将整数转换为书面数字

Question

是否有一种有效的方法将整数转换为书面数字，例如：

string Written = IntegerToWritten(21);

将返回“二十一”。

有没有什么方法可以做到这一点而不涉及大量的查找表？

Answer 1

以下 C# 控制台应用程序代码将接受最多 2 位小数的货币值并以英语打印。 这不仅将整数转换为其等值的英文，而且还转换为以美元和美分表示的货币价值。

 namespace ConsoleApplication2
{
    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text.RegularExpressions;
    class Program
    {
       static void Main(string[] args)
        {
            bool repeat = true;
            while (repeat)
            {
                string inputMonetaryValueInNumberic = string.Empty;
                string centPart = string.Empty;
                string dollarPart = string.Empty;
                Console.Write("\nEnter the monetary value : ");
                inputMonetaryValueInNumberic = Console.ReadLine();
                inputMonetaryValueInNumberic = inputMonetaryValueInNumberic.TrimStart('0');

                if (ValidateInput(inputMonetaryValueInNumberic))
                {

                    if (inputMonetaryValueInNumberic.Contains('.'))
                    {
                        centPart = ProcessCents(inputMonetaryValueInNumberic.Substring(inputMonetaryValueInNumberic.IndexOf(".") + 1));
                        dollarPart = ProcessDollar(inputMonetaryValueInNumberic.Substring(0, inputMonetaryValueInNumberic.IndexOf(".")));
                    }
                    else
                    {
                        dollarPart = ProcessDollar(inputMonetaryValueInNumberic);
                    }
                    centPart = string.IsNullOrWhiteSpace(centPart) ? string.Empty : " and " + centPart;
                    Console.WriteLine(string.Format("\n\n{0}{1}", dollarPart, centPart));
                }
                else
                {
                    Console.WriteLine("Invalid Input..");
                }

                Console.WriteLine("\n\nPress any key to continue or Escape of close : ");
                var loop = Console.ReadKey();
                repeat = !loop.Key.ToString().Contains("Escape");
                Console.Clear();
            }

