C# 中的自然排序顺序

发布于 2024-07-07 18:04:16 字数 100 浏览 12 评论 0原文

任何人都有好的资源或提供 C# 中 FileInfo 数组的自然顺序排序的示例吗? 我正在按我的方式实现 IComparer 接口。

Anyone have a good resource or provide a sample of a natural order sort in C# for an FileInfo array? I am implementing the IComparer interface in my sorts.

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墟烟 2024-07-14 18:04:17

我们需要一种自然的排序来处理具有以下模式的文本:

"Test 1-1-1 something"
"Test 1-2-3 something"
...

出于某种原因,当我第一次查看 SO 时,我没有找到这篇文章并实现了我们自己的。 与这里提出的一些解决方案相比,虽然概念相似,但它的优点是更简单、更容易理解。 然而,虽然我确实尝试查看性能瓶颈,但它的实现仍然比默认的 OrderBy() 慢得多。

这是我实现的扩展方法:

public static class EnumerableExtensions
{
    // set up the regex parser once and for all
    private static readonly Regex Regex = new Regex(@"\d+|\D+", RegexOptions.Compiled | RegexOptions.Singleline);

    // stateless comparer can be built once
    private static readonly AggregateComparer Comparer = new AggregateComparer();

    public static IEnumerable<T> OrderByNatural<T>(this IEnumerable<T> source, Func<T, string> selector)
    {
        // first extract string from object using selector
        // then extract digit and non-digit groups
        Func<T, IEnumerable<IComparable>> splitter =
            s => Regex.Matches(selector(s))
                      .Cast<Match>()
                      .Select(m => Char.IsDigit(m.Value[0]) ? (IComparable) int.Parse(m.Value) : m.Value);
        return source.OrderBy(splitter, Comparer);
    }

    /// <summary>
    /// This comparer will compare two lists of objects against each other
    /// </summary>
    /// <remarks>Objects in each list are compare to their corresponding elements in the other
    /// list until a difference is found.</remarks>
    private class AggregateComparer : IComparer<IEnumerable<IComparable>>
    {
        public int Compare(IEnumerable<IComparable> x, IEnumerable<IComparable> y)
        {
            return
                x.Zip(y, (a, b) => new {a, b})              // walk both lists
                 .Select(pair => pair.a.CompareTo(pair.b))  // compare each object
                 .FirstOrDefault(result => result != 0);    // until a difference is found
        }
    }
}

想法是将原始字符串拆分为数字和非数字块(“\d+|\D+”)。 由于这是一项潜在昂贵的任务,因此每个条目仅执行一次。 然后我们使用可比较对象的比较器(抱歉,我找不到更合适的方式来表达它)。 它将每个块与另一个字符串中相应的块进行比较。

我希望得到有关如何改进以及主要缺陷是什么的反馈。 请注意,此时可维护性对我们来说很重要,并且我们目前没有在非常大的数据集中使用它。

We had a need for a natural sort to deal with text with the following pattern:

"Test 1-1-1 something"
"Test 1-2-3 something"
...

For some reason when I first looked on SO, I didn't find this post and implemented our own. Compared to some of the solutions presented here, while similar in concept, it could have the benefit of maybe being simpler and easier to understand. However, while I did try to look at performance bottlenecks, It is still a much slower implementation than the default OrderBy().

Here is the extension method I implement:

public static class EnumerableExtensions
{
    // set up the regex parser once and for all
    private static readonly Regex Regex = new Regex(@"\d+|\D+", RegexOptions.Compiled | RegexOptions.Singleline);

    // stateless comparer can be built once
    private static readonly AggregateComparer Comparer = new AggregateComparer();

    public static IEnumerable<T> OrderByNatural<T>(this IEnumerable<T> source, Func<T, string> selector)
    {
        // first extract string from object using selector
        // then extract digit and non-digit groups
        Func<T, IEnumerable<IComparable>> splitter =
            s => Regex.Matches(selector(s))
                      .Cast<Match>()
                      .Select(m => Char.IsDigit(m.Value[0]) ? (IComparable) int.Parse(m.Value) : m.Value);
        return source.OrderBy(splitter, Comparer);
    }

    /// <summary>
    /// This comparer will compare two lists of objects against each other
    /// </summary>
    /// <remarks>Objects in each list are compare to their corresponding elements in the other
    /// list until a difference is found.</remarks>
    private class AggregateComparer : IComparer<IEnumerable<IComparable>>
    {
        public int Compare(IEnumerable<IComparable> x, IEnumerable<IComparable> y)
        {
            return
                x.Zip(y, (a, b) => new {a, b})              // walk both lists
                 .Select(pair => pair.a.CompareTo(pair.b))  // compare each object
                 .FirstOrDefault(result => result != 0);    // until a difference is found
        }
    }
}

The idea is to split the original strings into blocks of digits and non-digits ("\d+|\D+"). Since this is a potentially expensive task, it is done only once per entry. We then use a comparer of comparable objects (sorry, I can't find a more proper way to say it). It compares each block to its corresponding block in the other string.

I would like feedback on how this could be improved and what the major flaws are. Note that maintainability is important to us at this point and we are not currently using this in extremely large data sets.

王权女流氓 2024-07-14 18:04:17

如果您想按名称(自然)排序并按照数字正确排序

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

public class Book
{
    public int Id { get; set; }
    public string Title { get; set; }
}

public class BookComparer : IComparer<Book>
{
    public int Compare(Book x, Book y)
    {
        var matchX = Regex.Match(x.Title, @"([^\d]+)(\d+)");
        var matchY = Regex.Match(y.Title, @"([^\d]+)(\d+)");

        var result = string.Compare(matchX.Groups[1].Value, matchY.Groups[1].Value, StringComparison.Ordinal);

        if (result == 0)
        {
            // If the prefixes are the same, compare numeric parts
            result = int.Parse(matchX.Groups[2].Value).CompareTo(int.Parse(matchY.Groups[2].Value));
        }

        return result;
    }
}

class Program
{
    static void Main()
    {
        var list = new List<Book>
        {
            new Book { Id = 49, Title = "Test 10" },
            new Book { Id = 50, Title = "Test 101" },
            new Book { Id = 43, Title = "Test 11" },
            new Book { Id = 48, Title = "Test 100" }
        };

        var ordered = list.OrderBy(m => m, new BookComparer()).Select(x => x.Title);

        var str = string.Join(", ", ordered);
        Console.WriteLine(str);
    }
}

If you want to order by name (natural) with correct order in terms of numeric

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

public class Book
{
    public int Id { get; set; }
    public string Title { get; set; }
}

public class BookComparer : IComparer<Book>
{
    public int Compare(Book x, Book y)
    {
        var matchX = Regex.Match(x.Title, @"([^\d]+)(\d+)");
        var matchY = Regex.Match(y.Title, @"([^\d]+)(\d+)");

        var result = string.Compare(matchX.Groups[1].Value, matchY.Groups[1].Value, StringComparison.Ordinal);

        if (result == 0)
        {
            // If the prefixes are the same, compare numeric parts
            result = int.Parse(matchX.Groups[2].Value).CompareTo(int.Parse(matchY.Groups[2].Value));
        }

        return result;
    }
}

class Program
{
    static void Main()
    {
        var list = new List<Book>
        {
            new Book { Id = 49, Title = "Test 10" },
            new Book { Id = 50, Title = "Test 101" },
            new Book { Id = 43, Title = "Test 11" },
            new Book { Id = 48, Title = "Test 100" }
        };

        var ordered = list.OrderBy(m => m, new BookComparer()).Select(x => x.Title);

        var str = string.Join(", ", ordered);
        Console.WriteLine(str);
    }
}
舞袖。长 2024-07-14 18:04:17

尚未提及的另一个良好的自然排序资源是 NuGet NaturalSort.Extension 包。 它得到积极维护,在撰写本文时下载量已超过一百万次。 源代码可在 GitHub 中获取。

Another good natural-sort resource not yet mentioned is the NuGet NaturalSort.Extension package. It's actively maintained and has over one million downloads at the time of this writing. The source code is available in GitHub.

几味少女 2024-07-14 18:04:17

让我解释一下我的问题以及我如何解决它。

问题:- 根据从目录检索的 FileInfo 对象中的 FileName 对文件进行排序。

解决方案:- 我从 FileInfo 中选择了文件名并修剪了文件名的“.png”部分。 现在,只需执行 List.Sort(),它按自然排序顺序对文件名进行排序。 根据我的测试,我发现 .png 会打乱排序顺序。 看看下面的代码

var imageNameList = new DirectoryInfo(@"C:\Temp\Images").GetFiles("*.png").Select(x =>x.Name.Substring(0, x.Name.Length - 4)).ToList();
imageNameList.Sort();

Let me explain my problem and how i was able to solve it.

Problem:- Sort files based on FileName from FileInfo objects which are retrieved from a Directory.

Solution:- I selected the file names from FileInfo and trimed the ".png" part of the file name. Now, just do List.Sort(), which sorts the filenames in Natural sorting order. Based on my testing i found that having .png messes up sorting order. Have a look at the below code

var imageNameList = new DirectoryInfo(@"C:\Temp\Images").GetFiles("*.png").Select(x =>x.Name.Substring(0, x.Name.Length - 4)).ToList();
imageNameList.Sort();
浪菊怪哟 2024-07-14 18:04:16

最简单的事情就是 P/Invoke Windows 中的内置函数,并将其用作 IComparer 中的比较函数:

[DllImport("shlwapi.dll", CharSet = CharSet.Unicode)]
private static extern int StrCmpLogicalW(string psz1, string psz2);

Michael Kaplan 有一些 此处提供了此功能如何工作的示例,以及为使其工作更直观而对 Vista 所做的更改。 此功能的优点是,它将具有与其运行的 Windows 版本相同的行为,但这确实意味着它在 Windows 版本之间有所不同,因此您需要考虑这对您来说是否是一个问题。

所以一个完整的实现应该是这样的:

[SuppressUnmanagedCodeSecurity]
internal static class SafeNativeMethods
{
    [DllImport("shlwapi.dll", CharSet = CharSet.Unicode)]
    public static extern int StrCmpLogicalW(string psz1, string psz2);
}

public sealed class NaturalStringComparer : IComparer<string>
{
    public int Compare(string a, string b)
    {
        return SafeNativeMethods.StrCmpLogicalW(a, b);
    }
}

public sealed class NaturalFileInfoNameComparer : IComparer<FileInfo>
{
    public int Compare(FileInfo a, FileInfo b)
    {
        return SafeNativeMethods.StrCmpLogicalW(a.Name, b.Name);
    }
}

The easiest thing to do is just P/Invoke the built-in function in Windows, and use it as the comparison function in your IComparer:

[DllImport("shlwapi.dll", CharSet = CharSet.Unicode)]
private static extern int StrCmpLogicalW(string psz1, string psz2);

Michael Kaplan has some examples of how this function works here, and the changes that were made for Vista to make it work more intuitively. The plus side of this function is that it will have the same behaviour as the version of Windows it runs on, however this does mean that it differs between versions of Windows so you need to consider whether this is a problem for you.

