PHP的数组问题

Question

$sql = array('siteid'=>'1','url'=>"");

以上获取siteid为1,url为空的数组,

现在遇到一问题,该如何获取url不为空的.

数组中没有 !=> 这样的,请教各方大侠.

Answer 1

$sql = array(
   array('siteid' => '1', 'url' => ""),
   array('siteid' => '2', 'url' => "http://www.baidu.com"),
   array('siteid' => '4', 'url' => "http://www.yahoo.com"),
);

$sqlFilter = array_filter($sql, 'removeBlank');

function removeBlank($var){
  return $var['url'] !== "";
}

print_r($sqlFilter);

Answer 2

说实话，我没看懂...

Answer 3

tp的写法

$User = M( “User” );

$map['id'] = array( ‘neq’ ,1);

$map[ 'name'] = ‘ok’;

$map['_string'] = ‘status=1 AND score>10′ ;

$User->where($map)->select();

ci的写法

$this->db->where('name !=', $name);
$this->db->where('id <', $id);

Answer 4

!empty($sql['url'])

Answer 5

循环一遍呗.

Answer 6

这问题老尴尬的,却找不到别的方法解决

Answer 7

你应该说的是二维数组吧

$sql = array(array('siteid'=>'1','url'=>""),array('siteid'=>'2','url'=>"aaaa"),

array('siteid'=>'3','url'=>""),array('siteid'=>'4','url'=>"asdaasczxxc"));

$arr =array();

foreach($sql as $val){

if($val['url'] !=''){

$arr[]=$val;

}

}

print_r($arr);