使用 Windows 虚拟邮件服务器发送带有标头返回路径的电子邮件

发布于 2024-07-12 09:12:58 字数 1067 浏览 12 评论 0原文

我正在尝试使用 .NET MailMessage 类发送电子邮件,该类还可以添加返回路径标头,以便任何退回邮件都会返回到不同的电子邮件地址。 代码如下:

MailMessage mm = new MailMessage(
    new MailAddress(string.Format("{0}<{1}>", email.FromName, email.FromEmail)), 
    new MailAddress(emailTo));

mm.Subject = ReplaceValues(email.Subject, nameValues);
mm.ReplyTo = new MailAddress(string.Format("{0}<{1}>", email.FromName, email.FromEmail));
mm.Headers.Add("Return-Path", ReturnEmail);

// Set the email html and plain text
// Removed because it is unneccsary for this example

// Now setup the smtp server
SmtpClient smtp = new SmtpClient();
smtp.Host = SmtpServer;
smtp.DeliveryMethod = SmtpDeliveryMethod.PickupDirectoryFromIis;

if (SmtpUsername.Length > 0)
{
    System.Net.NetworkCredential theCredential = 
        new System.Net.NetworkCredential(SmtpUsername, SmtpPassword);
    smtp.Credentials = theCredential;
}

smtp.Send(mm);

每当我检查发送的电子邮件时,我都会检查标头,它似乎总是缺少返回路径。 我是否缺少某些内容来正确配置它? 正如我上面所说,我在我的开发计算机 (XP) 上使用标准虚拟邮件服务器,但它最终将在 Windows 2003 上运行。

有谁知道为什么它没有通过吗?

I'm trying to send an email message using the .NET MailMessage class which can also have the return-path header added so that any bounces come back to a different email address. Code is below:

MailMessage mm = new MailMessage(
    new MailAddress(string.Format("{0}<{1}>", email.FromName, email.FromEmail)), 
    new MailAddress(emailTo));

mm.Subject = ReplaceValues(email.Subject, nameValues);
mm.ReplyTo = new MailAddress(string.Format("{0}<{1}>", email.FromName, email.FromEmail));
mm.Headers.Add("Return-Path", ReturnEmail);

// Set the email html and plain text
// Removed because it is unneccsary for this example

// Now setup the smtp server
SmtpClient smtp = new SmtpClient();
smtp.Host = SmtpServer;
smtp.DeliveryMethod = SmtpDeliveryMethod.PickupDirectoryFromIis;

if (SmtpUsername.Length > 0)
{
    System.Net.NetworkCredential theCredential = 
        new System.Net.NetworkCredential(SmtpUsername, SmtpPassword);
    smtp.Credentials = theCredential;
}

smtp.Send(mm);

Whenever I check the email that was sent I check the header and it always seems to be missing return-path. Is there something I am missing to configure this correctly? As I said above I'm using the standard Virtual Mail Server on my development machine (XP) however it will run on Windows 2003 eventually.

Has anyone got any ideas why it isn't coming through?

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相权↑美人 2024-07-19 09:12:58

返回路径是根据 SMTP MAIL FROM 信封设置的。 您可以使用 Sender 属性来执行此类操作。
您迟早会遇到有关相关问题的另一次讨论:如何使用 System.Net.Mail 设置 SMTP 信封 MAIL FROM?

顺便说一句,如果您使用 SmtpDeliveryMethod.PickupDirectoryFromIis,则 Sender 属性不会用作 MAIL FROM; 你必须使用网络作为传递方式来保持这个值。
我没有找到此问题的任何解决方法。
PickupDirectoryFromIis、Sender 属性和 SMTP MAIL FROM 信封

The Return-Path is set based on the SMTP MAIL FROM Envelope. You can use the Sender property to do such a thing.
Another discussion on a related issue you will have sooner or later: How can you set the SMTP envelope MAIL FROM using System.Net.Mail?

And btw, if you use SmtpDeliveryMethod.PickupDirectoryFromIis, the Sender property is not used as a MAIL FROM; you have to use Network as a delivery method to keep this value.
I did not find any workaround for this issue.
PickupDirectoryFromIis, Sender property and SMTP MAIL FROM envelope

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