So a complete implementation would be something like:

[SuppressUnmanagedCodeSecurity]
internal static class SafeNativeMethods
{
    [DllImport("shlwapi.dll", CharSet = CharSet.Unicode)]
    public static extern int StrCmpLogicalW(string psz1, string psz2);
}

public sealed class NaturalStringComparer : IComparer<string>
{
    public int Compare(string a, string b)
    {
        return SafeNativeMethods.StrCmpLogicalW(a, b);
    }
}

public sealed class NaturalFileInfoNameComparer : IComparer<FileInfo>
{
    public int Compare(FileInfo a, FileInfo b)
    {
        return SafeNativeMethods.StrCmpLogicalW(a.Name, b.Name);
    }
}
心是晴朗的。 2024-07-14 18:04:16

只是想我会添加到此(使用我能找到的最简洁的解决方案):

public static IOrderedEnumerable<T> OrderByAlphaNumeric<T>(this IEnumerable<T> source, Func<T, string> selector)
{
    int max = source
        .SelectMany(i => Regex.Matches(selector(i), @"\d+").Cast<Match>().Select(m => (int?)m.Value.Length))
        .Max() ?? 0;

    return source.OrderBy(i => Regex.Replace(selector(i), @"\d+", m => m.Value.PadLeft(max, '0')));
}

上面将字符串中的任何数字填充到所有字符串中所有数字的最大长度,并使用结果字符串进行排序。

转换为 (int?) 是为了允许不带任何数字的字符串集合(空枚举上的 .Max() 会抛出 InvalidOperationException )。

Just thought I'd add to this (with the most concise solution I could find):

public static IOrderedEnumerable<T> OrderByAlphaNumeric<T>(this IEnumerable<T> source, Func<T, string> selector)
{
    int max = source
        .SelectMany(i => Regex.Matches(selector(i), @"\d+").Cast<Match>().Select(m => (int?)m.Value.Length))
        .Max() ?? 0;

    return source.OrderBy(i => Regex.Replace(selector(i), @"\d+", m => m.Value.PadLeft(max, '0')));
}

The above pads any numbers in the string to the max length of all numbers in all strings and uses the resulting string to sort.

The cast to (int?) is to allow for collections of strings without any numbers (.Max() on an empty enumerable throws an InvalidOperationException).

三生一梦 2024-07-14 18:04:16

现有的实现看起来都不是很好,所以我编写了自己的实现。 结果与现代版本的 Windows 资源管理器 (Windows 7/8) 使用的排序几乎相同。 我看到的唯一区别是 1) 尽管 Windows 过去(例如 XP)可以处理任意长度的数字,但现在仅限于 19 位数字 - 我的是无限的,2)Windows 给出的结果与某些 Unicode 数字集不一致 - 我的工作很好(尽管它不会在数字上比较代理项对中的数字;Windows 也不会),并且 3) 我的无法区分不同类型的非主要排序权重,如果它们出现在不同的部分中(例如“e-1é”与“ é1e-" - 数字之前和之后的部分有变音符号和标点符号重量差异)。

public static int CompareNatural(string strA, string strB) {
    return CompareNatural(strA, strB, CultureInfo.CurrentCulture, CompareOptions.IgnoreCase);
}

public static int CompareNatural(string strA, string strB, CultureInfo culture, CompareOptions options) {
    CompareInfo cmp = culture.CompareInfo;
    int iA = 0;
    int iB = 0;
    int softResult = 0;
    int softResultWeight = 0;
    while (iA < strA.Length && iB < strB.Length) {
        bool isDigitA = Char.IsDigit(strA[iA]);
        bool isDigitB = Char.IsDigit(strB[iB]);
        if (isDigitA != isDigitB) {
            return cmp.Compare(strA, iA, strB, iB, options);
        }
        else if (!isDigitA && !isDigitB) {
            int jA = iA + 1;
            int jB = iB + 1;
            while (jA < strA.Length && !Char.IsDigit(strA[jA])) jA++;
            while (jB < strB.Length && !Char.IsDigit(strB[jB])) jB++;
            int cmpResult = cmp.Compare(strA, iA, jA - iA, strB, iB, jB - iB, options);
            if (cmpResult != 0) {
                // Certain strings may be considered different due to "soft" differences that are
                // ignored if more significant differences follow, e.g. a hyphen only affects the
                // comparison if no other differences follow
                string sectionA = strA.Substring(iA, jA - iA);
                string sectionB = strB.Substring(iB, jB - iB);
                if (cmp.Compare(sectionA + "1", sectionB + "2", options) ==
                    cmp.Compare(sectionA + "2", sectionB + "1", options))
                {
                    return cmp.Compare(strA, iA, strB, iB, options);
                }
                else if (softResultWeight < 1) {
                    softResult = cmpResult;
                    softResultWeight = 1;
                }
            }
            iA = jA;
            iB = jB;
        }
        else {
            char zeroA = (char)(strA[iA] - (int)Char.GetNumericValue(strA[iA]));
            char zeroB = (char)(strB[iB] - (int)Char.GetNumericValue(strB[iB]));
            int jA = iA;
            int jB = iB;
            while (jA < strA.Length && strA[jA] == zeroA) jA++;
            while (jB < strB.Length && strB[jB] == zeroB) jB++;
            int resultIfSameLength = 0;
            do {
                isDigitA = jA < strA.Length && Char.IsDigit(strA[jA]);
                isDigitB = jB < strB.Length && Char.IsDigit(strB[jB]);
                int numA = isDigitA ? (int)Char.GetNumericValue(strA[jA]) : 0;
                int numB = isDigitB ? (int)Char.GetNumericValue(strB[jB]) : 0;
                if (isDigitA && (char)(strA[jA] - numA) != zeroA) isDigitA = false;
                if (isDigitB && (char)(strB[jB] - numB) != zeroB) isDigitB = false;
                if (isDigitA && isDigitB) {
                    if (numA != numB && resultIfSameLength == 0) {
                        resultIfSameLength = numA < numB ? -1 : 1;
                    }
                    jA++;
                    jB++;
                }
            }
            while (isDigitA && isDigitB);
            if (isDigitA != isDigitB) {
                // One number has more digits than the other (ignoring leading zeros) - the longer
                // number must be larger
                return isDigitA ? 1 : -1;
            }
            else if (resultIfSameLength != 0) {
                // Both numbers are the same length (ignoring leading zeros) and at least one of
                // the digits differed - the first difference determines the result
                return resultIfSameLength;
            }
            int lA = jA - iA;
            int lB = jB - iB;
            if (lA != lB) {
                // Both numbers are equivalent but one has more leading zeros
                return lA > lB ? -1 : 1;
            }
            else if (zeroA != zeroB && softResultWeight < 2) {
                softResult = cmp.Compare(strA, iA, 1, strB, iB, 1, options);
                softResultWeight = 2;
            }
            iA = jA;
            iB = jB;
        }
    }
    if (iA < strA.Length || iB < strB.Length) {
        return iA < strA.Length ? 1 : -1;
    }
    else if (softResult != 0) {
        return softResult;
    }
    return 0;
}

签名与 Comparison 委托匹配:

string[] files = Directory.GetFiles(@"C:\");
Array.Sort(files, CompareNatural);

这是一个用作 IComparer 的包装类:

public class CustomComparer<T> : IComparer<T> {
    private Comparison<T> _comparison;

    public CustomComparer(Comparison<T> comparison) {
        _comparison = comparison;
    }

    public int Compare(T x, T y) {
        return _comparison(x, y);
    }
}

示例:

string[] files = Directory.EnumerateFiles(@"C:\")
    .OrderBy(f => f, new CustomComparer<string>(CompareNatural))
    .ToArray();

这是我用于测试的一组很好的文件名:

