当前位置：文江博客话题详情

在 MSSQL 2000 中如何确定某列是否为标识列？

发布于 2024-07-07 18:24:18 字数 32 浏览 6 评论 0原文

我想在代码中执行此操作，而不是使用 ALT+F1。

原文

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

荒人说梦 2024-07-14 18:24:19

在 Sql Server 2016 中，您可以通过查询 sys.all_columns 表来检查字段是否是同一字段：

SELECT * from sys.all_columns where object_id = OBJECT_ID('TableName') AND [Name] = 'ColumnName' AND is_identity = 1

In Sql Server 2016 you can check if a field is identity by querying against the sys.all_columns table:

SELECT * from sys.all_columns where object_id = OBJECT_ID('TableName') AND [Name] = 'ColumnName' AND is_identity = 1

回复收藏 0 原文

傻比既视感 2024-07-14 18:24:18

您也可以这样做：

select columnproperty(object_id('mytable'),'mycolumn','IsIdentity')

如果它是一个恒等则返回 1，否则返回 0。

You can also do it this way:

select columnproperty(object_id('mytable'),'mycolumn','IsIdentity')

Returns 1 if it's an identity, 0 if not.

回复收藏 0 原文

中二柚 2024-07-14 18:24:18

sp_help tablename

在输出中查找类似以下内容：

 Identity     Seed     Increment     Not For Replication    
 -----------  -------  ------------  ---------------------- 
 userid       15500    1             0

sp_help tablename

In the output look for something like this:

 Identity     Seed     Increment     Not For Replication    
 -----------  -------  ------------  ---------------------- 
 userid       15500    1             0

回复收藏 0 原文

英雄似剑 2024-07-14 18:24:18

调整 WHERE 子句以适应：

select
    a.name as TableName,
    b.name as IdentityColumn
from
    sysobjects a inner join syscolumns b on a.id = b.id
where
    columnproperty(a.id, b.name, 'isIdentity') = 1
    and objectproperty(a.id, 'isTable') = 1

Adjust the WHERE clause to suit:

select
    a.name as TableName,
    b.name as IdentityColumn
from
    sysobjects a inner join syscolumns b on a.id = b.id
where
    columnproperty(a.id, b.name, 'isIdentity') = 1
    and objectproperty(a.id, 'isTable') = 1

回复收藏 0 原文

终难愈 2024-07-14 18:24:18

作为 @Blogbeard 答案的扩展

如果您喜欢纯查询而不是内置函数

select col_name(sys.all_objects.object_id, column_id) as id from sys.identity_columns 
join sys.all_objects on sys.identity_columns.object_id = sys.all_objects.object_id
where sys.all_objects.name = 'system_files'

As expansion on @Blogbeard's answer

If you like pure query and not inbuilt functions

select col_name(sys.all_objects.object_id, column_id) as id from sys.identity_columns 
join sys.all_objects on sys.identity_columns.object_id = sys.all_objects.object_id
where sys.all_objects.name = 'system_files'

回复收藏 0 原文