek.ToDateTime(year, week, DayOfWeek.Monday);
        EndOfWeek = ISOWeek.ToDateTime(year, week, DayOfWeek.Sunday).AddDays(1).AddTicks(-1);
    }

    public WeekOfYear((int Year, int Week) week) : this(week.Year, week.Week) { }
    public WeekOfYear(DateTime date) : this(DateToWeekOfYear(date)) { }
}

第二大问题是美国偏好从周日开始的几周。

我从上面提出了子类 WeekOfYear 的解决方案，并管理构造函数中的偏移量（将周转换为日期）和 DateToWeekOfYear （将日期转换为周） ）。

public class UsWeekOfYear : WeekOfYear
{
    public static new (int Year, int Week) DateToWeekOfYear(DateTime date)
    {
        // if date is a sunday, return the next week
        if (date.DayOfWeek == DayOfWeek.Sunday) date = date.AddDays(1);
        return WeekOfYear.DateToWeekOfYear(date);
    }

    public UsWeekOfYear(int year, int week) : base(year, week)
    {
        StartOfWeek = ISOWeek.ToDateTime(year, week, DayOfWeek.Monday).AddDays(-1);
        EndOfWeek = ISOWeek.ToDateTime(year, week, DayOfWeek.Sunday).AddTicks(-1);
    }

    public UsWeekOfYear((int Year, int Week) week) : this(week.Year, week.Week) { }
    public UsWeekOfYear(DateTime date) : this(DateToWeekOfYear(date)) { }
}

这是一些测试代码：

public static void Main(string[] args)
{
    Console.WriteLine("== Last Week / First Week");
    Log(new WeekOfYear(2020, 53));
    Log(new UsWeekOfYear(2020, 53));

    Log(new WeekOfYear(2021, 1));
    Log(new UsWeekOfYear(2021, 1));

    Console.WriteLine("\n== Year Crossover (iso)");
    var start = new DateTime(2020, 12, 26);
    var i = 0;
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2020-12-26 - Sat
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2020-12-27 - Sun
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2020-12-28 - Mon
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2020-12-29 - Tue
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2020-12-30 - Wed
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2020-12-30 - Thu
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2021-01-01 - Fri
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2021-01-02 - Sat
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2021-01-03 - Sun
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2021-01-04 - Mon
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2021-01-05 - Tue
    Log(start.AddDays(i), new WeekOfYear(start.AddDays(i++))); // 2021-01-06 - Wed

    Console.WriteLine("\n== Year Crossover (us)");
    i = 0;
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2020-12-26 - Sat
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2020-12-27 - Sun
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2020-12-28 - Mon
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2020-12-29 - Tue
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2020-12-30 - Wed
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2020-12-30 - Thu
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2021-01-01 - Fri
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2021-01-02 - Sat
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2021-01-03 - Sun
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2021-01-04 - Mon
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2021-01-05 - Tue
    Log(start.AddDays(i), new UsWeekOfYear(start.AddDays(i++))); // 2021-01-06 - Wed

    var x = new UsWeekOfYear(2020, 53) as WeekOfYear;
}

public static void Log(WeekOfYear week)
{
    Console.WriteLine($"{week} - {week.StartOfWeek:yyyy-MM-dd} ({week.StartOfWeek:ddd}) - {week.EndOfWeek:yyyy-MM-dd} ({week.EndOfWeek:ddd})");
}

public static void Log(DateTime date, WeekOfYear week)
{
    Console.WriteLine($"{date:yyyy-MM-dd (ddd)} - {week} - {week.StartOfWeek:yyyy-MM-dd (ddd)} - {week.EndOfWeek:yyyy-MM-dd (ddd)}");
}