Func<string, string> expand = (s) => { int o; while ((o = s.IndexOf('\\')) != -1) { int p = o + 1;
    int z = 1; while (s[p] == '0') { z++; p++; } int c = Int32.Parse(s.Substring(p, z));
    s = s.Substring(0, o) + new string(s[o - 1], c) + s.Substring(p + z); } return s; };
string encodedFileNames =
    "KDEqLW4xMiotbjEzKjAwMDFcMDY2KjAwMlwwMTcqMDA5XDAxNyowMlwwMTcqMDlcMDE3KjEhKjEtISox" +
    "LWEqMS4yNT8xLjI1KjEuNT8xLjUqMSoxXDAxNyoxXDAxOCoxXDAxOSoxXDA2NioxXDA2NyoxYSoyXDAx" +
    "NyoyXDAxOCo5XDAxNyo5XDAxOCo5XDA2Nio9MSphMDAxdGVzdDAxKmEwMDF0ZXN0aW5nYTBcMzEqYTAw" +
    "Mj9hMDAyIGE/YTAwMiBhKmEwMDIqYTAwMmE/YTAwMmEqYTAxdGVzdGluZ2EwMDEqYTAxdnNmcyphMSph" +
    "MWEqYTF6KmEyKmIwMDAzcTYqYjAwM3E0KmIwM3E1KmMtZSpjZCpjZipmIDEqZipnP2cgMT9oLW4qaG8t" +
    "bipJKmljZS1jcmVhbT9pY2VjcmVhbT9pY2VjcmVhbS0/ajBcNDE/ajAwMWE/ajAxP2shKmsnKmstKmsx" +
    "KmthKmxpc3QqbTAwMDNhMDA1YSptMDAzYTAwMDVhKm0wMDNhMDA1Km0wMDNhMDA1YSpuMTIqbjEzKm8t" +
    "bjAxMypvLW4xMipvLW40P28tbjQhP28tbjR6P28tbjlhLWI1Km8tbjlhYjUqb24wMTMqb24xMipvbjQ/" +
    "b240IT9vbjR6P29uOWEtYjUqb245YWI1Km/CrW4wMTMqb8KtbjEyKnAwMCpwMDEqcDAxwr0hKnAwMcK9" +
    "KnAwMcK9YSpwMDHCvcK+KnAwMipwMMK9KnEtbjAxMypxLW4xMipxbjAxMypxbjEyKnItMDAhKnItMDAh" +
    "NSpyLTAwIe+8lSpyLTAwYSpyLe+8kFwxIS01KnIt77yQXDEhLe+8lSpyLe+8kFwxISpyLe+8kFwxITUq" +
    "ci3vvJBcMSHvvJUqci3vvJBcMWEqci3vvJBcMyE1KnIwMCEqcjAwLTUqcjAwLjUqcjAwNSpyMDBhKnIw" +
    "NSpyMDYqcjQqcjUqctmg2aYqctmkKnLZpSpy27Dbtipy27Qqctu1KnLfgN+GKnLfhCpy34UqcuClpuCl" +
    "rCpy4KWqKnLgpasqcuCnpuCnrCpy4KeqKnLgp6sqcuCppuCprCpy4KmqKnLgqasqcuCrpuCrrCpy4Kuq" +
    "KnLgq6sqcuCtpuCtrCpy4K2qKnLgrasqcuCvpuCvrCpy4K+qKnLgr6sqcuCxpuCxrCpy4LGqKnLgsasq" +
    "cuCzpuCzrCpy4LOqKnLgs6sqcuC1puC1rCpy4LWqKnLgtasqcuC5kOC5lipy4LmUKnLguZUqcuC7kOC7" +
    "lipy4LuUKnLgu5UqcuC8oOC8pipy4LykKnLgvKUqcuGBgOGBhipy4YGEKnLhgYUqcuGCkOGClipy4YKU" +
    "KnLhgpUqcuGfoOGfpipy4Z+kKnLhn6UqcuGgkOGglipy4aCUKnLhoJUqcuGlhuGljCpy4aWKKnLhpYsq" +
    "cuGnkOGnlipy4aeUKnLhp5UqcuGtkOGtlipy4a2UKnLhrZUqcuGusOGutipy4a60KnLhrrUqcuGxgOGx" +
    "hipy4bGEKnLhsYUqcuGxkOGxlipy4bGUKnLhsZUqcuqYoFwx6pilKnLqmKDqmKUqcuqYoOqYpipy6pik" +
    "KnLqmKUqcuqjkOqjlipy6qOUKnLqo5UqcuqkgOqkhipy6qSEKnLqpIUqcuqpkOqplipy6qmUKnLqqZUq" +
    "cvCQkqAqcvCQkqUqcvCdn5gqcvCdn50qcu+8kFwxISpy77yQXDEt77yVKnLvvJBcMS7vvJUqcu+8kFwx" +
    "YSpy77yQXDHqmKUqcu+8kFwx77yO77yVKnLvvJBcMe+8lSpy77yQ77yVKnLvvJDvvJYqcu+8lCpy77yV" +
    "KnNpKnPEsSp0ZXN02aIqdGVzdNmi2aAqdGVzdNmjKnVBZS0qdWFlKnViZS0qdUJlKnVjZS0xw6kqdWNl" +
    "McOpLSp1Y2Uxw6kqdWPDqS0xZSp1Y8OpMWUtKnVjw6kxZSp3ZWlhMSp3ZWlhMip3ZWlzczEqd2Vpc3My" +
    "KndlaXoxKndlaXoyKndlacOfMSp3ZWnDnzIqeSBhMyp5IGE0KnknYTMqeSdhNCp5K2EzKnkrYTQqeS1h" +
    "Myp5LWE0KnlhMyp5YTQqej96IDA1MD96IDIxP3ohMjE/ejIwP3oyMj96YTIxP3rCqTIxP1sxKl8xKsKt" +
    "bjEyKsKtbjEzKsSwKg==";
string[] fileNames = Encoding.UTF8.GetString(Convert.FromBase64String(encodedFileNames))
    .Replace("*", ".txt?").Split(new[] { "?" }, StringSplitOptions.RemoveEmptyEntries)
    .Select(n => expand(n)).ToArray();

None of the existing implementations looked great so I wrote my own. The results are almost identical to the sorting used by modern versions of Windows Explorer (Windows 7/8). The only differences I've seen are 1) although Windows used to (e.g. XP) handle numbers of any length, it's now limited to 19 digits - mine is unlimited, 2) Windows gives inconsistent results with certain sets of Unicode digits - mine works fine (although it doesn't numerically compare digits from surrogate pairs; nor does Windows), and 3) mine can't distinguish different types of non-primary sort weights if they occur in different sections (e.g. "e-1é" vs "é1e-" - the sections before and after the number have diacritic and punctuation weight differences).

public static int CompareNatural(string strA, string strB) {
    return CompareNatural(strA, strB, CultureInfo.CurrentCulture, CompareOptions.IgnoreCase);
}

public static int CompareNatural(string strA, string strB, CultureInfo culture, CompareOptions options) {
    CompareInfo cmp = culture.CompareInfo;
    int iA = 0;
    int iB = 0;
    int softResult = 0;
    int softResultWeight = 0;
    while (iA < strA.Length && iB < strB.Length) {
        bool isDigitA = Char.IsDigit(strA[iA]);
        bool isDigitB = Char.IsDigit(strB[iB]);
        if (isDigitA != isDigitB) {
            return cmp.Compare(strA, iA, strB, iB, options);
        }
        else if (!isDigitA && !isDigitB) {
            int jA = iA + 1;
            int jB = iB + 1;
            while (jA < strA.Length && !Char.IsDigit(strA[jA])) jA++;
            while (jB < strB.Length && !Char.IsDigit(strB[jB])) jB++;
            int cmpResult = cmp.Compare(strA, iA, jA - iA, strB, iB, jB - iB, options);
            if (cmpResult != 0) {
                // Certain strings may be considered different due to "soft" differences that are
                // ignored if more significant differences follow, e.g. a hyphen only affects the
                // comparison if no other differences follow
                string sectionA = strA.Substring(iA, jA - iA);
                string sectionB = strB.Substring(iB, jB - iB);
                if (cmp.Compare(sectionA + "1", sectionB + "2", options) ==
                    cmp.Compare(sectionA + "2", sectionB + "1", options))
                {
                    return cmp.Compare(strA, iA, strB, iB, options);
                }
                else if (softResultWeight < 1) {
                    softResult = cmpResult;
                    softResultWeight = 1;
                }
            }
            iA = jA;
            iB = jB;
        }
        else {
            char zeroA = (char)(strA[iA] - (int)Char.GetNumericValue(strA[iA]));
            char zeroB = (char)(strB[iB] - (int)Char.GetNumericValue(strB[iB]));
            int jA = iA;
            int jB = iB;
            while (jA < strA.Length && strA[jA] == zeroA) jA++;
            while (jB < strB.Length && strB[jB] == zeroB) jB++;
            int resultIfSameLength = 0;
            do {
                isDigitA = jA < strA.Length && Char.IsDigit(strA[jA]);
                isDigitB = jB < strB.Length && Char.IsDigit(strB[jB]);
                int numA = isDigitA ? (int)Char.GetNumericValue(strA[jA]) : 0;
                int numB = isDigitB ? (int)Char.GetNumericValue(strB[jB]) : 0;
                if (isDigitA && (char)(strA[jA] - numA) != zeroA) isDigitA = false;
                if (isDigitB && (char)(strB[jB] - numB) != zeroB) isDigitB = false;
                if (isDigitA && isDigitB) {
                    if (numA != numB && resultIfSameLength == 0) {
                        resultIfSameLength = numA < numB ? -1 : 1;
                    }
                    jA++;
                    jB++;
                }
            }
            while (isDigitA && isDigitB);
            if (isDigitA != isDigitB) {
                // One number has more digits than the other (ignoring leading zeros) - the longer
                // number must be larger
                return isDigitA ? 1 : -1;
            }
            else if (resultIfSameLength != 0) {
                // Both numbers are the same length (ignoring leading zeros) and at least one of
                // the digits differed - the first difference determines the result
                return resultIfSameLength;
            }
            int lA = jA - iA;
            int lB = jB - iB;
            if (lA != lB) {
                // Both numbers are equivalent but one has more leading zeros
                return lA > lB ? -1 : 1;
            }
            else if (zeroA != zeroB && softResultWeight < 2) {
                softResult = cmp.Compare(strA, iA, 1, strB, iB, 1, options);
                softResultWeight = 2;
            }
            iA = jA;
            iB = jB;
        }
    }
    if (iA < strA.Length || iB < strB.Length) {
        return iA < strA.Length ? 1 : -1;
    }
    else if (softResult != 0) {
        return softResult;
    }
    return 0;
}

The signature matches the Comparison<string> delegate:

string[] files = Directory.GetFiles(@"C:\");
Array.Sort(files, CompareNatural);

Here's a wrapper class for use as IComparer<string>:

public class CustomComparer<T> : IComparer<T> {
    private Comparison<T> _comparison;

    public CustomComparer(Comparison<T> comparison) {
        _comparison = comparison;
    }

    public int Compare(T x, T y) {
        return _comparison(x, y);
    }
}

Example:

string[] files = Directory.EnumerateFiles(@"C:\")
    .OrderBy(f => f, new CustomComparer<string>(CompareNatural))
    .ToArray();

Here's a good set of filenames I use for testing:

