条件在 XSLT 1.0 中？

发布于 2024-07-14 10:28:38 字数 1520 浏览 6 评论 0原文

我有一个 XSLT 1.0（2.0 不是一个选项）样式表，它生成 XHTML。它可以根据参数生成完整的 XHTML 有效的文档或只是一个

...

片段，用于包含在网页中。

我的问题是在这两个中生成不同的 XML 声明案例。对于独立页面，我需要：

<xsl:output doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
       doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>

对于

一个：

<xsl:output omit-xml-declaration="yes"/>

但是不能包含在 。它只能是的直接子级。

我看到的唯一解决方案是创建一个包含大多数模板的样式表，然后创建两个带有正确的的小“包装器”，这将主样式表。

我一直在寻找更好的主意，但显然没有。根据 Andrew Hare 和 jelovirt 的建议，我编写了两个“驱动程序”，两个简单的样式表，它们调用正确的，然后编写主样式表。以下是这些驱动程序之一，用于独立 HTML 的驱动程序：

<?xml version="1.0" encoding="us-ascii"?>
<!-- This file is intended to be used as the main stylesheet, it creates a 
 standalone Web page. 
-->
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

  <xsl:import href="traceroute2html.xsl"/>

  <xsl:param name="standalone" select="'true'"/>

  <xsl:output doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
      doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>

</xsl:stylesheet>

原文

I have an XSLT 1.0 (2.0 is not an option) stylesheet which produces
XHTML. It can, depending on a parameter, produce a full XHTML
validable document or just a <div>...</div> snippet, intended for
inclusion in a Web page.

My problem is to produce different XML declarations in these two
cases. For the standalone page, I need:

<xsl:output doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
       doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>

And for the <div> one:

<xsl:output omit-xml-declaration="yes"/>

But <xsl:output> cannot be included in an <xsl:if>. It can only be the direct child of <xsl:stylesheet>.

The only solution I see is to create a stylesheet with most of the templates and then two small "wrappers" with the right <xsl:output> and which will <xsl:import> the main stylesheet.

I was looking for a better idea but apparently there is none. Following advice from Andrew Hare and jelovirt, I wrote two "drivers", two simple stylesheets which call the proper <xsl:output> and then the main stylesheet. Here is one of these drivers, the one for standalone HTML:

<?xml version="1.0" encoding="us-ascii"?>
<!-- This file is intended to be used as the main stylesheet, it creates a 
 standalone Web page. 
-->
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

  <xsl:import href="traceroute2html.xsl"/>

  <xsl:param name="standalone" select="'true'"/>

  <xsl:output doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
      doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>

</xsl:stylesheet>

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不交电费瞎发啥光 2024-07-21 10:28:38

我最近不得不采用的另一个选择是：

在所有情况下省略 XML 声明。
有条件地，将声明输出为未转义文本。

如果您要输出到文件，这仅适用于 XSLT 1.0 和 2.0——如果您需要在同一遍中将输出处理为 XML，例如存储在变量中时，这将不起作用。

（请注意，XSLT 2.0 扩展函数可能可以一次性获取此输出并将其视为 XML，而 XSLT 3.0 有一个内置函数可将输入字符串解析为 XML。）

示例片段：

<!-- Omit the XML declaration as the base case:
    we can conditionally output a declaration 
    as text, but we *cannot* apply conditions on
    this `omit-xml-declaration` attribute here.  -->
<xsl:output method="xml" indent="no" 
    omit-xml-declaration="yes"
/>

<!-- Root element match: evaluate different cases, output XML declaration,
    XHTML DOCTYPE, or something else, then process the rest of the input. -->
<xsl:template match="/">
    <xsl:choose>
        <xsl:when test="'... some condition ...'">
            <xsl:text disable-output-escaping="yes"><?xml version="1.0" encoding="UTF-8"?></xsl:text>
        </xsl:when>
        <xsl:when test="'... some other condition ...'">
            <xsl:text disable-output-escaping="yes"><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"></xsl:text>
        </xsl:when>
        <xsl:otherwise>
            <!-- ... some third kind of output ... -->
        </xsl:otherwise>
    </xsl:choose>
    <!-- Just process the rest -->
    <xsl:apply-templates/>
</xsl:template>


... [ other code ] ...

Another option, which I recently had to employ, is to:

Omit the XML declaration in all cases.
Conditionally, output the declaration as unescaped text.

This only works in XSLT 1.0 and 2.0 if you're outputting to a file -- this won't work if you need to process the output as XML in the same pass, such as when storing in a variable.

(Note that XSLT 2.0 extension functions might make it possible to take this output and treat it as XML in one go, and XSLT 3.0 has a built-in function to parse an input string as XML.)

Example snippet:

<!-- Omit the XML declaration as the base case:
    we can conditionally output a declaration 
    as text, but we *cannot* apply conditions on
    this `omit-xml-declaration` attribute here.  -->
<xsl:output method="xml" indent="no" 
    omit-xml-declaration="yes"
/>

<!-- Root element match: evaluate different cases, output XML declaration,
    XHTML DOCTYPE, or something else, then process the rest of the input. -->
<xsl:template match="/">
    <xsl:choose>
        <xsl:when test="'... some condition ...'">
            <xsl:text disable-output-escaping="yes"><?xml version="1.0" encoding="UTF-8"?></xsl:text>
        </xsl:when>
        <xsl:when test="'... some other condition ...'">
            <xsl:text disable-output-escaping="yes"><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"></xsl:text>
        </xsl:when>
        <xsl:otherwise>
            <!-- ... some third kind of output ... -->
        </xsl:otherwise>
    </xsl:choose>
    <!-- Just process the rest -->
    <xsl:apply-templates/>
</xsl:template>


... [ other code ] ...

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