在Python中N个单词后分割HTML

发布于 2024-07-10 08:14:48 字数 712 浏览 4 评论 0原文

有没有办法将一长串HTML后的N个单词分割开？显然我可以使用：

' '.join(foo.split(' ')[:n])

获取纯文本字符串的前 n 个单词，但这可能会在 html 标签中间分开，并且不会生成有效的 html，因为它不会关闭已打开的标签。

我需要在 zope / plone 站点中执行此操作 - 如果这些产品中存在可以执行此操作的标准内容，那将是理想的。

例如，假设我有文本：

<p>This is some text with a 
  <a href="http://www.example.com/" title="Example link">
     bit of linked text in it
  </a>.
</p>

我要求它在 5 个单词后分割，它应该返回：

<p>This is some text with</p>

7 个单词：

<p>This is some text with a 
  <a href="http://www.example.com/" title="Example link">
     bit
  </a>
</p>

原文

Is there any way to split a long string of HTML after N words? Obviously I could use:

' '.join(foo.split(' ')[:n])

to get the first n words of a plain text string, but that might split in the middle of an html tag, and won't produce valid html because it won't close the tags that have been opened.

I need to do this in a zope / plone site - if there is something as standard in those products that can do it, that would be ideal.

For example, say I have the text:

<p>This is some text with a 
  <a href="http://www.example.com/" title="Example link">
     bit of linked text in it
  </a>.
</p>

And I ask it to split after 5 words, it should return:

<p>This is some text with</p>

7 words:

<p>This is some text with a 
  <a href="http://www.example.com/" title="Example link">
     bit
  </a>
</p>

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徒留西风 2024-07-17 08:14:48

看一下 django.utils 中的 truncate_html_words 函数。文本。即使您不使用 Django，那里的代码也完全可以满足您的需求。

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攒一口袋星星 2024-07-17 08:14:48

我听说 Beautiful Soup 非常擅长解析 html。它可能能够帮助您获得正确的 html。

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阳光的暖冬 2024-07-17 08:14:48

我要提到的是用 Python 构建的基本 HTMLParser ，因为我不确定你想要达到的最终结果是什么，它可能会也可能不会让你到达那里，你将主要与处理程序一起工作

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爱你是孤单的心事 2024-07-17 08:14:48

您可以混合使用正则表达式、BeautifulSoup 或 Tidy（我更喜欢 BeautifulSoup）。
这个想法很简单——首先去除所有 HTML 标签。找到第 n 个单词（这里 n=7），找到第 n 个单词在字符串中出现的次数，直到 n 个单词 - 因为你只查找最后一个出现的单词以用于截断。

这是一段代码，虽然有点混乱但有效

import re
from BeautifulSoup import BeautifulSoup
import tidy

def remove_html_tags(data):
    p = re.compile(r'<.*?>')
    return p.sub('', data)

input_string='<p>This is some text with a <a href="http://www.example.com/" '\
    'title="Example link">bit of linked text in it</a></p>'

s=remove_html_tags(input_string).split(' ')[:7]

###required to ensure that only the last occurrence of the nth word is                                                                                      
#  taken into account for truncating.                                                                                                                       
#  coz if the nth word could be 'a'/'and'/'is'....etc                                                                                                       
#  which may occur multiple times within n words                                                                                                            
temp=input_string
k=s.count(s[-1])
i=1
j=0
while i<=k:
    j+=temp.find(s[-1])
    temp=temp[j+len(s[-1]):]
    i+=1
####                                                                                                                                                        
output_string=input_string[:j+len(s[-1])]

print "\nBeautifulSoup\n", BeautifulSoup(output_string)
print "\nTidy\n", tidy.parseString(output_string)

输出就是你想要的

BeautifulSoup
<p>This is some text with a <a href="http://www.example.com/" title="Example link">bit</a></p>

Tidy
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 3.2//EN">
<html>
<head>
<meta name="generator" content=
"HTML Tidy for Linux/x86 (vers 6 November 2007), see www.w3.org">
<title></title>
</head>
<body>
<p>This is some text with a <a href="http://www.example.com/"
title="Example link">bit</a></p>
</body>
</html>

希望这有助于

编辑：更好的正则表达式

`p = re.compile(r'<[^<]*?>')`

You can use a mix of regex, BeautifulSoup or Tidy (I prefer BeautifulSoup).
The idea is simple - strip all the HTML tags first. Find the nth word (n=7 here), find the number of times the nth word appears in the string till n words - coz u are looking only for the last occurrence to be used for truncation.

Here is a piece of code, though a bit messy but works

import re
from BeautifulSoup import BeautifulSoup
import tidy

def remove_html_tags(data):
    p = re.compile(r'<.*?>')
    return p.sub('', data)

input_string='<p>This is some text with a <a href="http://www.example.com/" '\
    'title="Example link">bit of linked text in it</a></p>'

s=remove_html_tags(input_string).split(' ')[:7]

###required to ensure that only the last occurrence of the nth word is                                                                                      
#  taken into account for truncating.                                                                                                                       
#  coz if the nth word could be 'a'/'and'/'is'....etc                                                                                                       
#  which may occur multiple times within n words                                                                                                            
temp=input_string
k=s.count(s[-1])
i=1
j=0
while i<=k:
    j+=temp.find(s[-1])
    temp=temp[j+len(s[-1]):]
    i+=1
####                                                                                                                                                        
output_string=input_string[:j+len(s[-1])]

print "\nBeautifulSoup\n", BeautifulSoup(output_string)
print "\nTidy\n", tidy.parseString(output_string)

The output is what u want

BeautifulSoup
<p>This is some text with a <a href="http://www.example.com/" title="Example link">bit</a></p>

Tidy
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 3.2//EN">
<html>
<head>
<meta name="generator" content=
"HTML Tidy for Linux/x86 (vers 6 November 2007), see www.w3.org">
<title></title>
</head>
<body>
<p>This is some text with a <a href="http://www.example.com/"
title="Example link">bit</a></p>
</body>
</html>

Hope this helps

Edit: A better regex