Func<string, string> expand = (s) => { int o; while ((o = s.IndexOf('\\')) != -1) { int p = o + 1;
    int z = 1; while (s[p] == '0') { z++; p++; } int c = Int32.Parse(s.Substring(p, z));
    s = s.Substring(0, o) + new string(s[o - 1], c) + s.Substring(p + z); } return s; };
string encodedFileNames =
    "KDEqLW4xMiotbjEzKjAwMDFcMDY2KjAwMlwwMTcqMDA5XDAxNyowMlwwMTcqMDlcMDE3KjEhKjEtISox" +
    "LWEqMS4yNT8xLjI1KjEuNT8xLjUqMSoxXDAxNyoxXDAxOCoxXDAxOSoxXDA2NioxXDA2NyoxYSoyXDAx" +
    "NyoyXDAxOCo5XDAxNyo5XDAxOCo5XDA2Nio9MSphMDAxdGVzdDAxKmEwMDF0ZXN0aW5nYTBcMzEqYTAw" +
    "Mj9hMDAyIGE/YTAwMiBhKmEwMDIqYTAwMmE/YTAwMmEqYTAxdGVzdGluZ2EwMDEqYTAxdnNmcyphMSph" +
    "MWEqYTF6KmEyKmIwMDAzcTYqYjAwM3E0KmIwM3E1KmMtZSpjZCpjZipmIDEqZipnP2cgMT9oLW4qaG8t" +
    "bipJKmljZS1jcmVhbT9pY2VjcmVhbT9pY2VjcmVhbS0/ajBcNDE/ajAwMWE/ajAxP2shKmsnKmstKmsx" +
    "KmthKmxpc3QqbTAwMDNhMDA1YSptMDAzYTAwMDVhKm0wMDNhMDA1Km0wMDNhMDA1YSpuMTIqbjEzKm8t" +
    "bjAxMypvLW4xMipvLW40P28tbjQhP28tbjR6P28tbjlhLWI1Km8tbjlhYjUqb24wMTMqb24xMipvbjQ/" +
    "b240IT9vbjR6P29uOWEtYjUqb245YWI1Km/CrW4wMTMqb8KtbjEyKnAwMCpwMDEqcDAxwr0hKnAwMcK9" +
    "KnAwMcK9YSpwMDHCvcK+KnAwMipwMMK9KnEtbjAxMypxLW4xMipxbjAxMypxbjEyKnItMDAhKnItMDAh" +
    "NSpyLTAwIe+8lSpyLTAwYSpyLe+8kFwxIS01KnIt77yQXDEhLe+8lSpyLe+8kFwxISpyLe+8kFwxITUq" +
    "ci3vvJBcMSHvvJUqci3vvJBcMWEqci3vvJBcMyE1KnIwMCEqcjAwLTUqcjAwLjUqcjAwNSpyMDBhKnIw" +
    "NSpyMDYqcjQqcjUqctmg2aYqctmkKnLZpSpy27Dbtipy27Qqctu1KnLfgN+GKnLfhCpy34UqcuClpuCl" +
    "rCpy4KWqKnLgpasqcuCnpuCnrCpy4KeqKnLgp6sqcuCppuCprCpy4KmqKnLgqasqcuCrpuCrrCpy4Kuq" +
    "KnLgq6sqcuCtpuCtrCpy4K2qKnLgrasqcuCvpuCvrCpy4K+qKnLgr6sqcuCxpuCxrCpy4LGqKnLgsasq" +
    "cuCzpuCzrCpy4LOqKnLgs6sqcuC1puC1rCpy4LWqKnLgtasqcuC5kOC5lipy4LmUKnLguZUqcuC7kOC7" +
    "lipy4LuUKnLgu5UqcuC8oOC8pipy4LykKnLgvKUqcuGBgOGBhipy4YGEKnLhgYUqcuGCkOGClipy4YKU" +
    "KnLhgpUqcuGfoOGfpipy4Z+kKnLhn6UqcuGgkOGglipy4aCUKnLhoJUqcuGlhuGljCpy4aWKKnLhpYsq" +
    "cuGnkOGnlipy4aeUKnLhp5UqcuGtkOGtlipy4a2UKnLhrZUqcuGusOGutipy4a60KnLhrrUqcuGxgOGx" +
    "hipy4bGEKnLhsYUqcuGxkOGxlipy4bGUKnLhsZUqcuqYoFwx6pilKnLqmKDqmKUqcuqYoOqYpipy6pik" +
    "KnLqmKUqcuqjkOqjlipy6qOUKnLqo5UqcuqkgOqkhipy6qSEKnLqpIUqcuqpkOqplipy6qmUKnLqqZUq" +
    "cvCQkqAqcvCQkqUqcvCdn5gqcvCdn50qcu+8kFwxISpy77yQXDEt77yVKnLvvJBcMS7vvJUqcu+8kFwx" +
    "YSpy77yQXDHqmKUqcu+8kFwx77yO77yVKnLvvJBcMe+8lSpy77yQ77yVKnLvvJDvvJYqcu+8lCpy77yV" +
    "KnNpKnPEsSp0ZXN02aIqdGVzdNmi2aAqdGVzdNmjKnVBZS0qdWFlKnViZS0qdUJlKnVjZS0xw6kqdWNl" +
    "McOpLSp1Y2Uxw6kqdWPDqS0xZSp1Y8OpMWUtKnVjw6kxZSp3ZWlhMSp3ZWlhMip3ZWlzczEqd2Vpc3My" +
    "KndlaXoxKndlaXoyKndlacOfMSp3ZWnDnzIqeSBhMyp5IGE0KnknYTMqeSdhNCp5K2EzKnkrYTQqeS1h" +
    "Myp5LWE0KnlhMyp5YTQqej96IDA1MD96IDIxP3ohMjE/ejIwP3oyMj96YTIxP3rCqTIxP1sxKl8xKsKt" +
    "bjEyKsKtbjEzKsSwKg==";
string[] fileNames = Encoding.UTF8.GetString(Convert.FromBase64String(encodedFileNames))
    .Replace("*", ".txt?").Split(new[] { "?" }, StringSplitOptions.RemoveEmptyEntries)
    .Select(n => expand(n)).ToArray();
养猫人 2024-07-14 18:04:16

马修斯霍斯利的答案是最快的方法,它不会根据程序运行的 Windows 版本而改变行为。 但是,通过创建一次正则表达式并使用 RegexOptions.Compiled 甚至可以更快。 我还添加了插入字符串比较器的选项,以便您可以在需要时忽略大小写,并稍微提高了可读性。

    public static IEnumerable<T> OrderByNatural<T>(this IEnumerable<T> items, Func<T, string> selector, StringComparer stringComparer = null)
    {
        var regex = new Regex(@"\d+", RegexOptions.Compiled);

        int maxDigits = items
                      .SelectMany(i => regex.Matches(selector(i)).Cast<Match>().Select(digitChunk => (int?)digitChunk.Value.Length))
                      .Max() ?? 0;

        return items.OrderBy(i => regex.Replace(selector(i), match => match.Value.PadLeft(maxDigits, '0')), stringComparer ?? StringComparer.CurrentCulture);
    }

使用方式

var sortedEmployees = employees.OrderByNatural(emp => emp.Name);

对 100,000 个字符串进行排序需要 450 毫秒,而默认的 .net 字符串比较需要 300 毫秒 - 相当快!

Matthews Horsleys answer is the fastest method which doesn't change behaviour depending on which version of windows your program is running on. However, it can be even faster by creating the regex once, and using RegexOptions.Compiled. I also added the option of inserting a string comparer so you can ignore case if needed, and improved readability a bit.

    public static IEnumerable<T> OrderByNatural<T>(this IEnumerable<T> items, Func<T, string> selector, StringComparer stringComparer = null)
    {
        var regex = new Regex(@"\d+", RegexOptions.Compiled);

        int maxDigits = items
                      .SelectMany(i => regex.Matches(selector(i)).Cast<Match>().Select(digitChunk => (int?)digitChunk.Value.Length))
                      .Max() ?? 0;

        return items.OrderBy(i => regex.Replace(selector(i), match => match.Value.PadLeft(maxDigits, '0')), stringComparer ?? StringComparer.CurrentCulture);
    }

Use by

var sortedEmployees = employees.OrderByNatural(emp => emp.Name);

This takes 450ms to sort 100,000 strings compared to 300ms for the default .net string comparison - pretty fast!

仅一夜美梦 2024-07-14 18:04:16

linq orderby 的纯 C# 解决方案:

http:// Zootfroot.blogspot.com/2009/09/natural-sort-compare-with-linq-orderby.html

public class NaturalSortComparer<T> : IComparer<string>, IDisposable
{
    private bool isAscending;

    public NaturalSortComparer(bool inAscendingOrder = true)
    {
        this.isAscending = inAscendingOrder;
    }

    #region IComparer<string> Members

    public int Compare(string x, string y)
    {
        throw new NotImplementedException();
    }

    #endregion

    #region IComparer<string> Members

    int IComparer<string>.Compare(string x, string y)
    {
        if (x == y)
            return 0;

        string[] x1, y1;

        if (!table.TryGetValue(x, out x1))
        {
            x1 = Regex.Split(x.Replace(" ", ""), "([0-9]+)");
            table.Add(x, x1);
        }

        if (!table.TryGetValue(y, out y1))
        {
            y1 = Regex.Split(y.Replace(" ", ""), "([0-9]+)");
            table.Add(y, y1);
        }

        int returnVal;

        for (int i = 0; i < x1.Length && i < y1.Length; i++)
        {
            if (x1[i] != y1[i])
            {
                returnVal = PartCompare(x1[i], y1[i]);
                return isAscending ? returnVal : -returnVal;
            }
        }

        if (y1.Length > x1.Length)
        {
            returnVal = 1;
        }
        else if (x1.Length > y1.Length)
        { 
            returnVal = -1; 
        }
        else
        {
            returnVal = 0;
        }

        return isAscending ? returnVal : -returnVal;
    }

    private static int PartCompare(string left, string right)
    {
        int x, y;
        if (!int.TryParse(left, out x))
            return left.CompareTo(right);

        if (!int.TryParse(right, out y))
            return left.CompareTo(right);

        return x.CompareTo(y);
    }

    #endregion

    private Dictionary<string, string[]> table = new Dictionary<string, string[]>();

    public void Dispose()
    {
        table.Clear();
        table = null;
    }
}

Pure C# solution for linq orderby:

http://zootfroot.blogspot.com/2009/09/natural-sort-compare-with-linq-orderby.html

public class NaturalSortComparer<T> : IComparer<string>, IDisposable
{
    private bool isAscending;

    public NaturalSortComparer(bool inAscendingOrder = true)
    {
        this.isAscending = inAscendingOrder;
    }

