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如何缩短 TSQL 中的长 UNION ALL 查询

发布于 2024-07-13 12:42:26 字数 1957 浏览 7 评论 0原文

我需要缩短这个查询，虽然我非常擅长 SQL，但我仍在学习中。

    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
        LEFT([Recipient-Address], 6) IN ('doejoh') 
UNION ALL 
    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
        LEFT([Recipient-Address], 10) IN ('john.doe@g') 
UNION ALL 
    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
            LEFT([Sender-Address], 6) IN ('doejoh') 
    UNION ALL 
    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
            LEFT([Sender-Address], 10) IN ('john.doe@g')
    ORDER BY
        DateTime

我必须使用这个联合，因为在同一个表中，每个用户及其电子邮件地址有 4 种不同的可能性。 也就是说，我有 30 个用户，因此在整个查询中 30x4 将是 120 个组。 第一列必须是用户名的原因是因为我在水晶报表中使用该列。

我只是想为我的查询创建一些逻辑来缩短查询，同时将每个用户“分配”到适当的第一列。

编辑添加

虽然这会缩短我的查询，但我仍然需要 30 个联合：

SELECT
   'doejoh',
   DATETIME,
   [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
   dbo.Logs 
WHERE
   LEFT([Recipient-Address], 6) IN ('doejoh') OR
   LEFT([Recipient-Address], 10) IN ('john.doe@g') OR
   LEFT([Sender-Address], 6) IN ('doejoh') OR
   LEFT([Sender-Address], 10) IN ('john.doe@g')
ORDER BY
   DateTime

因为下一个用户将与前一个用户联合：

UNION ALL 
SELECT
   'doejan',
   DATETIME,
   [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
   dbo.Logs 
WHERE
   LEFT([Recipient-Address], 6) IN ('doejan') OR
   LEFT([Recipient-Address], 10) IN ('jane.doe@g') OR
   LEFT([Sender-Address], 6) IN ('doejan') OR
   LEFT([Sender-Address], 10) IN ('jan.doe@g')

依此类推......任何更短方式？

原文

I need to shorten this query and while I'm pretty good at SQL, I'm still learning.

    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
        LEFT([Recipient-Address], 6) IN ('doejoh') 
UNION ALL 
    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
        LEFT([Recipient-Address], 10) IN ('john.doe@g') 
UNION ALL 
    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
            LEFT([Sender-Address], 6) IN ('doejoh') 
    UNION ALL 
    SELECT
        'doejoh',
        DATETIME,
        [Recipient-Address], [Message-Subject], [Sender-Address] 
    FROM
        dbo.Logs 
    WHERE
            LEFT([Sender-Address], 10) IN ('john.doe@g')
    ORDER BY
        DateTime

I have to use this union, because in the same table, there are 4 different possibilities for each user and their email address. That being said, I have 30 users, so 30x4 would be 120 groups in this entire query. The reason the first column has to be the username is because I'm using that column in a Crystal Report.

I'm just looking to create some logic for my query that will shorten it down, while at the same time, "assigning" each user to their appropriate first column.

Edited to add

While this will shorten my query, I'll still have to have 30 unions:

SELECT
   'doejoh',
   DATETIME,
   [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
   dbo.Logs 
WHERE
   LEFT([Recipient-Address], 6) IN ('doejoh') OR
   LEFT([Recipient-Address], 10) IN ('john.doe@g') OR
   LEFT([Sender-Address], 6) IN ('doejoh') OR
   LEFT([Sender-Address], 10) IN ('john.doe@g')
ORDER BY
   DateTime

Because the next user would be unioned to the previous one:

UNION ALL 
SELECT
   'doejan',
   DATETIME,
   [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
   dbo.Logs 
WHERE
   LEFT([Recipient-Address], 6) IN ('doejan') OR
   LEFT([Recipient-Address], 10) IN ('jane.doe@g') OR
   LEFT([Sender-Address], 6) IN ('doejan') OR
   LEFT([Sender-Address], 10) IN ('jan.doe@g')

And so on and so forth... any shorter way?

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评论（5）

虚拟世界 2024-07-20 12:42:26

您应该将查询重写为：

SELECT
   'doejoh',
   DATETIME,
   [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
   dbo.Logs 
WHERE
   LEFT([Recipient-Address], 6) IN ('doejoh') OR
   LEFT([Recipient-Address], 10) IN ('john.doe@g') OR
   LEFT([Sender-Address], 6) IN ('doejoh') OR
   LEFT([Sender-Address], 10) IN ('john.doe@g')
ORDER BY
   DateTime

我认为在选择方面应该是相同的，只是更快更容易理解一点。

马克

You should rewrite your query as:

SELECT
   'doejoh',
   DATETIME,
   [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
   dbo.Logs 
WHERE
   LEFT([Recipient-Address], 6) IN ('doejoh') OR
   LEFT([Recipient-Address], 10) IN ('john.doe@g') OR
   LEFT([Sender-Address], 6) IN ('doejoh') OR
   LEFT([Sender-Address], 10) IN ('john.doe@g')
ORDER BY
   DateTime

SHould be the same in terms of selection, just a bit faster and easier to understand, I think.