        }

        private static string ProcessCents(string cents)
        {
            string english = string.Empty;
            string dig3 = Process3Digit(cents);
            if (!string.IsNullOrWhiteSpace(dig3))
            {
                dig3 = string.Format("{0} {1}", dig3, GetSections(0));
            }
            english = dig3 + english;
            return english;
        }
        private static string ProcessDollar(string dollar)
        {
            string english = string.Empty;
            foreach (var item in Get3DigitList(dollar))
            {
                string dig3 = Process3Digit(item.Value);
                if (!string.IsNullOrWhiteSpace(dig3))
                {
                    dig3 = string.Format("{0} {1}", dig3, GetSections(item.Key));
                }
                english = dig3 + english;
            }
            return english;
        }
        private static string Process3Digit(string digit3)
        {
            string result = string.Empty;
            if (Convert.ToInt32(digit3) != 0)
            {
                int place = 0;
                Stack<string> monetaryValue = new Stack<string>();
                for (int i = digit3.Length - 1; i >= 0; i--)
                {
                    place += 1;
                    string stringValue = string.Empty;
                    switch (place)
                    {
                        case 1:
                            stringValue = GetOnes(digit3[i].ToString());
                            break;
                        case 2:
                            int tens = Convert.ToInt32(digit3[i]);
                            if (tens == 1)
                            {
                                if (monetaryValue.Count > 0)
                                {
                                    monetaryValue.Pop();
                                }
                                stringValue = GetTens((digit3[i].ToString() + digit3[i + 1].ToString()));
                            }
                            else
                            {
                                stringValue = GetTens(digit3[i].ToString());
                            }
                            break;
                        case 3:
                            stringValue = GetOnes(digit3[i].ToString());
                            if (!string.IsNullOrWhiteSpace(stringValue))
                            {
                                string postFixWith = " Hundred";
                                if (monetaryValue.Count > 0)
                                {
                                    postFixWith = postFixWith + " And";
                                }
                                stringValue += postFixWith;
                            }
                            break;
                    }
                    if (!string.IsNullOrWhiteSpace(stringValue))
                        monetaryValue.Push(stringValue);
                }
                while (monetaryValue.Count > 0)
                {
                    result += " " + monetaryValue.Pop().ToString().Trim();
                }
            }
            return result;
        }
        private static Dictionary<int, string> Get3DigitList(string monetaryValueInNumberic)
        {
            Dictionary<int, string> hundredsStack = new Dictionary<int, string>();
            int counter = 0;
            while (monetaryValueInNumberic.Length >= 3)
            {
                string digit3 = monetaryValueInNumberic.Substring(monetaryValueInNumberic.Length - 3, 3);
                monetaryValueInNumberic = monetaryValueInNumberic.Substring(0, monetaryValueInNumberic.Length - 3);
                hundredsStack.Add(++counter, digit3);
            }
            if (monetaryValueInNumberic.Length != 0)
                hundredsStack.Add(++counter, monetaryValueInNumberic);
            return hundredsStack;
        }
        private static string GetTens(string tensPlaceValue)
        {
            string englishEquvalent = string.Empty;
            int value = Convert.ToInt32(tensPlaceValue);
            Dictionary<int, string> tens = new Dictionary<int, string>();
            tens.Add(2, "Twenty");
            tens.Add(3, "Thirty");
            tens.Add(4, "Forty");
            tens.Add(5, "Fifty");
            tens.Add(6, "Sixty");
            tens.Add(7, "Seventy");
            tens.Add(8, "Eighty");
            tens.Add(9, "Ninty");
            tens.Add(10, "Ten");
            tens.Add(11, "Eleven");
            tens.Add(12, "Twelve");
            tens.Add(13, "Thrteen");
            tens.Add(14, "Fourteen");
            tens.Add(15, "Fifteen");
            tens.Add(16, "Sixteen");
            tens.Add(17, "Seventeen");
            tens.Add(18, "Eighteen");
            tens.Add(19, "Ninteen");
            if (tens.ContainsKey(value))
            {
                englishEquvalent = tens[value];
            }

            return englishEquvalent;

        }
        private static string GetOnes(string onesPlaceValue)
        {
            int value = Convert.ToInt32(onesPlaceValue);
            string englishEquvalent = string.Empty;
            Dictionary<int, string> ones = new Dictionary<int, string>();
            ones.Add(1, " One");
            ones.Add(2, " Two");
            ones.Add(3, " Three");
            ones.Add(4, " Four");
            ones.Add(5, " Five");
            ones.Add(6, " Six");
            ones.Add(7, " Seven");
            ones.Add(8, " Eight");
            ones.Add(9, " Nine");

            if (ones.ContainsKey(value))
            {
                englishEquvalent = ones[value];
            }

            return englishEquvalent;
        }
        private static string GetSections(int section)
        {
            string sectionName = string.Empty;
            switch (section)
            {
                case 0:
                    sectionName = "Cents";
                    break;
                case 1:
                    sectionName = "Dollars";
                    break;
                case 2:
                    sectionName = "Thousand";
                    break;
                case 3:
                    sectionName = "Million";
                    break;
                case 4:
                    sectionName = "Billion";
                    break;
                case 5:
                    sectionName = "Trillion";
                    break;
                case 6:
                    sectionName = "Zillion";
                    break;
            }
            return sectionName;
        }
        private static bool ValidateInput(string input)
        {
            return Regex.IsMatch(input, "[0-9]{1,18}(\\.[0-9]{1,2})?"))
        }
    }
}

Answer 2

我使用这个代码。它是 VB 代码，但您可以轻松地将其转换为 C#。 它可以工作

Function NumberToText(ByVal n As Integer) As String

   Select Case n
Case 0
  Return ""

Case 1 To 19
  Dim arr() As String = {"One","Two","Three","Four","Five","Six","Seven", _
    "Eight","Nine","Ten","Eleven","Twelve","Thirteen","Fourteen", _
      "Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"}
  Return arr(n-1) & " "