    #region IComparer<string> Members

    public int Compare(string x, string y)
    {
        throw new NotImplementedException();
    }

    #endregion

    #region IComparer<string> Members

    int IComparer<string>.Compare(string x, string y)
    {
        if (x == y)
            return 0;

        string[] x1, y1;

        if (!table.TryGetValue(x, out x1))
        {
            x1 = Regex.Split(x.Replace(" ", ""), "([0-9]+)");
            table.Add(x, x1);
        }

        if (!table.TryGetValue(y, out y1))
        {
            y1 = Regex.Split(y.Replace(" ", ""), "([0-9]+)");
            table.Add(y, y1);
        }

        int returnVal;

        for (int i = 0; i < x1.Length && i < y1.Length; i++)
        {
            if (x1[i] != y1[i])
            {
                returnVal = PartCompare(x1[i], y1[i]);
                return isAscending ? returnVal : -returnVal;
            }
        }

        if (y1.Length > x1.Length)
        {
            returnVal = 1;
        }
        else if (x1.Length > y1.Length)
        { 
            returnVal = -1; 
        }
        else
        {
            returnVal = 0;
        }

        return isAscending ? returnVal : -returnVal;
    }

    private static int PartCompare(string left, string right)
    {
        int x, y;
        if (!int.TryParse(left, out x))
            return left.CompareTo(right);

        if (!int.TryParse(right, out y))
            return left.CompareTo(right);

        return x.CompareTo(y);
    }

    #endregion

    private Dictionary<string, string[]> table = new Dictionary<string, string[]>();

    public void Dispose()
    {
        table.Clear();
        table = null;
    }
}
烟柳画桥 2024-07-14 18:04:16

我的解决方案:

void Main()
{
    new[] {"a4","a3","a2","a10","b5","b4","b400","1","C1d","c1d2"}.OrderBy(x => x, new NaturalStringComparer()).Dump();
}

public class NaturalStringComparer : IComparer<string>
{
    private static readonly Regex _re = new Regex(@"(?<=\D)(?=\d)|(?<=\d)(?=\D)", RegexOptions.Compiled);

    public int Compare(string x, string y)
    {
        x = x.ToLower();
        y = y.ToLower();
        if(string.Compare(x, 0, y, 0, Math.Min(x.Length, y.Length)) == 0)
        {
            if(x.Length == y.Length) return 0;
            return x.Length < y.Length ? -1 : 1;
        }
        var a = _re.Split(x);
        var b = _re.Split(y);
        int i = 0;
        while(true)
        {
            int r = PartCompare(a[i], b[i]);
            if(r != 0) return r;
            ++i;
        }
    }

    private static int PartCompare(string x, string y)
    {
        int a, b;
        if(int.TryParse(x, out a) && int.TryParse(y, out b))
            return a.CompareTo(b);
        return x.CompareTo(y);
    }
}

结果:

1
a2
a3
a4
a10
b4
b5
b400
C1d
c1d2

My solution:

void Main()
{
    new[] {"a4","a3","a2","a10","b5","b4","b400","1","C1d","c1d2"}.OrderBy(x => x, new NaturalStringComparer()).Dump();
}

public class NaturalStringComparer : IComparer<string>
{
    private static readonly Regex _re = new Regex(@"(?<=\D)(?=\d)|(?<=\d)(?=\D)", RegexOptions.Compiled);

    public int Compare(string x, string y)
    {
        x = x.ToLower();
        y = y.ToLower();
        if(string.Compare(x, 0, y, 0, Math.Min(x.Length, y.Length)) == 0)
        {
            if(x.Length == y.Length) return 0;
            return x.Length < y.Length ? -1 : 1;
        }
        var a = _re.Split(x);
        var b = _re.Split(y);
        int i = 0;
        while(true)
        {
            int r = PartCompare(a[i], b[i]);
            if(r != 0) return r;
            ++i;
        }
    }

    private static int PartCompare(string x, string y)
    {
        int a, b;
        if(int.TryParse(x, out a) && int.TryParse(y, out b))
            return a.CompareTo(b);
        return x.CompareTo(y);
    }
}

Results:

1
a2
a3
a4
a10
b4
b5
b400
C1d
c1d2
橘亓 2024-07-14 18:04:16

这是 .NET Core 2.1+ / .NET 5.0+ 的版本,使用跨度来避免分配

public class NaturalSortStringComparer : IComparer<string>
{
    public static NaturalSortStringComparer Ordinal { get; } = new NaturalSortStringComparer(StringComparison.Ordinal);
    public static NaturalSortStringComparer OrdinalIgnoreCase { get; } = new NaturalSortStringComparer(StringComparison.OrdinalIgnoreCase);
    public static NaturalSortStringComparer CurrentCulture { get; } = new NaturalSortStringComparer(StringComparison.CurrentCulture);
    public static NaturalSortStringComparer CurrentCultureIgnoreCase { get; } = new NaturalSortStringComparer(StringComparison.CurrentCultureIgnoreCase);
    public static NaturalSortStringComparer InvariantCulture { get; } = new NaturalSortStringComparer(StringComparison.InvariantCulture);
    public static NaturalSortStringComparer InvariantCultureIgnoreCase { get; } = new NaturalSortStringComparer(StringComparison.InvariantCultureIgnoreCase);

    private readonly StringComparison _comparison;

    public NaturalSortStringComparer(StringComparison comparison)
    {
        _comparison = comparison;
    }

    public int Compare(string x, string y)
    {
        // Let string.Compare handle the case where x or y is null
        if (x is null || y is null)
            return string.Compare(x, y, _comparison);

        var xSegments = GetSegments(x);
        var ySegments = GetSegments(y);

        while (xSegments.MoveNext() && ySegments.MoveNext())
        {
            int cmp;

            // If they're both numbers, compare the value
            if (xSegments.CurrentIsNumber && ySegments.CurrentIsNumber)
            {
                var xValue = long.Parse(xSegments.Current);
                var yValue = long.Parse(ySegments.Current);
                cmp = xValue.CompareTo(yValue);
                if (cmp != 0)
                    return cmp;
            }
            // If x is a number and y is not, x is "lesser than" y
            else if (xSegments.CurrentIsNumber)
            {
                return -1;
            }
            // If y is a number and x is not, x is "greater than" y
            else if (ySegments.CurrentIsNumber)
            {
                return 1;
            }

            // OK, neither are number, compare the segments as text
            cmp = xSegments.Current.CompareTo(ySegments.Current, _comparison);
            if (cmp != 0)
                return cmp;
        }

        // At this point, either all segments are equal, or one string is shorter than the other

        // If x is shorter, it's "lesser than" y
        if (x.Length < y.Length)
            return -1;
        // If x is longer, it's "greater than" y
        if (x.Length > y.Length)
            return 1;

        // If they have the same length, they're equal
        return 0;
    }

    private static StringSegmentEnumerator GetSegments(string s) => new StringSegmentEnumerator(s);

    private struct StringSegmentEnumerator
    {
        private readonly string _s;
        private int _start;
        private int _length;

        public StringSegmentEnumerator(string s)
        {
            _s = s;
            _start = -1;
            _length = 0;
            CurrentIsNumber = false;
        }

        public ReadOnlySpan<char> Current => _s.AsSpan(_start, _length);
        
        public bool CurrentIsNumber { get; private set; }

        public bool MoveNext()
        {
            var currentPosition = _start >= 0
                ? _start + _length
                : 0;

            if (currentPosition >= _s.Length)
                return false;

            int start = currentPosition;
            bool isFirstCharDigit = Char.IsDigit(_s[currentPosition]);

            while (++currentPosition < _s.Length && Char.IsDigit(_s[currentPosition]) == isFirstCharDigit)
            {
            }

            _start = start;
            _length = currentPosition - start;
            CurrentIsNumber = isFirstCharDigit;

            return true;
        }
    }
}

Here's a version for .NET Core 2.1+ / .NET 5.0+, using spans to avoid allocations

public class NaturalSortStringComparer : IComparer<string>
{
    public static NaturalSortStringComparer Ordinal { get; } = new NaturalSortStringComparer(StringComparison.Ordinal);
    public static NaturalSortStringComparer OrdinalIgnoreCase { get; } = new NaturalSortStringComparer(StringComparison.OrdinalIgnoreCase);
    public static NaturalSortStringComparer CurrentCulture { get; } = new NaturalSortStringComparer(StringComparison.CurrentCulture);
    public static NaturalSortStringComparer CurrentCultureIgnoreCase { get; } = new NaturalSortStringComparer(StringComparison.CurrentCultureIgnoreCase);
    public static NaturalSortStringComparer InvariantCulture { get; } = new NaturalSortStringComparer(StringComparison.InvariantCulture);
    public static NaturalSortStringComparer InvariantCultureIgnoreCase { get; } = new NaturalSortStringComparer(StringComparison.InvariantCultureIgnoreCase);

    private readonly StringComparison _comparison;

    public NaturalSortStringComparer(StringComparison comparison)
    {
        _comparison = comparison;
    }

    public int Compare(string x, string y)
    {
        // Let string.Compare handle the case where x or y is null
        if (x is null || y is null)
            return string.Compare(x, y, _comparison);

        var xSegments = GetSegments(x);
        var ySegments = GetSegments(y);

        while (xSegments.MoveNext() && ySegments.MoveNext())
        {
            int cmp;

            // If they're both numbers, compare the value
            if (xSegments.CurrentIsNumber && ySegments.CurrentIsNumber)
            {
                var xValue = long.Parse(xSegments.Current);
                var yValue = long.Parse(ySegments.Current);
                cmp = xValue.CompareTo(yValue);
                if (cmp != 0)
                    return cmp;
            }
            // If x is a number and y is not, x is "lesser than" y
            else if (xSegments.CurrentIsNumber)
            {
                return -1;
            }
            // If y is a number and x is not, x is "greater than" y
            else if (ySegments.CurrentIsNumber)
            {
                return 1;
            }