Answer 23

即使 @RobinAndersson 进行了修复，我也对 @HenkHolterman 的解决方案有疑问。

阅读 ISO 8601 标准可以很好地解决这个问题。 使用第一个星期四作为目标，而不是星期一。 下面的代码也适用于 2009 年第 53 周。

public static DateTime FirstDateOfWeekISO8601(int year, int weekOfYear)
{
    DateTime jan1 = new DateTime(year, 1, 1);
    int daysOffset = DayOfWeek.Thursday - jan1.DayOfWeek;

    // Use first Thursday in January to get first week of the year as
    // it will never be in Week 52/53
    DateTime firstThursday = jan1.AddDays(daysOffset);
    var cal = CultureInfo.CurrentCulture.Calendar;
    int firstWeek = cal.GetWeekOfYear(firstThursday, CalendarWeekRule.FirstFourDayWeek, DayOfWeek.Monday);

    var weekNum = weekOfYear;
    // As we're adding days to a date in Week 1,
    // we need to subtract 1 in order to get the right date for week #1
    if (firstWeek == 1)
    {
        weekNum -= 1;
    }

    // Using the first Thursday as starting week ensures that we are starting in the right year
    // then we add number of weeks multiplied with days
    var result = firstThursday.AddDays(weekNum * 7);

    // Subtract 3 days from Thursday to get Monday, which is the first weekday in ISO8601
    return result.AddDays(-3);
}       

Answer 24

注意

以下答案使用 .NET 日历规则。 它不承诺符合 ISO8601。 当您需要时，请参阅此处的一些其他答案。 周编号是一团糟，总是先尝试找出需要遵循的规则。

---

下面的代码正确地将 2009 年第 1 周的开始时间定为 2008 年 12 月 29 日。 CalendarWeekRule 可能应该是一个参数。

请注意，weekNum 应该 >= 1

static DateTime FirstDateOfWeek(int year, int weekNum, CalendarWeekRule rule)
{
    Debug.Assert(weekNum >= 1);

    DateTime jan1 = new DateTime(year, 1, 1);

    int daysOffset = DayOfWeek.Monday - jan1.DayOfWeek;
    DateTime firstMonday = jan1.AddDays(daysOffset);
    Debug.Assert(firstMonday.DayOfWeek == DayOfWeek.Monday);

    var cal = CultureInfo.CurrentCulture.Calendar;
    int firstWeek = cal.GetWeekOfYear(firstMonday, rule, DayOfWeek.Monday);

    if (firstWeek <= 1)
    {
        weekNum -= 1;
    }

    DateTime result = firstMonday.AddDays(weekNum * 7);

    return result;
}

Answer 25

更新：.NET Core 3.0 和 .NET Standard 2.1 已随此类型一起提供。

好消息！ 将 System.Globalization.ISOWeek 添加到 .NET 的拉取请求 Core 刚刚合并，目前计划发布 3.0 版本。 希望它能在不久的将来传播到其他 .NET 平台。

您应该能够使用 ISOWeek.ToDateTime(intyear, int week, DayOfWeek dayOfWeek) 方法来计算此值。

您可以找到源代码 此处。

Answer 26

我喜欢 Henk Holterman 提供的解决方案。 但为了更加独立于文化，您必须获得当前文化的一周的第一天（并不总是星期一）：

using System.Globalization;

static DateTime FirstDateOfWeek(int year, int weekOfYear)
{
  DateTime jan1 = new DateTime(year, 1, 1);

  int daysOffset = (int)CultureInfo.CurrentCulture.DateTimeFormat.FirstDayOfWeek - (int)jan1.DayOfWeek;

  DateTime firstMonday = jan1.AddDays(daysOffset);

  int firstWeek = CultureInfo.CurrentCulture.Calendar.GetWeekOfYear(jan1, CultureInfo.CurrentCulture.DateTimeFormat.CalendarWeekRule, CultureInfo.CurrentCulture.DateTimeFormat.FirstDayOfWeek);

  if (firstWeek <= 1)
  {
    weekOfYear -= 1;
  }

  return firstMonday.AddDays(weekOfYear * 7);
}