Case 20 to 99
  Dim arr() as String = {"Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"}
  Return arr(n\10 -2) & " " & NumberToText(n Mod 10)

Case 100 to 199
  Return "One Hundred " & NumberToText(n Mod 100)

Case 200 to 999
  Return NumberToText(n\100) & "Hundreds " & NumberToText(n mod 100)

Case 1000 to 1999
  Return "One Thousand " & NumberToText(n Mod 1000)

Case 2000 to 999999
  Return NumberToText(n\1000) & "Thousands " & NumberToText(n Mod 1000)

Case 1000000 to 1999999
  Return "One Million " & NumberToText(n Mod 1000000)

Case 1000000 to 999999999
  Return NumberToText(n\1000000) & "Millions " & NumberToText(n Mod 1000000)

Case 1000000000 to 1999999999
  Return "One Billion " & NumberTotext(n Mod 1000000000)

Case Else
  Return NumberToText(n\1000000000) & "Billion " _
    & NumberToText(n mod 1000000000)
End Select
End Function

这是c#中的代码

public static string AmountInWords(double amount)
{
        var n = (int)amount;

        if (n == 0)
            return "";
        else if (n > 0 && n <= 19)
        {
            var arr = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
            return arr[n - 1] + " ";
        }
        else if (n >= 20 && n <= 99)
        {
            var arr = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
            return arr[n / 10 - 2] + " " + AmountInWords(n % 10);
        }
        else if (n >= 100 && n <= 199)
        {
            return "One Hundred " + AmountInWords(n % 100);
        }
        else if (n >= 200 && n <= 999)
        {
            return AmountInWords(n / 100) + "Hundred " + AmountInWords(n % 100);
        }
        else if (n >= 1000 && n <= 1999)
        {
            return "One Thousand " + AmountInWords(n % 1000);
        }
        else if (n >= 2000 && n <= 999999)
        {
            return AmountInWords(n / 1000) + "Thousand " + AmountInWords(n % 1000);
        }
        else if (n >= 1000000 && n <= 1999999)
        {
            return "One Million " + AmountInWords(n % 1000000);
        }
        else if (n >= 1000000 && n <= 999999999)
        {
            return AmountInWords(n / 1000000) + "Million " + AmountInWords(n % 1000000);
        }
        else if (n >= 1000000000 && n <= 1999999999)
        {
            return "One Billion " + AmountInWords(n % 1000000000);
        }
        else
        {
            return AmountInWords(n / 1000000000) + "Billion " + AmountInWords(n % 1000000000);
        }
    }

Answer 3

为什么需要大量的查找表？

string GetWrittenInteger(int n)
{
  string[] a = new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" }
  string[] b = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" }
  string[] c = new string[] {"Twenty", "Thirty", "Forty", "Sixty", "Seventy", "Eighty", "Ninety"};
  string[] d = new string[] {"Hundred", "Thousand", "Million"}
  string s = n.ToString();

  for (int i = 0; i < s.Length; i++)
  {
    // logic (too lazy but you get the idea)
  }
}

Answer 4

using System;
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 

namespace tryingstartfror4digits 
{ 
    class Program 
    { 
        static void Main(string[] args)
        {
            Program pg = new Program();
            Console.WriteLine("Enter ur number");
            int num = Convert.ToInt32(Console.ReadLine());

            if (num <= 19)
            {
                string g = pg.first(num);
                Console.WriteLine("The number is " + g);
            }
            else if ((num >= 20) && (num <= 99))
            {
                    if (num % 10 == 0)
                    {
                        string g = pg.second(num / 10);
                        Console.WriteLine("The number is " + g);
                    }
                    else
                    {
                        string g = pg.second(num / 10) + pg.first(num % 10);
                        Console.WriteLine("The number is " + g);
                    }
            }
            else if ((num >= 100) && (num <= 999))
            {
                int k = num % 100;
                string g = pg.first(num / 100) +pg.third(0) + pg.second(k / 10)+pg.first(k%10);
                Console.WriteLine("The number is " + g);
            }
            else if ((num >= 1000) && (num <= 19999))
            {
                int h = num % 1000;
                int k = h % 100;
                string g = pg.first(num / 1000) + "Thousand " + pg.first(h/ 100) + pg.third(k) + pg.second(k / 10) + pg.first(k % 10);
                Console.WriteLine("The number is " + g);
            }

