java 反射 getMethod传httpServletRequest报错

Question

描述：此报错只出现在IDEA当中，eclipse并不会。

环境：JDK1.7    Tomcat7.0.42

报错信息：

 

 

报错位置：ServletDemo02>>doGet>>>try{}>>

Method method=clazz.getMethod(md, HttpServletRequest.class,HttpServletResponse.class);

代码块：

public class ServletDemo02 extends HttpServlet {
    private static final long serialVersionUID = 1L;
    public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        doGet(request, response);
    }

    public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        //获取客户端提交到服务端的method对应的值
        String md=request.getParameter("method");
        //定义变量,存放功能执行完毕之后要转发的路径
        String path=null;
        //获取到当前字节码对象(ServletDemo02.class在内存中对象)
        Class clazz = this.getClass();
        try {
            //获取clazz上名称为md方法
            Method method=clazz.getMethod(md, HttpServletRequest.class,HttpServletResponse.class);
            if(null!=method){
                //调用找到的方法
                path=(String)method.invoke(this, request,response);
            }
            if(null!=path){
                //服务端的转发
                request.getRequestDispatcher(path).forward(request, response);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }



    }

    public String addStu(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        System.out.println("添加学生");
        return "/test.html";

    }



}

Answer 1

这么写没问题，可能idea抽风，重新编译然后重新打开项目