为什么FlexUnit中没有assertError()函数？

发布于 2024-07-14 09:34:44 字数 221 浏览 7 评论 0原文

似乎大多数 XUnit 测试框架都在您想要断言给定操作将抛出异常（或 AS3 术语中的错误）时提供断言。是否有一些我忽略的“标准”方法来执行此操作，这是否可以解释 FlexUnit 中缺少 assertError() 断言？

我知道如何实现这样的事情，并且我可能会将其添加到我的 FlexUnit 中（开源！），但这似乎是一个明显的遗漏，我想知道我是否只是做错了。

有人对此有什么想法吗？

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以可爱出名 2024-07-21 09:34:44

编辑 05/02/2010： 我现在建议使用 FlexUnit 4。它使用可扩展的元数据系统，支持预期的异常，并且还支持在不使用AIR的情况下在集成服务器环境中运行。

编辑：您应该查看fluint，这是由那些已经受够了 FlexUnit 及其局限性的人构建的。它可能内置了一些此类断言。

我完全同意。事实上，FlexUnit 缺少几个有用的方法（assertEvent、assertArrayEquals 等）。我知道你说过你知道如何实现它，但请随意使用我的：

public static function assertError(message : String, func : Function, errorClass : Class = null, errorMessage : String = null, errorCodes : Array = null) : Error 
{
    _assertionsMade++;

    if (errorClass == null) errorClass = Error;

    try
    {
        func();
    }
    catch(ex : Error)
    {
        if (!(ex is errorClass))
        {
            fail("Expected error of type '" + getQualifiedClassName(errorClass) + "' but was '" + getQualifiedClassName(ex) + "'");
        }

        if (errorMessage != null && ex.message != errorMessage)
        {
            fail("Expected error with message '" + errorMessage + "' but was '" + ex.message + "'");
        }

        if (errorCodes != null && errorCodes.indexOf(ex.errorID) == -1)
        {
            fail("Expected error with errorID '" + errorCodes.join(" or ") + "' but was '" + ex.errorID + "'");
        }

        return ex;
    }

    if (message == null)
    {
        message = "Expected error of type '" + getQualifiedClassName(errorClass) + "' but none was thrown"
    }

    fail(message);

    return null;
}

Edit 05/02/2010: I'd now recommend using FlexUnit 4. It uses an extensible metdata system, supports expected exceptions, and also supports running in an integration server environment without the use of AIR.

Edit: You should have a look at fluint, which was built by people who had enough of FlexUnit and it's limitations. It might have some of these types of assertions built in.

I totally agree. In fact, FlexUnit is missing several useful methods (assertEvent, assertArrayEquals, etc). I know you said you know how to implement it, but feel free to use mine:

public static function assertError(message : String, func : Function, errorClass : Class = null, errorMessage : String = null, errorCodes : Array = null) : Error 
{
    _assertionsMade++;

    if (errorClass == null) errorClass = Error;

    try
    {
        func();
    }
    catch(ex : Error)
    {
        if (!(ex is errorClass))
        {
            fail("Expected error of type '" + getQualifiedClassName(errorClass) + "' but was '" + getQualifiedClassName(ex) + "'");
        }

        if (errorMessage != null && ex.message != errorMessage)
        {
            fail("Expected error with message '" + errorMessage + "' but was '" + ex.message + "'");
        }

        if (errorCodes != null && errorCodes.indexOf(ex.errorID) == -1)
        {
            fail("Expected error with errorID '" + errorCodes.join(" or ") + "' but was '" + ex.errorID + "'");
        }

        return ex;
    }

    if (message == null)
    {
        message = "Expected error of type '" + getQualifiedClassName(errorClass) + "' but none was thrown"
    }

    fail(message);

    return null;
}

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为人所爱 2024-07-21 09:34:44

FlexUnit 4 与 hamcrest-as3 配合良好。 hamcrest 有错误断言匹配器

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您的好友蓝忘机已上羡 2024-07-21 09:34:44

您可能需要考虑使用这个断言工具。

它不会取代 xxxunit 框架，只是方便你做出断言，使它们更英文化，代码更少。

https://github.com/osher/should.as

var p:Person = new Person();

//assume a method p.sayHi()
p.sayHi.should().throwError('name is not set');

p.name = "Radagast";
p.sayHi.should().not.throwError();

玩得开心:)

You may want to consider using this assertion tool.

It does not replace the xxxunit framework, just facilitate the assertions you make, make them more English and less code.

https://github.com/osher/should.as

var p:Person = new Person();

//assume a method p.sayHi()
p.sayHi.should().throwError('name is not set');

p.name = "Radagast";
p.sayHi.should().not.throwError();

Have fun :)

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