            Console.ReadLine();
        }

        public string first(int num)
        {
            string name;

            if (num == 0)
            {
                name = " ";
            }
            else
            {
                string[] arr1 = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" , "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
                name = arr1[num - 1];
            }

            return name;
        }

        public string second(int num)
        {
            string name;

            if ((num == 0)||(num==1))
            {
                 name = " ";
            }
            else
            {
                string[] arr1 = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
                name = arr1[num - 2];
            }

            return name;
        }

        public string third(int num)
        {
            string name ;

            if (num == 0)
            {
                name = "";
            }
            else
            {
                string[] arr1 = new string[] { "Hundred" };
                name = arr1[0];
            }

            return name;
        }
    }
}

从 1 到 19999 工作正常，我完成后很快就会更新

Answer 5

接受的答案似乎并不完美。 它不处理像二十一这样的数字中的破折号，它不会在像“一百零一”这样的数字中放入单词“and”，而且，它是递归的。

这是我的答案。 它智能地添加“and”一词，并适当地用连字符连接数字。 如果需要任何修改，请告诉我。

下面是如何调用它（显然你会想把它放在一个类中的某个地方）：

for (int i = int.MinValue+1; i < int.MaxValue; i++)
{
    Console.WriteLine(ToWords(i));
}

这是代码：

private static readonly string[] Ones = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};

private static readonly string[] Teens =
{
    "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
    "Seventeen", "Eighteen", "Nineteen"
};

private static readonly string[] Tens =
{
    "", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty",
    "Ninety"
};

public static string ToWords(int number)
{
    if (number == 0)
        return "Zero";

    var wordsList = new List<string>();

    if (number < 0)
    {
        wordsList.Add("Negative");
        number = Math.Abs(number);
    }

    if (number >= 1000000000 && number <= int.MaxValue) //billions
    {
        int billionsValue = number / 1000000000;
        GetValuesUnder1000(billionsValue, wordsList);
        wordsList.Add("Billion");
        number -= billionsValue * 1000000000;

        if (number > 0 && number < 10)
            wordsList.Add("and");
    }

    if (number >= 1000000 && number < 1000000000) //millions
    {
        int millionsValue = number / 1000000;
        GetValuesUnder1000(millionsValue, wordsList);
        wordsList.Add("Million");
        number -= millionsValue * 1000000;

        if (number > 0 && number < 10)
            wordsList.Add("and");
    }

    if (number >= 1000 && number < 1000000) //thousands
    {
        int thousandsValue = number/1000;
        GetValuesUnder1000(thousandsValue, wordsList);
        wordsList.Add("Thousand");
        number -= thousandsValue * 1000;

        if (number > 0 && number < 10)
            wordsList.Add("and");
    }

    GetValuesUnder1000(number, wordsList);

    return string.Join(" ", wordsList);
}

private static void GetValuesUnder1000(int number, List<string> wordsList)
{
    while (number != 0)
    {
        if (number < 10)
        {
            wordsList.Add(Ones[number]);
            number -= number;
        }
        else if (number < 20)
        {
            wordsList.Add(Teens[number - 10]);
            number -= number;
        }
        else if (number < 100)
        {
            int tensValue = ((int) (number/10))*10;
            int onesValue = number - tensValue;

            if (onesValue == 0)
            {
                wordsList.Add(Tens[tensValue/10]);
            }
            else
            {
                wordsList.Add(Tens[tensValue/10] + "-" + Ones[onesValue]);
            }

            number -= tensValue;
            number -= onesValue;
        }
        else if (number < 1000)
        {
            int hundredsValue = ((int) (number/100))*100;
            wordsList.Add(Ones[hundredsValue/100]);
            wordsList.Add("Hundred");
            number -= hundredsValue;

