你能用 LaTeX 迭代吗？

发布于 2024-07-10 15:16:52 字数 894 浏览 5 评论 0原文

我是 LaTeX 的新手，我必须说我真的很挣扎。我发现 \newcommand 命令有点像常规编程语言中的函数/方法。你可以给它论据和一切。

但我想知道，我可以以某种方式在 LaTeX 中迭代吗？基本上，我想做的是创建一个包含 N+1 列的表格，其中第一行仅包含一个空白单元格，然后其他列中包含数字 1, 2, ..., N。我只想将 N 作为这个“函数”（newcommand）的参数。

这是一个可能看起来像我正在寻找的东西的示例（尽管显然这不起作用）：

\newcommand{\mytable}[2]{  
\begin{tabular}{l|*{#1}{c|}} % table with first argument+1 columns  
  for(int i = 1; i &lt;= #1; i++) "& i" % 'output' numbers in different columns  
  \\\hline  
  letters & #2 % second argument should contain actual content for row  
  \\\hline  
\end{tabular}  
}

调用它：

\mytable{3}{a & b & c}

输出应该是：

        | 1 | 2 | 3 |
--------+---+---+---+
letters | a | b | c |
--------+---+---+---+

有谁知道这样的事情是否可能？

谢谢！

原文

I'm new to LaTeX and I must say that I am really struggling with it. I discovered the \newcommand command that is kind of like a function/method in regular programming languages. You can give it arguments and everything.

I was wondering though, can I somehow iterate in LaTeX? Basically, what I would like to do is create a table with N+1 columns where the first row just contains a blank cell and then the numbers 1, 2, ..., N in the other columns. I only want to give N as an argument to this 'function' (newcommand).

Here is an example of something that might look like what I'm looking for (although obviously this won't work):

\newcommand{\mytable}[2]{  
\begin{tabular}{l|*{#1}{c|}} % table with first argument+1 columns  
  for(int i = 1; i <= #1; i++) "& i" % 'output' numbers in different columns  
  \\\hline  
  letters & #2 % second argument should contain actual content for row  
  \\\hline  
\end{tabular}  
}

Call it with:

\mytable{3}{a & b & c}

Output should be:

        | 1 | 2 | 3 |
--------+---+---+---+
letters | a | b | c |
--------+---+---+---+

Does anyone know if something like this is possible?

Thanks!

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澉约 2024-07-17 15:16:52

只需将以下内容放入新命令中，并确保使用包 ifthen 即可。

\begin{tabular}{l|*{10}{c|}}
\newcounter{count}
\whiledo{\value{count}<10}{
\ifthenelse{\value{count}=0}{}{\the\value{count}}
\ifthenelse{\value{count}<9}{&}{\\}
\stepcounter{count}
}
letters&a&b&c&d&e&f&g&h&i\\
\end{tabular}

Just make the following into a new command and be sure to use package ifthen.

\begin{tabular}{l|*{10}{c|}}
\newcounter{count}
\whiledo{\value{count}<10}{
\ifthenelse{\value{count}=0}{}{\the\value{count}}
\ifthenelse{\value{count}<9}{&}{\\}
\stepcounter{count}
}
letters&a&b&c&d&e&f&g&h&i\\
\end{tabular}

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