你看我这个部分，从Ztree中取得的name值，传不到action中

Question

<SCRIPT type="text/javascript">
            var setting = {    
                treeNodeKey : "id",               //在isSimpleData格式下，当前节点id属性  
                treeNodeParentKey : "pId",        //在isSimpleData格式下，当前节点的父节点id属性  

                check:{
                    enable:true
                },
                data:    {
                    simpleData:{
                        enable:true
                    }
                },
                callback:{
                    onCheck:onCheck
                }
            };         
            var zNodes =[
                { id:1, pId:0, name:"student", open:false },
                { id:11, pId:1, name:"name"},
                { id:12, pId:1, name:"student_no"},
                { id:13, pId:1, name:"gender"},
                { id:14, pId:1, name:"age"},
                { id:15, pId:1, name:"hobby"},
                { id:2, pId:0, name:"score", open:false},
                { id:21, pId:2, name:"name"},
                { id:22, pId:2, name:"class"},
                { id:23, pId:2, name:"score"},
                { id:24, pId:2, name:"student_no"},
                { id:25, pId:2, name:"subject"}
            ];
            
            $(document).ready(function(){
                $.fn.zTree.init($("#treeDemo"), setting, zNodes);
            });
            
            function onCheck(e,treeId,treeNode){
                
                
                var treeObj=$.fn.zTree.getZTreeObj("treeDemo");
                //获取选择的节点
                nodes=treeObj.getCheckedNodes(true),
                tableName="", columns="";
                for(var i=0;i<nodes.length;i++){
                    if (nodes[i].pId == null && nodes[i].children == null){
                        tableName=nodes[i].name;
                    }else {
                        if (nodes[i].pId == null) {
                                columns += nodes[i].name + ";";
                            } else {
                                columns += nodes[i].name + ",";
                            }
                    }
                }
                alert("表名" + tableName);
                alert("列名" + columns);
                
                
                $.ajax({
                    async:false ,
                    cache:false,
                    data:"tableName=" + tableName + "&columns=" + columns,
                    type:"post",
                    dataType:"json",
                    url:"authorityRole_insert.htm",
                    success:function(data){ //请求成功后处理函数。    
                        alert("选择成功");  
                    }   
                }); 
            }   
            
        </SCRIPT>

@zTree 你好，想跟你请教个问题：

Answer 1

用 chrome 调试代码，检查 network 中 ajax 提交的数据是否正确