            if (number > 0)
                wordsList.Add("and");
        }
    }
}

Answer 6

这是一个 C# 控制台应用程序这将返回整数和小数。

Answer 7

仅用于类的土耳其语表示 HumanFriendlyInteger (↑) (Türkçe, sayı yazı karşılığı)：

public static class HumanFriendlyInteger
{
    static string[] ones = new string[] { "", "Bir", "İki", "Üç", "Dört", "Beş", "Altı", "Yedi", "Sekiz", "Dokuz" };
    static string[] teens = new string[] { "On", "On Bir", "On İki", "On Üç", "On Dört", "On Beş", "On Altı", "On Yedi", "On Sekiz", "On Dokuz" };
    static string[] tens = new string[] { "Yirmi", "Otuz", "Kırk", "Elli", "Altmış", "Yetmiş", "Seksen", "Doksan" };
    static string[] thousandsGroups = { "", " Bin", " Milyon", " Milyar" };

    private static string FriendlyInteger(int n, string leftDigits, int thousands)
    {
        if (n == 0)
        {
            return leftDigits;
        }

        string friendlyInt = leftDigits;

        if (friendlyInt.Length > 0)
        {
            friendlyInt += " ";
        }

        if (n < 10)
            friendlyInt += ones[n];
        else if (n < 20)
            friendlyInt += teens[n - 10];
        else if (n < 100)
            friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
        else if (n < 1000)
            friendlyInt += FriendlyInteger(n % 100, ((n / 100 == 1 ? "" : ones[n / 100] + " ") + "Yüz"), 0); // Yüz 1 ile başlangıçta "Bir" kelimesini Türkçe'de almaz.
        else
            friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands + 1), 0);

        return friendlyInt + thousandsGroups[thousands];
    }

    public static string IntegerToWritten(int n)
    {
        if (n == 0)
            return "Sıfır";
        else if (n < 0)
            return "Eksi " + IntegerToWritten(-n);

        return FriendlyInteger(n, "", 0);
    }

Answer 8

Nick Masao 对同一问题的孟加拉数字答案的扩展。 数字的初始输入是 Unicode 字符串。 干杯！！

string number = "২২৮৯";
number = number.Replace("০", "0").Replace("১", "1").Replace("২", "2").Replace("৩", "3").Replace("৪", "4").Replace("৫", "5").Replace("৬", "6").Replace("৭", "7").Replace("৮", "8").Replace("৯", "9");
double vtempdbl = Convert.ToDouble(number);
string amount = AmountInWords(vtempdbl);

private static string AmountInWords(double amount)
    {
        var n = (int)amount;

        if (n == 0)
            return " ";
        else if (n > 0 && n <= 99)
        {
            var arr = new string[] {  "এক", "দুই",  "তিন",  "চার",  "পাঁচ", "ছয়",  "সাত",  "আট",   "নয়",  "দশ",   "এগার", "বারো", "তের",  "চৌদ্দ",    "পনের", "ষোল", "সতের", "আঠার", "ঊনিশ", "বিশ",  "একুশ", "বাইস", "তেইশ", "চব্বিশ",   "পঁচিশ",    "ছাব্বিশ",  "সাতাশ",    "আঠাশ", "ঊনত্রিশ",  "ত্রিশ",    "একত্রিস",  "বত্রিশ",   "তেত্রিশ",  "চৌত্রিশ",  "পঁয়ত্রিশ", "ছত্রিশ",   "সাঁইত্রিশ",    "আটত্রিশ",  "ঊনচল্লিশ", "চল্লিশ",   "একচল্লিশ", "বিয়াল্লিশ",    "তেতাল্লিশ",    "চুয়াল্লিশ",    "পয়তাল্লিশ",    "ছিচল্লিশ", "সাতচল্লিশ",    "আতচল্লিশ", "উনপঞ্চাশ", "পঞ্চাশ",   "একান্ন",   "বায়ান্ন",  "তিপ্পান্ন",    "চুয়ান্ন",  "পঞ্চান্ন", "ছাপ্পান্ন",    "সাতান্ন",  "আটান্ন",   "উনষাট",    "ষাট",  "একষট্টি",  "বাষট্টি",  "তেষট্টি",  "চৌষট্টি",  "পয়ষট্টি",  "ছিষট্টি",  " সাতষট্টি",    "আটষট্টি",  "ঊনসত্তর ", "সত্তর",    "একাত্তর ", "বাহাত্তর", "তেহাত্তর", "চুয়াত্তর", "পঁচাত্তর", "ছিয়াত্তর", "সাতাত্তর", "আটাত্তর",  "ঊনাশি",    "আশি",  "একাশি",    "বিরাশি",   "তিরাশি",   "চুরাশি",   "পঁচাশি",   "ছিয়াশি",   "সাতাশি",   "আটাশি",    "উননব্বই",  "নব্বই",    "একানব্বই", "বিরানব্বই",    "তিরানব্বই",    "চুরানব্বই",    "পঁচানব্বই ",   "ছিয়ানব্বই ",   "সাতানব্বই",    "আটানব্বই", "নিরানব্বই" };
            return arr[n - 1] + " ";
        }
        else if (n >= 100 && n <= 199)
        {
            return AmountInWords(n / 100) + "এক শত " + AmountInWords(n % 100);
        }

