RedirectStandardOutput 是缓冲行而不是瞬时的？

发布于 2024-07-08 02:46:05 字数 1290 浏览 10 评论 0原文

好的，我正在尝试使用 Tail 来监视日志文件，但是我无法以编程方式获得与使用相同参数通过 cmd 提示符手动运行它时相同的行为。

当通过 cmd 提示符运行时，它会立即显示新行。不过，从编程角度来说，在“缓冲区”释放所有行之前，我必须等待日志文件中大约75+新行。

这是我现在的代码。

private const string tailExecutable = @"C:\tail.exe";
private const string logFile = @"C:\test.log";

private static void ReadStdOut()
{
    var psi = new ProcessStartInfo
    {
        FileName = tailExecutable,
        Arguments = String.Format("-f \"{0}\"", logFile),
        UseShellExecute = false,
        RedirectStandardOutput = true
    };

    // Running same exe -args through cmd.exe 
    // works perfectly, but not programmatically.
    Console.WriteLine("{0} {1}", psi.FileName, psi.Arguments);

    var tail = new Process();
    tail.StartInfo = psi;
    tail.OutputDataReceived += tail_OutputDataReceived;
    tail.Start();
    tail.BeginOutputReadLine();
}

static void tail_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
    Console.WriteLine(e.Data);
}

我以前使用过 OutputDataReceived 事件，但从未遇到过这些缓冲/垃圾邮件问题。

我现在很困惑。

* 编辑 *

我在CodeProject上找到了这个wintail项目我将切换到这个，因为缓冲区使这个解决方案太慢了。

感谢您的回答。

原文

Ok, I am trying to use Tail to monitor a log file, but I cannot get the same behavior programatically as when I manually run it through cmd prompt using the same parameters.

When run through cmd prompt it displays the new lines instantly. Programatically though, I have to wait for about 75+ new lines in log file before the 'buffer' unleashes all the lines.

Here's the code I have now.

private const string tailExecutable = @"C:\tail.exe";
private const string logFile = @"C:\test.log";

private static void ReadStdOut()
{
    var psi = new ProcessStartInfo
    {
        FileName = tailExecutable,
        Arguments = String.Format("-f \"{0}\"", logFile),
        UseShellExecute = false,
        RedirectStandardOutput = true
    };

    // Running same exe -args through cmd.exe 
    // works perfectly, but not programmatically.
    Console.WriteLine("{0} {1}", psi.FileName, psi.Arguments);

    var tail = new Process();
    tail.StartInfo = psi;
    tail.OutputDataReceived += tail_OutputDataReceived;
    tail.Start();
    tail.BeginOutputReadLine();
}

static void tail_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
    Console.WriteLine(e.Data);
}

I have used the OutputDataReceived event before but never had these buffering/spamming problems.

I am so confused with about right now.