            // OK, neither are number, compare the segments as text
            cmp = xSegments.Current.CompareTo(ySegments.Current, _comparison);
            if (cmp != 0)
                return cmp;
        }

        // At this point, either all segments are equal, or one string is shorter than the other

        // If x is shorter, it's "lesser than" y
        if (x.Length < y.Length)
            return -1;
        // If x is longer, it's "greater than" y
        if (x.Length > y.Length)
            return 1;

        // If they have the same length, they're equal
        return 0;
    }

    private static StringSegmentEnumerator GetSegments(string s) => new StringSegmentEnumerator(s);

    private struct StringSegmentEnumerator
    {
        private readonly string _s;
        private int _start;
        private int _length;

        public StringSegmentEnumerator(string s)
        {
            _s = s;
            _start = -1;
            _length = 0;
            CurrentIsNumber = false;
        }

        public ReadOnlySpan<char> Current => _s.AsSpan(_start, _length);
        
        public bool CurrentIsNumber { get; private set; }

        public bool MoveNext()
        {
            var currentPosition = _start >= 0
                ? _start + _length
                : 0;

            if (currentPosition >= _s.Length)
                return false;

            int start = currentPosition;
            bool isFirstCharDigit = Char.IsDigit(_s[currentPosition]);

            while (++currentPosition < _s.Length && Char.IsDigit(_s[currentPosition]) == isFirstCharDigit)
            {
            }

            _start = start;
            _length = currentPosition - start;
            CurrentIsNumber = isFirstCharDigit;

            return true;
        }
    }
}
迟到的我 2024-07-14 18:04:16

你确实需要小心——我隐约记得读到过,StrCmpLogicalW 或类似的东西不是严格传递的,而且我观察到,如果比较函数违反了该规则,.NET 的排序方法有时会陷入无限循环。

传递比较总是会报告 a < 如果a<c b 且 b < C。 存在一个进行自然排序比较的函数,该函数并不总是满足该标准,但我不记得它是 StrCmpLogicalW 还是其他东西。

You do need to be careful -- I vaguely recall reading that StrCmpLogicalW, or something like it, was not strictly transitive, and I have observed .NET's sort methods to sometimes get stuck in infinite loops if the comparison function breaks that rule.

A transitive comparison will always report that a < c if a < b and b < c. There exists a function that does a natural sort order comparison that does not always meet that criterion, but I can't recall whether it is StrCmpLogicalW or something else.

勿挽旧人 2024-07-14 18:04:16

这是我对同时包含字母和数字字符的字符串进行排序的代码。

首先,这个扩展方法:

public static IEnumerable<string> AlphanumericSort(this IEnumerable<string> me)
{
    return me.OrderBy(x => Regex.Replace(x, @"\d+", m => m.Value.PadLeft(50, '0')));
}

然后,只需在代码中的任何地方使用它,如下所示:

List<string> test = new List<string>() { "The 1st", "The 12th", "The 2nd" };
test = test.AlphanumericSort();

它是如何工作的? 通过用零替换:

  Original  | Regex Replace |      The      |   Returned
    List    | Apply PadLeft |    Sorting    |     List
            |               |               |
 "The 1st"  |  "The 001st"  |  "The 001st"  |  "The 1st"
 "The 12th" |  "The 012th"  |  "The 002nd"  |  "The 2nd"
 "The 2nd"  |  "The 002nd"  |  "The 012th"  |  "The 12th"

适用于多个数字:

 Alphabetical Sorting | Alphanumeric Sorting
                      |
 "Page 21, Line 42"   | "Page 3, Line 7"
 "Page 21, Line 5"    | "Page 3, Line 32"
 "Page 3, Line 32"    | "Page 21, Line 5"
 "Page 3, Line 7"     | "Page 21, Line 42"

希望这会有所帮助。

This is my code to sort a string having both alpha and numeric characters.

First, this extension method:

public static IEnumerable<string> AlphanumericSort(this IEnumerable<string> me)
{
    return me.OrderBy(x => Regex.Replace(x, @"\d+", m => m.Value.PadLeft(50, '0')));
}

Then, simply use it anywhere in your code like this:

List<string> test = new List<string>() { "The 1st", "The 12th", "The 2nd" };
test = test.AlphanumericSort();

How does it works ? By replaceing with zeros:

  Original  | Regex Replace |      The      |   Returned
    List    | Apply PadLeft |    Sorting    |     List
            |               |               |
 "The 1st"  |  "The 001st"  |  "The 001st"  |  "The 1st"
 "The 12th" |  "The 012th"  |  "The 002nd"  |  "The 2nd"
 "The 2nd"  |  "The 002nd"  |  "The 012th"  |  "The 12th"

Works with multiples numbers:

 Alphabetical Sorting | Alphanumeric Sorting
                      |
 "Page 21, Line 42"   | "Page 3, Line 7"
 "Page 21, Line 5"    | "Page 3, Line 32"
 "Page 3, Line 32"    | "Page 21, Line 5"
 "Page 3, Line 7"     | "Page 21, Line 42"

Hope that's will help.

凶凌 2024-07-14 18:04:16

这是一个相对简单的示例,它不使用 P/Invoke 并避免在执行期间进行任何分配。

请随意使用此处的代码,或者如果更简单,可以使用 NuGet 包:

https://www.nuget .org/packages/NaturalSort

https://github.com/drewnoakes/natural-sort

internal sealed class NaturalStringComparer : IComparer<string>
{
    public static NaturalStringComparer Instance { get; } = new NaturalStringComparer();

    public int Compare(string x, string y)
    {
        // sort nulls to the start
        if (x == null)
            return y == null ? 0 : -1;
        if (y == null)
            return 1;

        var ix = 0;
        var iy = 0;

        while (true)
        {
            // sort shorter strings to the start
            if (ix >= x.Length)
                return iy >= y.Length ? 0 : -1;
            if (iy >= y.Length)
                return 1;

            var cx = x[ix];
            var cy = y[iy];

            int result;
            if (char.IsDigit(cx) && char.IsDigit(cy))
                result = CompareInteger(x, y, ref ix, ref iy);
            else
                result = cx.CompareTo(y[iy]);

            if (result != 0)
                return result;

            ix++;
            iy++;
        }
    }

    private static int CompareInteger(string x, string y, ref int ix, ref int iy)
    {
        var lx = GetNumLength(x, ix);
        var ly = GetNumLength(y, iy);

        // shorter number first (note, doesn't handle leading zeroes)
        if (lx != ly)
            return lx.CompareTo(ly);

        for (var i = 0; i < lx; i++)
        {
            var result = x[ix++].CompareTo(y[iy++]);
            if (result != 0)
                return result;
        }

        return 0;
    }

    private static int GetNumLength(string s, int i)
    {
        var length = 0;
        while (i < s.Length && char.IsDigit(s[i++]))
            length++;
        return length;
    }
}

它不会忽略前导零,因此 01 位于 2 之后。

对应的单元测试:

public class NumericStringComparerTests
{
    [Fact]
    public void OrdersCorrectly()
    {
        AssertEqual("", "");
        AssertEqual(null, null);
        AssertEqual("Hello", "Hello");
        AssertEqual("Hello123", "Hello123");
        AssertEqual("123", "123");
        AssertEqual("123Hello", "123Hello");

        AssertOrdered("", "Hello");
        AssertOrdered(null, "Hello");
        AssertOrdered("Hello", "Hello1");
        AssertOrdered("Hello123", "Hello124");
        AssertOrdered("Hello123", "Hello133");
        AssertOrdered("Hello123", "Hello223");
        AssertOrdered("123", "124");
        AssertOrdered("123", "133");
        AssertOrdered("123", "223");
        AssertOrdered("123", "1234");
        AssertOrdered("123", "2345");
        AssertOrdered("0", "1");
        AssertOrdered("123Hello", "124Hello");
        AssertOrdered("123Hello", "133Hello");
        AssertOrdered("123Hello", "223Hello");
        AssertOrdered("123Hello", "1234Hello");
    }

    private static void AssertEqual(string x, string y)
    {
        Assert.Equal(0, NaturalStringComparer.Instance.Compare(x, y));
        Assert.Equal(0, NaturalStringComparer.Instance.Compare(y, x));
    }

    private static void AssertOrdered(string x, string y)
    {
        Assert.Equal(-1, NaturalStringComparer.Instance.Compare(x, y));
        Assert.Equal( 1, NaturalStringComparer.Instance.Compare(y, x));
    }
}

Here's a relatively simple example that doesn't use P/Invoke and avoids any allocation during execution.

Feel free to use the code from here, or if it's easier there's a NuGet package:

https://www.nuget.org/packages/NaturalSort

https://github.com/drewnoakes/natural-sort

internal sealed class NaturalStringComparer : IComparer<string>
{
    public static NaturalStringComparer Instance { get; } = new NaturalStringComparer();

    public int Compare(string x, string y)
    {
        // sort nulls to the start
        if (x == null)
            return y == null ? 0 : -1;
        if (y == null)
            return 1;

        var ix = 0;
        var iy = 0;

        while (true)
        {
            // sort shorter strings to the start
            if (ix >= x.Length)
                return iy >= y.Length ? 0 : -1;
            if (iy >= y.Length)
                return 1;

            var cx = x[ix];
            var cy = y[iy];

            int result;
            if (char.IsDigit(cx) && char.IsDigit(cy))
                result = CompareInteger(x, y, ref ix, ref iy);
            else
                result = cx.CompareTo(y[iy]);

            if (result != 0)
                return result;

            ix++;
            iy++;
        }
    }

    private static int CompareInteger(string x, string y, ref int ix, ref int iy)
    {
        var lx = GetNumLength(x, ix);
        var ly = GetNumLength(y, iy);

        // shorter number first (note, doesn't handle leading zeroes)
        if (lx != ly)
            return lx.CompareTo(ly);

        for (var i = 0; i < lx; i++)
        {
            var result = x[ix++].CompareTo(y[iy++]);
            if (result != 0)
                return result;
        }

        return 0;
    }

    private static int GetNumLength(string s, int i)
    {
        var length = 0;
        while (i < s.Length && char.IsDigit(s[i++]))
            length++;
        return length;
    }
}

It doesn't ignore leading zeroes, so 01 comes after 2.