Marc

回复 原文
落花随流水 2024-07-20 12:42:26

这样的事情有什么理由行不通吗？

CREATE TABLE #TempNames
(
    shortname nvarchar(6),
    longname nvarchar(10)
)

INSERT INTO #TempNames (shortname, longname) VALUES('doejoh', 'john.doe@g')
INSERT INTO #TempNames (shortname, longname) VALUES('doejan', 'jan.doe@g')
INSERT INTO #TempNames (shortname, longname) VALUES('smibob', 'bob.smith@g')

SELECT
    #TempName.shortname,
    DATETIME,
    [Recipient-Address], [Message-Subject], [Sender-Address]
FROM
    dbo.Logs
INNER JOIN
    #TempNames
ON
    LEFT([Recipient-Address], 6) = #TempNames.shortname
OR
    LEFT([Recipient-Address], 10) = #TempNames.longname
OR
    LEFT([Sender-Address], 6) = #TempNames.shortname
OR
    LEFT([Sender-Address], 10) = #TempNames.longname

Is there a reason something like this won't work?

CREATE TABLE #TempNames
(
    shortname nvarchar(6),
    longname nvarchar(10)
)

INSERT INTO #TempNames (shortname, longname) VALUES('doejoh', 'john.doe@g')
INSERT INTO #TempNames (shortname, longname) VALUES('doejan', 'jan.doe@g')
INSERT INTO #TempNames (shortname, longname) VALUES('smibob', 'bob.smith@g')

SELECT
    #TempName.shortname,
    DATETIME,
    [Recipient-Address], [Message-Subject], [Sender-Address]
FROM
    dbo.Logs
INNER JOIN
    #TempNames
ON
    LEFT([Recipient-Address], 6) = #TempNames.shortname
OR
    LEFT([Recipient-Address], 10) = #TempNames.longname
OR
    LEFT([Sender-Address], 6) = #TempNames.shortname
OR
    LEFT([Sender-Address], 10) = #TempNames.longname
回复 原文
瑾兮 2024-07-20 12:42:26

创建一个映射表并加入其中。

例如。 就像是

select user_name, DateTime .... 
from Logs
join Users on 
   LEFT([Recipient-Address], 6) IN (user_name) OR
   LEFT([Recipient-Address], 10) IN (user_email) OR
   LEFT([Sender-Address], 6) IN (user_name) OR
   LEFT([Sender-Address], 10) IN (user_email)

create a mapping table and join to it.

eg. something like

select user_name, DateTime .... 
from Logs
join Users on 
   LEFT([Recipient-Address], 6) IN (user_name) OR
   LEFT([Recipient-Address], 10) IN (user_email) OR
   LEFT([Sender-Address], 6) IN (user_name) OR
   LEFT([Sender-Address], 10) IN (user_email)
回复 原文
薄暮涼年 2024-07-20 12:42:26

难道你不能只用...

SELECT
    'doejoh',
    DATETIME,
    [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
    dbo.Logs 
 WHERE
    (LEFT([Recipient-Address], 10) IN ('john.doe@g'))
or  (LEFT([Recipient-Address], 6) IN ('doejoh') )
or  ( LEFT([Sender-Address], 10) IN ('john.doe@g'))
or  (LEFT([Sender-Address], 6) IN ('doejoh') )

Can't you use just...

SELECT
    'doejoh',
    DATETIME,
    [Recipient-Address], [Message-Subject], [Sender-Address] 
FROM
    dbo.Logs 
 WHERE
    (LEFT([Recipient-Address], 10) IN ('john.doe@g'))
or  (LEFT([Recipient-Address], 6) IN ('doejoh') )
or  ( LEFT([Sender-Address], 10) IN ('john.doe@g'))
or  (LEFT([Sender-Address], 6) IN ('doejoh') )
回复 原文
并安 2024-07-20 12:42:26

创建一个包含 30 人的电子邮件地址的表。
表：电子邮件
列：short6、long10、email

，然后仅使用 1 个 union all

Select Emails.short6, Logs.DateTime, Logs.[Recipient-Address], Logs.[Message-Subject], Logs.[Sender-Address]
From Emails JOIN Log on Emails.email = Log.[Recipient-Address]
Where LEFT([Recipient-Address], 6) = Emails.short6 
or LEFT([Recipient-Address], 10) = Emails.long10

union all

Select Emails.short6, Logs.DateTime, Logs.[Recipient-Address], Logs.[Message-Subject], Logs.[Sender-Address]
From Emails JOIN Log on Emails.email = Log.[Sender-Address]
Where LEFT([Sender-Address], 6) = Emails.short6 
or LEFT([Sender-Address], 10) = Emails.long10

Create a table with the email address of the 30 people.
Table: Emails
Columns: short6, long10, email

then using only 1 union all

Select Emails.short6, Logs.DateTime, Logs.[Recipient-Address], Logs.[Message-Subject], Logs.[Sender-Address]
From Emails JOIN Log on Emails.email = Log.[Recipient-Address]
Where LEFT([Recipient-Address], 6) = Emails.short6 
or LEFT([Recipient-Address], 10) = Emails.long10

union all

Select Emails.short6, Logs.DateTime, Logs.[Recipient-Address], Logs.[Message-Subject], Logs.[Sender-Address]
From Emails JOIN Log on Emails.email = Log.[Sender-Address]
Where LEFT([Sender-Address], 6) = Emails.short6 
or LEFT([Sender-Address], 10) = Emails.long10
回复 原文
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