fastjson和spring mvc结合的问题

Question

@wenshao 你好，想跟你请教个问题：

我看你写的那个FastJsonHttpMessageConverter，我的spring mvc配置文件怎样写才能让输出的时间是yyyy-MM-dd HH

Answer 1

还真是这两个包的问题。

Answer 2

配置好了，访问后出现：
The resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers.  是不是还有什么参数没有加上

Answer 3

哈，我自己改源码了。先凑合着用，等温少更新之后，就用他的。

http://code.alibabatech.com/jira/browse/FASTJSON-190

Answer 4

public class MappingFastjsonHttpMessageConverter extends AbstractHttpMessageConverter<Object> {

	public static final Charset DEFAULT_CHARSET = Charset.forName("UTF-8");
	
    private SerializerFeature[] serializerFeature;  
  
    public SerializerFeature[] getSerializerFeature() {  
        return serializerFeature;  
    }  
  
    public void setSerializerFeature(SerializerFeature[] serializerFeature) {  
        this.serializerFeature = serializerFeature;  
    }  
  
    public MappingFastjsonHttpMessageConverter() {  
        super(new MediaType("application", "json", DEFAULT_CHARSET));  
    }  
  
    @Override  
    public boolean canRead(Class<?> clazz, MediaType mediaType) {  
        return true;  
    }  
  
    @Override  
    public boolean canWrite(Class<?> clazz, MediaType mediaType) {  
        return true;  
    }  
  
    @Override  
    protected boolean supports(Class<?> clazz) {  
        throw new UnsupportedOperationException();
    }
    
    @Override
	protected Object readInternal(Class<?> clazz, HttpInputMessage inputMessage) throws IOException, HttpMessageNotReadableException {
		return JSON.parseObject(StreamUtil.readBytes(inputMessage.getBody()), clazz);
	}
    
    @Override  
    protected void writeInternal(Object o, HttpOutputMessage outputMessage) throws IOException, HttpMessageNotWritableException {  
		String jsonString = JSON.toJSONString(o, serializerFeature);  
		OutputStream out = outputMessage.getBody();  
		out.write(jsonString.getBytes(DEFAULT_CHARSET));  
		out.flush();
    }  
}

Answer 5

<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<bean class="xxx.web.json.MappingFastjsonHttpMessageConverter">
   <property name="supportedMediaTypes" value="application/json" />
   <property name="serializerFeature">  
       <list>  
           <value>WriteMapNullValue</value>  
           <value>QuoteFieldNames</value>
       </list>
   </property>  
</bean>
</list>
</property>
</bean>

Answer 6

你都配置了转换器了，当然直接return obj就行了

@RequestMapping(params = "queryUserInfo")
    @ResponseBody
    public List<UserInfoDO> queryUserInfo(){
        System.out.println("================begin==================");
        List<UserInfoDO> userList=userInfoService.queryUserInfo();
        return userList;
    }

Answer 7

Controller 中如何输出呢。

@RequestMapping(params = "queryUserInfo")
    @ResponseBody
    public void queryUserInfo(){
        System.out.println("================begin==================");
        List<UserInfoDO> userList=userInfoService.queryUserInfo();

        JSON.toJSONString(userList);

如何输出呢？
    }

Answer 8

我等待温少的1.1.28。哈

Answer 9

温少，这个问题解决了么？

Answer 10

这个功能在当前的1.1.27版本中还没做好，你来提交一个patch？