如何剪切(1) 个驼峰字？

发布于 2024-07-14 12:06:29 字数 182 浏览 7 评论 0原文

Bash 中有没有一种简单的方法可以将驼峰式单词拆分为其组成词？

例如，我想将 aCertainCamelCasedWord 拆分为“a certain Camel Cased Word”，并能够选择我感兴趣的那些字段。当单词分隔符是下划线时，可以使用 cut(1) 轻松完成此操作，但是当单词是驼峰式时我该如何做到这一点？

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对岸观火 2024-07-21 12:06:29

sed 's/\([AZ]\)/ \1/g'

捕获每个大写字母，并用捕获的整个流替换前导空格。

$ echo "aCertainCamelCasedWord" | sed 's/\([A-Z]\)/ \1/g'
a Certain Camel Cased Word

sed 's/\([A-Z]\)/ \1/g'

Captures each capital letter and substitutes a leading space with the capture for the whole stream.

$ echo "aCertainCamelCasedWord" | sed 's/\([A-Z]\)/ \1/g'
a Certain Camel Cased Word

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风和你 2024-07-21 12:06:29

如果您不需要拆分全部大写的单词，则此解决方案有效。例如，使用您将得到的最佳答案：

$ echo 'FAQPage' | sed 's/\([A-Z]\)/ \1/g' 
F A Q Page

但是使用我的解决方案，您将得到：

$ echo 'FAQPage' | sed 's/\([A-Z][^A-Z]\)/ \1/g'
FAQ Page

注意：当存在多个大写单词的第二个实例时，此方法无法正常工作，例如：

$ echo 'FAQPageOneReplacedByFAQPageTwo' | sed 's|\([A-Z][^A-Z]\)| \1|g'
FAQ Page One Replaced ByFAQ Page Two

This solution works if you need to not split up words that are all caps. For example, using the top answer you'll get:

$ echo 'FAQPage' | sed 's/\([A-Z]\)/ \1/g' 
F A Q Page

But instead with my solution, you'll get:

$ echo 'FAQPage' | sed 's/\([A-Z][^A-Z]\)/ \1/g'
FAQ Page

Note: This does not work correctly when there is a second instance of multiple uppercase words, for example:

$ echo 'FAQPageOneReplacedByFAQPageTwo' | sed 's|\([A-Z][^A-Z]\)| \1|g'
FAQ Page One Replaced ByFAQ Page Two

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谜泪 2024-07-21 12:06:29

此答案在存在第二个实例时无法正常工作多个大写

echo 'FAQPageOneReplacedByFAQPageTwo' | sed 's|\([A-Z][^A-Z]\)| \1|g'
FAQ Page One Replaced ByFAQ Page Two

So 且需要附加表达式

 echo 'FAQPageOneReplacedByFAQPageTwo' | sed -e 's|\([A-Z][^A-Z]\)| \1|g' -e 's|\([a-z]\)\([A-Z]\)|\1 \2|g'
 FAQ Page One Replaced By FAQ Page Two

This answer does not work correctly when there is a second instance of multiple uppercase

echo 'FAQPageOneReplacedByFAQPageTwo' | sed 's|\([A-Z][^A-Z]\)| \1|g'
FAQ Page One Replaced ByFAQ Page Two

So and additional expression is required for that

 echo 'FAQPageOneReplacedByFAQPageTwo' | sed -e 's|\([A-Z][^A-Z]\)| \1|g' -e 's|\([a-z]\)\([A-Z]\)|\1 \2|g'
 FAQ Page One Replaced By FAQ Page Two

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无敌元气妹 2024-07-21 12:06:29

纯 Bash：

name="aCertainCamelCasedWord"

declare -a word                                 # the word array

counter1=0                                      # count characters
counter2=0                                      # count words

while [ $counter1 -lt ${#name} ] ; do
  nextchar=${name:${counter1}:1}
  if [[ $nextchar =~ [[:upper:]] ]] ; then
    ((counter2++))
    word[${counter2}]=$nextchar
  else
    word[${counter2}]=${word[${counter2}]}$nextchar
  fi
  ((counter1++))
done

echo -e "'${word[@]}'"

Pure Bash:

name="aCertainCamelCasedWord"

declare -a word                                 # the word array

counter1=0                                      # count characters
counter2=0                                      # count words

while [ $counter1 -lt ${#name} ] ; do
  nextchar=${name:${counter1}:1}
  if [[ $nextchar =~ [[:upper:]] ]] ; then
    ((counter2++))
    word[${counter2}]=$nextchar
  else
    word[${counter2}]=${word[${counter2}]}$nextchar
  fi
  ((counter1++))
done

echo -e "'${word[@]}'"

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