Corresponding unit test:

public class NumericStringComparerTests
{
    [Fact]
    public void OrdersCorrectly()
    {
        AssertEqual("", "");
        AssertEqual(null, null);
        AssertEqual("Hello", "Hello");
        AssertEqual("Hello123", "Hello123");
        AssertEqual("123", "123");
        AssertEqual("123Hello", "123Hello");

        AssertOrdered("", "Hello");
        AssertOrdered(null, "Hello");
        AssertOrdered("Hello", "Hello1");
        AssertOrdered("Hello123", "Hello124");
        AssertOrdered("Hello123", "Hello133");
        AssertOrdered("Hello123", "Hello223");
        AssertOrdered("123", "124");
        AssertOrdered("123", "133");
        AssertOrdered("123", "223");
        AssertOrdered("123", "1234");
        AssertOrdered("123", "2345");
        AssertOrdered("0", "1");
        AssertOrdered("123Hello", "124Hello");
        AssertOrdered("123Hello", "133Hello");
        AssertOrdered("123Hello", "223Hello");
        AssertOrdered("123Hello", "1234Hello");
    }

    private static void AssertEqual(string x, string y)
    {
        Assert.Equal(0, NaturalStringComparer.Instance.Compare(x, y));
        Assert.Equal(0, NaturalStringComparer.Instance.Compare(y, x));
    }

    private static void AssertOrdered(string x, string y)
    {
        Assert.Equal(-1, NaturalStringComparer.Instance.Compare(x, y));
        Assert.Equal( 1, NaturalStringComparer.Instance.Compare(y, x));
    }
}
兔姬 2024-07-14 18:04:16

添加到 Greg Beech 的答案(因为我一直在寻找),如果您想从 Linq 使用它,您可以使用带有 IComparerOrderBy。 例如:

var items = new List<MyItem>();

// fill items

var sorted = items.OrderBy(item => item.Name, new NaturalStringComparer());

Adding to Greg Beech's answer (because I've just been searching for that), if you want to use this from Linq you can use the OrderBy that takes an IComparer. E.g.:

var items = new List<MyItem>();

// fill items

var sorted = items.OrderBy(item => item.Name, new NaturalStringComparer());
鼻尖触碰 2024-07-14 18:04:16

实际上,我已将其实现为 StringComparer 上的扩展方法,以便您可以执行以下操作:

  • StringComparer.CurrentCulture.WithNaturalSort()
  • StringComparer.OrdinalIgnoreCase。 WithNaturalSort()。

生成的 IComparer 可用于所有位置,例如 OrderByOrderByDescendingThenByThenByDescendingSortedSet 等。您仍然可以轻松调整区分大小写、区域性等。

该实现相当简单,即使在大型序列上也应该表现良好。


我还将其发布为一个小型 NuGet 包,所以你可以这样做:

Install-Package NaturalSort.Extension

代码包括 XML 文档注释和 测试套件可在 NaturalSort.Extension GitHub 存储库


整个代码是这样的(如果你还不能使用C#7,只需安装NuGet包):

public static class StringComparerNaturalSortExtension
{
    public static IComparer<string> WithNaturalSort(this StringComparer stringComparer) => new NaturalSortComparer(stringComparer);

    private class NaturalSortComparer : IComparer<string>
    {
        public NaturalSortComparer(StringComparer stringComparer)
        {
            _stringComparer = stringComparer;
        }

        private readonly StringComparer _stringComparer;
        private static readonly Regex NumberSequenceRegex = new Regex(@"(\d+)", RegexOptions.Compiled | RegexOptions.CultureInvariant);
        private static string[] Tokenize(string s) => s == null ? new string[] { } : NumberSequenceRegex.Split(s);
        private static ulong ParseNumberOrZero(string s) => ulong.TryParse(s, NumberStyles.None, CultureInfo.InvariantCulture, out var result) ? result : 0;

        public int Compare(string s1, string s2)
        {
            var tokens1 = Tokenize(s1);
            var tokens2 = Tokenize(s2);

            var zipCompare = tokens1.Zip(tokens2, TokenCompare).FirstOrDefault(x => x != 0);
            if (zipCompare != 0)
                return zipCompare;

            var lengthCompare = tokens1.Length.CompareTo(tokens2.Length);
            return lengthCompare;
        }
        
        private int TokenCompare(string token1, string token2)
        {
            var number1 = ParseNumberOrZero(token1);
            var number2 = ParseNumberOrZero(token2);

            var numberCompare = number1.CompareTo(number2);
            if (numberCompare != 0)
                return numberCompare;

            var stringCompare = _stringComparer.Compare(token1, token2);
            return stringCompare;
        }
    }
}

I've actually implemented it as an extension method on the StringComparer so that you could do for example:

  • StringComparer.CurrentCulture.WithNaturalSort() or
  • StringComparer.OrdinalIgnoreCase.WithNaturalSort().

The resulting IComparer<string> can be used in all places like OrderBy, OrderByDescending, ThenBy, ThenByDescending, SortedSet<string>, etc. And you can still easily tweak case sensitivity, culture, etc.

The implementation is fairly trivial and it should perform quite well even on large sequences.


I've also published it as a tiny NuGet package, so you can just do:

Install-Package NaturalSort.Extension

The code including XML documentation comments and suite of tests is available in the NaturalSort.Extension GitHub repository.


The entire code is this (if you cannot use C# 7 yet, just install the NuGet package):

public static class StringComparerNaturalSortExtension
{
    public static IComparer<string> WithNaturalSort(this StringComparer stringComparer) => new NaturalSortComparer(stringComparer);

    private class NaturalSortComparer : IComparer<string>
    {
        public NaturalSortComparer(StringComparer stringComparer)
        {
            _stringComparer = stringComparer;
        }

        private readonly StringComparer _stringComparer;
        private static readonly Regex NumberSequenceRegex = new Regex(@"(\d+)", RegexOptions.Compiled | RegexOptions.CultureInvariant);
        private static string[] Tokenize(string s) => s == null ? new string[] { } : NumberSequenceRegex.Split(s);
        private static ulong ParseNumberOrZero(string s) => ulong.TryParse(s, NumberStyles.None, CultureInfo.InvariantCulture, out var result) ? result : 0;

        public int Compare(string s1, string s2)
        {
            var tokens1 = Tokenize(s1);
            var tokens2 = Tokenize(s2);

            var zipCompare = tokens1.Zip(tokens2, TokenCompare).FirstOrDefault(x => x != 0);
            if (zipCompare != 0)
                return zipCompare;

            var lengthCompare = tokens1.Length.CompareTo(tokens2.Length);
            return lengthCompare;
        }
        
        private int TokenCompare(string token1, string token2)
        {
            var number1 = ParseNumberOrZero(token1);
            var number2 = ParseNumberOrZero(token2);

            var numberCompare = number1.CompareTo(number2);
            if (numberCompare != 0)
                return numberCompare;

            var stringCompare = _stringComparer.Compare(token1, token2);
            return stringCompare;
        }
    }
}
方圜几里 2024-07-14 18:04:16

受 Michael Parker 解决方案的启发,这里有一个 IComparer 实现,您可以将其放入任何 linq 排序方法中:

private class NaturalStringComparer : IComparer<string>
{
    public int Compare(string left, string right)
    {
        int max = new[] { left, right }
            .SelectMany(x => Regex.Matches(x, @"\d+").Cast<Match>().Select(y => (int?)y.Value.Length))
            .Max() ?? 0;

        var leftPadded = Regex.Replace(left, @"\d+", m => m.Value.PadLeft(max, '0'));
        var rightPadded = Regex.Replace(right, @"\d+", m => m.Value.PadLeft(max, '0'));

        return string.Compare(leftPadded, rightPadded);
    }
}

Inspired by Michael Parker's solution, here is an IComparer implementation that you can drop in to any of the linq ordering methods:

private class NaturalStringComparer : IComparer<string>
{
    public int Compare(string left, string right)
    {
        int max = new[] { left, right }
            .SelectMany(x => Regex.Matches(x, @"\d+").Cast<Match>().Select(y => (int?)y.Value.Length))
            .Max() ?? 0;

        var leftPadded = Regex.Replace(left, @"\d+", m => m.Value.PadLeft(max, '0'));
        var rightPadded = Regex.Replace(right, @"\d+", m => m.Value.PadLeft(max, '0'));

        return string.Compare(leftPadded, rightPadded);
    }
}
我只土不豪 2024-07-14 18:04:16

这是一种简单的单行无正则表达式 LINQ 方式(借用自 python):

var alphaStrings = new List<string>() { "10","2","3","4","50","11","100","a12","b12" };
var orderedString = alphaStrings.OrderBy(g => new Tuple<int, string>(g.ToCharArray().All(char.IsDigit)? int.Parse(g) : int.MaxValue, g));
// Order Now: ["2","3","4","10","11","50","100","a12","b12"]

Here is a naive one-line regex-less LINQ way (borrowed from python):

var alphaStrings = new List<string>() { "10","2","3","4","50","11","100","a12","b12" };
var orderedString = alphaStrings.OrderBy(g => new Tuple<int, string>(g.ToCharArray().All(char.IsDigit)? int.Parse(g) : int.MaxValue, g));
// Order Now: ["2","3","4","10","11","50","100","a12","b12"]
恰似旧人归 2024-07-14 18:04:16

扩展之前的几个答案并利用扩展方法,我提出了以下方法,它没有潜在的多个可枚举枚举的警告,也没有与使用多个正则表达式对象有关的性能问题,或者不必要地调用正则表达式,话虽如此,它确实使用了 ToList(),这可能会抵消较大集合的好处。

