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通过 UDP 的字节缓冲区传输

发布于 2024-07-04 05:49:29 字数 47 浏览 12 评论 0原文

您能提供一个通过 UDP 数据报在两个 java 类之间传输字节缓冲区的示例吗？

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秋千易 2024-07-11 05:49:29

@none

DatagramSocket 类确实需要改进，DatagramChannel 对于客户端来说稍好一些，但对于服务器编程来说则令人困惑。例如：

import java.io.IOException;
import java.net.InetSocketAddress;
import java.nio.ByteBuffer;
import java.nio.channels.DatagramChannel;


public class Client {

    public static void main(String[] args) throws IOException {
        DatagramChannel channel = DatagramChannel.open();
        ByteBuffer buffer = ByteBuffer.wrap("Oh Hai!".getBytes());
        channel.send(buffer, new InetSocketAddress("localhost", 5000));
    }
}

启用 JSR-203 I说

@none

The DatagramSocket classes sure need a polish up, DatagramChannel is slightly better for clients, but confusing for server programming. For example:

import java.io.IOException;
import java.net.InetSocketAddress;
import java.nio.ByteBuffer;
import java.nio.channels.DatagramChannel;


public class Client {

    public static void main(String[] args) throws IOException {
        DatagramChannel channel = DatagramChannel.open();
        ByteBuffer buffer = ByteBuffer.wrap("Oh Hai!".getBytes());
        channel.send(buffer, new InetSocketAddress("localhost", 5000));
    }
}

Bring on JSR-203 I say

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单身狗的梦 2024-07-11 05:49:29

这个怎么样？

import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetSocketAddress;


public class Server {

    public static void main(String[] args) throws IOException {
        DatagramSocket socket = new DatagramSocket(new InetSocketAddress(5000));
        byte[] message = new byte[512];
        DatagramPacket packet = new DatagramPacket(message, message.length);
        socket.receive(packet);
        System.out.println(new String(packet.getData(), packet.getOffset(), packet.getLength()));
    }
}

import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetSocketAddress;


public class Client {

    public static void main(String[] args) throws IOException {
        DatagramSocket socket = new DatagramSocket();
        socket.connect(new InetSocketAddress(5000));
        byte[] message = "Oh Hai!".getBytes();
        DatagramPacket packet = new DatagramPacket(message, message.length);
        socket.send(packet);
    }
}

Hows' this ?

import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetSocketAddress;


public class Server {

    public static void main(String[] args) throws IOException {
        DatagramSocket socket = new DatagramSocket(new InetSocketAddress(5000));
        byte[] message = new byte[512];
        DatagramPacket packet = new DatagramPacket(message, message.length);
        socket.receive(packet);
        System.out.println(new String(packet.getData(), packet.getOffset(), packet.getLength()));
    }
}

import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetSocketAddress;


public class Client {

    public static void main(String[] args) throws IOException {
        DatagramSocket socket = new DatagramSocket();
        socket.connect(new InetSocketAddress(5000));
        byte[] message = "Oh Hai!".getBytes();
        DatagramPacket packet = new DatagramPacket(message, message.length);
        socket.send(packet);
    }
}

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