jQuery - 在新图像上运行函数
我是 jQuery 新手,所以这个问题的答案可能非常简单:
我有一个图像,我想用它做几件事。 当用户点击“缩放”图标时,我正在运行“imagetool”插件( http://code.google.com/p/jquery-imagetool/)来加载更大版本的图像。 该插件在图像周围创建一个新的 div 并允许用户平移。
当用户单击替代图像时,我将删除旧图像并加载新图像。
当用户单击替代图像,然后单击缩放按钮时,问题就出现了 - imagetool 插件创建了新的 div,但图像出现在它之后......
代码如下:
// Product Zoom (jQuery)
$(document).ready(function(){
$("#productZoom").click(function() {
// Set new image src
var imageSrc = $("#productZoom").attr("href");
$("#productImage").attr('src', imageSrc);
// Run the imagetool plugin on the image
$(function() {
$("#productImage").imagetool({
viewportWidth: 300,
viewportHeight: 300,
topX: 150,
topY: 150,
bottomX: 450,
bottomY: 450
});
});
return false;
});
});
// Alternative product photos (jQuery)
$(document).ready(function(){
$(".altPhoto").click(function() {
$('#productImageDiv div.viewport').remove();
$('#productImage').remove();
// Set new image src
var altImageSrc = $(this).attr("href");
$("#productZoom").attr('href', altImageSrc);
var img = new Image();
$(img).load(function () {
$(this).hide();
$('#productImageDiv').append(this);
$(this).fadeIn();
}).error(function () {
// notify the user that the image could not be loaded
}).attr({
src: altImageSrc,
id: "productImage"
});
return false;
});
});
在我看来,imagetool一旦被新图像替换,插件就无法再看到 #productImage 图像...所以我认为这与绑定有关? 因为新图像在页面加载后添加到 dom 中,所以 iamgetool 插件无法再正确使用它......这是对的吗? 如果是这样,有什么想法如何处理吗?
I'm a jQuery novice, so the answer to this may be quite simple:
I have an image, and I would like to do several things with it.
When a user clicks on a 'Zoom' icon, I'm running the 'imagetool' plugin (http://code.google.com/p/jquery-imagetool/) to load a larger version of the image. The plugin creates a new div around the image and allows the user to pan around.
When a user clicks on an alternative image, I'm removing the old one and loading in the new one.
The problem comes when a user clicks an alternative image, and then clicks on the zoom button - the imagetool plugin creates the new div, but the image appears after it...
The code is as follows:
// Product Zoom (jQuery)
$(document).ready(function(){
$("#productZoom").click(function() {
// Set new image src
var imageSrc = $("#productZoom").attr("href");
$("#productImage").attr('src', imageSrc);
// Run the imagetool plugin on the image
$(function() {
$("#productImage").imagetool({
viewportWidth: 300,
viewportHeight: 300,
topX: 150,
topY: 150,
bottomX: 450,
bottomY: 450
});
});
return false;
});
});
// Alternative product photos (jQuery)
$(document).ready(function(){
$(".altPhoto").click(function() {
$('#productImageDiv div.viewport').remove();
$('#productImage').remove();
// Set new image src
var altImageSrc = $(this).attr("href");
$("#productZoom").attr('href', altImageSrc);
var img = new Image();
$(img).load(function () {
$(this).hide();
$('#productImageDiv').append(this);
$(this).fadeIn();
}).error(function () {
// notify the user that the image could not be loaded
}).attr({
src: altImageSrc,
id: "productImage"
});
return false;
});
});
It seems to me, that the imagetool plugin can no longer see the #productImage image once it has been replaced with a new image... So I think this has something to do with binding? As in because the new image is added to the dom after the page has loaded, the iamgetool plugin can no longer use it correctly... is this right?
If so, any ideas how to deal with it?
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评论(3)
嘿嘿! 我自己整理了一下...
事实证明,如果我完全删除包含的div,然后用.html重写它,imagetool插件会再次识别它。
任何有兴趣的人都可以修改代码:
Wehey! I've sorted it out myself...
Turns out if I remove the containing div completely, and then rewrite it with .html, the imagetool plugin recognises it again.
Amended code for anyone who's interested:
您可以尝试将 productZoom.click() 函数抽象为命名函数,然后在更改为备用图像后重新绑定它。 类似于:
另外,将两个ready()块滚动到同一个块中。
You could try abstracting the productZoom.click() function to a named function, and then re-binding it after changing to an alternate image. Something like:
Also, rolled both your ready() blocks into the same block.
首先,我有一个问题,.altPhoto 链接还是图像? 因为如果它的图像那么这条线是错误的,
它应该是
我一眼就能找到的唯一东西
First, i have one question, are the .altPhoto links or images? Cause if its images then this line is wrong
it should be
its the only thing i could find in a glance