选择器支持通用类型以允许分配任何委托,源集合中的元素由选择器进行变异,然后使用 ToString() 转换为字符串。

    private static readonly Regex _NaturalOrderExpr = new Regex(@"\d+", RegexOptions.Compiled);

    public static IEnumerable<TSource> OrderByNatural<TSource, TKey>(
        this IEnumerable<TSource> source, Func<TSource, TKey> selector)
    {
        int max = 0;

        var selection = source.Select(
            o =>
            {
                var v = selector(o);
                var s = v != null ? v.ToString() : String.Empty;

                if (!String.IsNullOrWhiteSpace(s))
                {
                    var mc = _NaturalOrderExpr.Matches(s);

                    if (mc.Count > 0)
                    {
                        max = Math.Max(max, mc.Cast<Match>().Max(m => m.Value.Length));
                    }
                }

                return new
                {
                    Key = o,
                    Value = s
                };
            }).ToList();

        return
            selection.OrderBy(
                o =>
                String.IsNullOrWhiteSpace(o.Value) ? o.Value : _NaturalOrderExpr.Replace(o.Value, m => m.Value.PadLeft(max, '0')))
                     .Select(o => o.Key);
    }

    public static IEnumerable<TSource> OrderByDescendingNatural<TSource, TKey>(
        this IEnumerable<TSource> source, Func<TSource, TKey> selector)
    {
        int max = 0;

        var selection = source.Select(
            o =>
            {
                var v = selector(o);
                var s = v != null ? v.ToString() : String.Empty;

                if (!String.IsNullOrWhiteSpace(s))
                {
                    var mc = _NaturalOrderExpr.Matches(s);

                    if (mc.Count > 0)
                    {
                        max = Math.Max(max, mc.Cast<Match>().Max(m => m.Value.Length));
                    }
                }

                return new
                {
                    Key = o,
                    Value = s
                };
            }).ToList();

        return
            selection.OrderByDescending(
                o =>
                String.IsNullOrWhiteSpace(o.Value) ? o.Value : _NaturalOrderExpr.Replace(o.Value, m => m.Value.PadLeft(max, '0')))
                     .Select(o => o.Key);
    }

Expanding on a couple of the previous answers and making use of extension methods, I came up with the following that doesn't have the caveats of potential multiple enumerable enumeration, or performance issues concerned with using multiple regex objects, or calling regex needlessly, that being said, it does use ToList(), which can negate the benefits in larger collections.

The selector supports generic typing to allow any delegate to be assigned, the elements in the source collection are mutated by the selector, then converted to strings with ToString().

    private static readonly Regex _NaturalOrderExpr = new Regex(@"\d+", RegexOptions.Compiled);

    public static IEnumerable<TSource> OrderByNatural<TSource, TKey>(
        this IEnumerable<TSource> source, Func<TSource, TKey> selector)
    {
        int max = 0;

        var selection = source.Select(
            o =>
            {
                var v = selector(o);
                var s = v != null ? v.ToString() : String.Empty;

                if (!String.IsNullOrWhiteSpace(s))
                {
                    var mc = _NaturalOrderExpr.Matches(s);

                    if (mc.Count > 0)
                    {
                        max = Math.Max(max, mc.Cast<Match>().Max(m => m.Value.Length));
                    }
                }

                return new
                {
                    Key = o,
                    Value = s
                };
            }).ToList();

        return
            selection.OrderBy(
                o =>
                String.IsNullOrWhiteSpace(o.Value) ? o.Value : _NaturalOrderExpr.Replace(o.Value, m => m.Value.PadLeft(max, '0')))
                     .Select(o => o.Key);
    }

    public static IEnumerable<TSource> OrderByDescendingNatural<TSource, TKey>(
        this IEnumerable<TSource> source, Func<TSource, TKey> selector)
    {
        int max = 0;

        var selection = source.Select(
            o =>
            {
                var v = selector(o);
                var s = v != null ? v.ToString() : String.Empty;

                if (!String.IsNullOrWhiteSpace(s))
                {
                    var mc = _NaturalOrderExpr.Matches(s);

                    if (mc.Count > 0)
                    {
                        max = Math.Max(max, mc.Cast<Match>().Max(m => m.Value.Length));
                    }
                }

                return new
                {
                    Key = o,
                    Value = s
                };
            }).ToList();

        return
            selection.OrderByDescending(
                o =>
                String.IsNullOrWhiteSpace(o.Value) ? o.Value : _NaturalOrderExpr.Replace(o.Value, m => m.Value.PadLeft(max, '0')))
                     .Select(o => o.Key);
    }
愁杀 2024-07-14 18:04:16

更容易阅读/维护的版本。

public class NaturalStringComparer : IComparer<string>
{
    public static NaturalStringComparer Instance { get; } = new NaturalStringComparer();

    public int Compare(string x, string y) {
        const int LeftIsSmaller = -1;
        const int RightIsSmaller = 1;
        const int Equal = 0;

        var leftString = x;
        var rightString = y;

        var stringComparer = CultureInfo.CurrentCulture.CompareInfo;

        int rightIndex;
        int leftIndex;

        for (leftIndex = 0, rightIndex = 0;
             leftIndex < leftString.Length && rightIndex < rightString.Length;
             leftIndex++, rightIndex++) {
            var leftChar = leftString[leftIndex];
            var rightChar = rightString[leftIndex];

            var leftIsNumber = char.IsNumber(leftChar);
            var rightIsNumber = char.IsNumber(rightChar);

            if (!leftIsNumber && !rightIsNumber) {
                var result = stringComparer.Compare(leftString, leftIndex, 1, rightString, leftIndex, 1);
                if (result != 0) return result;
            } else if (leftIsNumber && !rightIsNumber) {
                return LeftIsSmaller;
            } else if (!leftIsNumber && rightIsNumber) {
                return RightIsSmaller;
            } else {
                var leftNumberLength = NumberLength(leftString, leftIndex, out var leftNumber);
                var rightNumberLength = NumberLength(rightString, rightIndex, out var rightNumber);

                if (leftNumberLength < rightNumberLength) {
                    return LeftIsSmaller;
                } else if (leftNumberLength > rightNumberLength) {
                    return RightIsSmaller;
                } else {
                    if(leftNumber < rightNumber) {
                        return LeftIsSmaller;
                    } else if(leftNumber > rightNumber) {
                        return RightIsSmaller;
                    }
                }
            }
        }

        if (leftString.Length < rightString.Length) {
            return LeftIsSmaller;
        } else if(leftString.Length > rightString.Length) {
            return RightIsSmaller;
        }

        return Equal;
    }

    public int NumberLength(string str, int offset, out int number) {
        if (string.IsNullOrWhiteSpace(str)) throw new ArgumentNullException(nameof(str));
        if (offset >= str.Length) throw new ArgumentOutOfRangeException(nameof(offset), offset, "Offset must be less than the length of the string.");

        var currentOffset = offset;

        var curChar = str[currentOffset];

        if (!char.IsNumber(curChar))
            throw new ArgumentException($"'{curChar}' is not a number.", nameof(offset));

        int length = 1;

        var numberString = string.Empty;

        for (currentOffset = offset + 1;
            currentOffset < str.Length;
            currentOffset++, length++) {

            curChar = str[currentOffset];
            numberString += curChar;

            if (!char.IsNumber(curChar)) {
                number = int.Parse(numberString);

                return length;
            }
        }

        number = int.Parse(numberString);

        return length;
    }
}

A version that's easier to read/maintain.

public class NaturalStringComparer : IComparer<string>
{
    public static NaturalStringComparer Instance { get; } = new NaturalStringComparer();

    public int Compare(string x, string y) {
        const int LeftIsSmaller = -1;
        const int RightIsSmaller = 1;
        const int Equal = 0;

        var leftString = x;
        var rightString = y;

        var stringComparer = CultureInfo.CurrentCulture.CompareInfo;

        int rightIndex;
        int leftIndex;

        for (leftIndex = 0, rightIndex = 0;
             leftIndex < leftString.Length && rightIndex < rightString.Length;
             leftIndex++, rightIndex++) {
            var leftChar = leftString[leftIndex];
            var rightChar = rightString[leftIndex];

            var leftIsNumber = char.IsNumber(leftChar);
            var rightIsNumber = char.IsNumber(rightChar);

            if (!leftIsNumber && !rightIsNumber) {
                var result = stringComparer.Compare(leftString, leftIndex, 1, rightString, leftIndex, 1);
                if (result != 0) return result;
            } else if (leftIsNumber && !rightIsNumber) {
                return LeftIsSmaller;
            } else if (!leftIsNumber && rightIsNumber) {
                return RightIsSmaller;
            } else {
                var leftNumberLength = NumberLength(leftString, leftIndex, out var leftNumber);
                var rightNumberLength = NumberLength(rightString, rightIndex, out var rightNumber);

                if (leftNumberLength < rightNumberLength) {
                    return LeftIsSmaller;
                } else if (leftNumberLength > rightNumberLength) {
                    return RightIsSmaller;
                } else {
                    if(leftNumber < rightNumber) {
                        return LeftIsSmaller;
                    } else if(leftNumber > rightNumber) {
                        return RightIsSmaller;
                    }
                }
            }
        }

        if (leftString.Length < rightString.Length) {
            return LeftIsSmaller;
        } else if(leftString.Length > rightString.Length) {
            return RightIsSmaller;
        }

        return Equal;
    }

    public int NumberLength(string str, int offset, out int number) {
        if (string.IsNullOrWhiteSpace(str)) throw new ArgumentNullException(nameof(str));
        if (offset >= str.Length) throw new ArgumentOutOfRangeException(nameof(offset), offset, "Offset must be less than the length of the string.");

        var currentOffset = offset;

        var curChar = str[currentOffset];

        if (!char.IsNumber(curChar))
            throw new ArgumentException($"'{curChar}' is not a number.", nameof(offset));

        int length = 1;

        var numberString = string.Empty;

        for (currentOffset = offset + 1;
            currentOffset < str.Length;
            currentOffset++, length++) {

            curChar = str[currentOffset];
            numberString += curChar;

            if (!char.IsNumber(curChar)) {
                number = int.Parse(numberString);

                return length;
            }
        }

        number = int.Parse(numberString);

        return length;
    }
}
~没有更多了~
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