        else if (n >= 100 && n <= 999)
        {
            return AmountInWords(n / 100) + "শত " + AmountInWords(n % 100);
        }
        else if (n >= 1000 && n <= 1999)
        {
            return "এক হাজার " + AmountInWords(n % 1000);
        }
        else if (n >= 1000 && n <= 99999)
        {
            return AmountInWords(n / 1000) + "হাজার " + AmountInWords(n % 1000);
        }
        else if (n >= 100000 && n <= 199999)
        {
            return "এক লাখ " + AmountInWords(n % 100000);
        }
        else if (n >= 100000 && n <= 9999999)
        {
            return AmountInWords(n / 100000) + "লাখ " + AmountInWords(n % 100000);
        }
        else if (n >= 10000000 && n <= 19999999)
        {
            return "এক কোটি " + AmountInWords(n % 10000000);
        }
        else
        {
            return AmountInWords(n / 10000000) + "কোটি " + AmountInWords(n % 10000000);
        }
    }

Answer 9

我使用这个名为 Humanizer 的方便库。

https://github.com/Humanizr/Humanizer

它支持多种文化，不仅可以将数字转换为单词，还可以将数字转换为单词。还可以日期，而且使用起来非常简单。

我的使用方法如下：

int someNumber = 543;
var culture = System.Globalization.CultureInfo("en-US");
var result = someNumber.ToWords(culture); // 543 -> five hundred forty-three

瞧！

Answer 10

这应该工作得相当好：（

public static class HumanFriendlyInteger
{
    static string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
    static string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
    static string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
    static string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };

    private static string FriendlyInteger(int n, string leftDigits, int thousands)
    {
        if (n == 0)
        {
            return leftDigits;
        }

        string friendlyInt = leftDigits;

        if (friendlyInt.Length > 0)
        {
            friendlyInt += " ";
        }

        if (n < 10)
        {
            friendlyInt += ones[n];
        }
        else if (n < 20)
        {
            friendlyInt += teens[n - 10];
        }
        else if (n < 100)
        {
            friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
        }
        else if (n < 1000)
        {
            friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
        }
        else
        {
            friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);
            if (n % 1000 == 0)
            {
                return friendlyInt;
            }
        }

        return friendlyInt + thousandsGroups[thousands];
    }

    public static string IntegerToWritten(int n)
    {
        if (n == 0)
        {
            return "Zero";
        }
        else if (n < 0)
        {
            return "Negative " + IntegerToWritten(-n);
        }

        return FriendlyInteger(n, "", 0);
    }
}

编辑以修复百万、十亿等的错误）

Answer 11

只需获取该字符串并使用
就像

string s = txtNumber.Text.Tostring();
int i = Convert.ToInt32(s.Tostring());

它只会写入完整的整数值